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Published on: 27/11/2019
Transition and Inner Transition Elements
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1.
Which one of the following exhibits highest oxidation state?
Ni
Mn
V
Zr
2.
The highest possible oxidation state shown by osmium in its compound is_______.
+4
+6
+8
+10
3.
MnO4- react with Br- in alkaline PH to give ________.
BrO3- MnO2
Br2, MnO42-
Br2, MnO2
BrO-, MnO42-
4.
The correct order of increasing oxidizing power in the series _______.
VO2+ < Cr2O72- < MnO4-
Cr2O72- < VO2+ < MnO4-
Cr2O72- < MnO4- < VO2+
MnO4- < Cr2O72- < VO2+
5.
Which of the following compounds is colourless?
Fe3+
Ti4+
Co2+
Ni2+
6.
Silver atom has completely filled d-orbitals (4d10) in its ground state. How can you say that it is a transition element?
7.
Calculate the magnetic moment of Fe3+ ion (Atomic no. of Fe = 26)
8.
Why do transition metals have high enthalpy of hydration?
9.
What is lanthanoid contraction and what are the effects of lanthanoid contraction?
10.
11.
Give reason for the following:
(i) Compounds of transition elements are generally coloured,
(ii) MnO is basic while Mn2O7 is acidic.
(iii) Calculate the magnetic moment of a divalent ion in aqueous medium if its atomic number is 26.
12.
What are the general properties of f-block elements? (Lanthanides and Actinides)
(i) Electronic configuration
(ii) Oxidation state
(iii) Radii of tripositive ions.
13.
Which metal in the 3d series exhibits +1 oxidation state most frequently and why?
14.
Describe the variable oxidation state of 3d series elements.
15.
Compare the ionization enthalpies of first series of the transition elements.
16.
Explain why Cr2+ is strongly reducing while Mn3+ is strongly oxidizing.
17.
Which is more stable? Fe3+ or Fe2+? Why ?
18.
How are materials classified based on their magnetic properties?
19.
Write a note on the ionization enthalpy of transition elements.
1.
(b)
Mn
2.
(c)
+8
3.
(a)
BrO3- MnO2
4.
+5 +6 +7
VO2+ < Cr2O72- < MnO4-
Greater the oxidation state, higher is the oxidising power.
5.
(b)
Ti4+
6.
(i) Silver in its +1 oxidation state, exhibits 4d105s0configuration.
(ii) But in some compounds, it also shows +2 oxidation state, so the configuration becomes 4d95s0
(iii) Here, d-orbital is not completely filled. Therefore silver is a transition element.
7.
Fe3+ has the electronic configuration
[Ar] 4s0 3d5
It is 5 unpaired electron
μ = \(\sqrt{n(n+2)}\)
= \(\sqrt{5(5+2)}\) = \(\sqrt{35}\) = 5.9 BM
8.
Transition metal ions are smaller in case of size and have higher ionic charge, therefore they have high enthalpy of hydration.
9.
Lanthanoid contraction:
As we move across 4f series, the atomic and ionic radii of lanthanoids show gradual decrease with increase in atomic number. This decrease in ionic size is called lanthanoid contraction.
Effects (consequence) of lanthanoid contraction:
1. Basicity difference:
As we move from Ce3+ to Lu3+, the basic character of Ln3+ ions decrease. Due to the decrease in the size of Ln3+ ions, the ionic character of Ln -OH bond decreases (covalent character increases) which results in the decrease in the basicity.
2. Similarities among lanthanoid:
In the complete f - series only 10 pm decrease in atomic radii and 20 pm decrease in ionic radii is observed because of this very small change in radii of lanthanoids, their chemical properties are quite similar.
3. The elements of the second and third transition series resemble each other more closely than the elements of the first and second transition series.
10.
11.
(i) The colour of the transition elements is due to the d-d transition.
(ii) Since the oxidation state and polarising power of Mn in Mn2O7 is higher, it is acidic in nature
(iii) μ = \(\sqrt{n(n+2)}=\sqrt{4(4+2)}\)
= 4.90 BM
12.
| Properties | Lanthanides | Actinides |
|---|---|---|
| Electronic configuration | [54Xe]4f1-14 5d16s2 | [Rn] 5f0,1-14 6d0,1-27s2 |
| Oxidation state | Common: +3 Uncommon: +2, +4 |
Common: +4 Uncommon: +2, +3, +5, +6 |
| Radii | M3+gradually decrease in size on moving from La to Lu Lanthanide contraction | M3+ and M4+ ions decrease in size on moving from Ac to Lr. Actinide contraction. |
13.
Copper exhibits +1 oxidation state most frequently Cu (29) - electronic configuration 3d104s1 copper ready to lose outer most one electron to attain the stable full filled electronic configuration. Hence it exhibits +1 oxidisation state.
14.
(i) The first transition metal Scandium exhibits only +3 oxidation state, but all other transition elements exhibit variable oxidation states by loosing electrons from (n-1)d orbital and ns orbital as the energy difference between them is very small. At the beginning of the series, +3 oxidation state is stable but towards the end +2 oxidation state becomes stable. The first and last elements show less number of oxidation states and the middle elements with more number of oxidation states
(ii) For example, the first element Sc has only one oxidation state +3; the middle element Mn has six different oxidation states from +2 to +7. The last element Cu shows +1 and +2 oxidation states only.
15.
As we move from left to right in a transition metal series, the ionization enthalpy increases as expected. This is due to increase in the nuclear charge corresponding to the filling of d electrons. The increase in first ionisation enthalpy with increase in atomic number along a particular series is not regular. The added electron enters (n-1) d orbital and the inner electrons act as a shield and decrease the effect of nuclear charge on valence ns electrons. Therefore, it leads to variation in the ionization energy value.
16.
Mn3+ has large and negative standard electrode potential E0 (-1.18 V) than that of Cr2+ which has only -0.91 V. If the standard electrode potential of a metal is large and negative, the metal is a powerful reducing agent because it loses electrons easily. Hence Mn3+ is strongly oxidizing while Cr2+ is strongly reducing.
17.
(i) Fe3+ - electronic configuration - [Ar] 3d5
(ii) It has exactly half-filled stable electronic configuration.
(iii) Fe2+ - electronic configuration -[Ar]3d6
(iv) It has only partially filled d-orbitals.
Hence Fe3+ is more stable than Fe2+.
18.
On the basis of magnetic properties, materials can be broadly classified as
(a) paramagnetic materials
(b) diamagnetic materials, besides these there are ferromagnetic and antiferromagnetic materials
(i) Materials with no elementary magnetic dipoles are diamagnetic, in other words a species with all paired electrons exhibits diamagnetism.
(ii) This kind of materials are repelled by the magnetic field because the presence of external magnetic field, a magnetic induction is introduced to the material which generates weak magnetic field that oppose the applied field
(iii) Paramagnetic solids having unpaired electrons possess magnetic dipoles which are isolated from one another.
(iv) In the absence of external magnetic field, the dipoles are arranged at random and hence the solid shows no net magnetism.
(v) But in the presence of magnetic field, the dipoles are aligned parallel to the direction of the applied field and therefore, they are attracted by an external magnetic field.
(vi) Ferromagnetic materials have domain structure and in each domain the magnetic dipoles are arranged.
(vii) But the spin dipoles of the adjacent domains are randomly oriented.
(viii) Some transition elements or ions with unpaired d electrons show ferromagnetism.
19.
(i) Ionization energy of transition element is intermediate between those of sand p block elements.
(ii) As we move from left to right in a transition metal series, the ionization enthalpy increases as expected.
(iii) This is due to increase in nuclear charge corresponding to the filling of d electrons.
(iv) The increase in first ionisation enthalpy with increase in atomic number along a particular series is not regular.
(v) The added electron enters (n-1)d orbital and the inner electrons act as a shield and decrease the effect of nuclear charge on valence ns electrons. Therefore, it leads to variation in the ionization energy values
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