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Published on: 12/08/2019
Coordination Chemistry
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1.
Write the IUPAC name of the complex.
2.
What is the coordination entity formed when excess of liquid ammonia is added to an aqueous solution of copper sulphate?
3.
Why tetrahedral complexes do not exhibit geometrical isomerism.
4.
Give an example for complex of the type [Ma2b2c2] where a, b, c are monodentate ligands and give the possible isomers.
5.
[Ti(H2O)6]3+ is coloured, while [Sc(H2O)6]3+ is colourless- explain.
6.
Write the IUPAC names for the following complexes.
7.
Draw the structure of the following homoleptic metal carbonyl.
(i) [Ni(CO)4]
(ii) [Fe(CO)5]
(iii) [Cr(CO)6]
8.
Write briefly about the applications of coordination compounds in volumetric analysis
9.
Draw all possible geometrical isomers of the complex [Co(en)2Cl2]+ and identify the optically active isomer.
10.
Based on VB theory explain why [Cr(NH3)6]3+ is paramagnetic, while [Ni(CN)4]2- is diamagnetic.
11.
Give the structure for the following compounds.
(i) pentaamminechlorocobalt (III) ion
(ii) Triamminetrinitrito- k N cobalt (III)
(ill) tetraammineaquabromidooobalt(III)nitrate
(iv) Dichloridobisethane-(1,2-diamine) cobalt (lIl) chloride
(v) Tetraamminecopper (lI) sulphate
12.
Give the postulates and limitation of Werner's theory of co-ordination compounds.
13.
Write the postulates of Werner’s theory.
14.
In Co-ordination compound. [Cr(en)3][CrF6] _______.
ligand is en (ethylenediamine)
Oxidation state of central atom is +3
Central metal is Cr (in anomie complexes)
Cation complex is [Co(NH3)4Cl2]+
15.
The name of complex ion, [Fe(CN)6]3- is _______.
Trieyanoferrate (III) ion
Hexacyano iron (III) ion
Hexacyanitoferrate (III) ion
Hexacyanido ferrate (III) ion
16.
IUPAC name of H2[Ptcl6] is _______.
Hexa chloridoplatinum (IV) acid
Hexa chloridoplatinum (IV) acid
Hexachloridoplatinic (IV) acid
Dihydrogenhexaehloro platinate (IV)
17.
Which of the following octahedral complexes do not show geometrical isomerism?
[Co(NH3)3Cl3]
[PtCl2(NH3)4]
[Pt(NH3)2Cl2]
[Co(en)3]3+
18.
Primary and secondary valencies of Cu in [Cu(NH3)4]SO4 is _______.
4,4
2,4
4,1
4,2
19.
Choose the correct statement.
Square planar complexes are more stable than octahedral complexes
The spin only magnetic moment of [Cu(Cl)4]2- is BM and it has square planar structure.
Crystal field splitting energy \(\left( { \Delta }_{ 0 } \right) \) [FeF6]4- is higher than the \((\Delta _{ 0 })\) of [Fe(CN)6]4-
crystal field stabilization energy of [V(H2O)6]2+ is higher than the crystal field stabilization of [Ti(H2O)6]2+
20.
Fac-mer isomerism is shown by _______.
[CO(en)3]3+
[Co(NH3)4(Cl)2]+
[Co(NH3)3(Cl)3]
[Co(NH3)5Cl]SO4
21.
How many geometrical isomers are possible for [Pt(Py)(NH3)(Br)(Cl)]
3
4
0
15
22.
A magnetic moment of 1.73BM will be shown by one among the following.
TiCl4
[CoCl6]4-
[Cu(NH3)4]2+
[Ni(CN)4]2-
23.
The sum of primary valence and secondary valence of the metal M in the complex [M(en)2(Ox)]Cl is________.
3
6
-3
9
1.
Sodium tetrafluoridodihydroxychromate (III) Na[CrF4(H2O)2]
2.
(i) When excess of liquid ammonia is added to an aqueous solution of copper sulphate gives tetra ammine copper (II) sulphate is formed.
CUso4 + 4NH3 \(\rightarrow\) [Cu(NH3)4]SO4
(ii) The co-ordination entity is [Cu(NH3)4]2+
3.
Tetrahedral complexes do not exhibit geometrical isomerism. Because the relative position of donor atoms of ligand the unidentate Iigands (donor atom) attached to the central atom are same with respect to each other.
4.
[Ma2b2C2]\(\pm\)n where a, b, c are monodentate ligands.
[Pt(py2)(NH3)2Cl2]2+. It exhibits both optical and geometrical isomerism. c is isomer exhibit optical isomerism also. While trans isomer exhibits geometrical isomerism only.
5.
\({ }_{22} \mathrm{Ti}-{ }_{18}[\mathrm{Ar}] 4 \mathrm{s}^{2} 3 \mathrm{d}^{2} / {}_{21}\mathrm{Sc}-{ }_{18}[\mathrm{Ar}] 4 \mathrm{~s}^{2} 3 \mathrm{~d} \)
\({ }_{22} \mathrm{Ti}^{3+}-{ }_{18}[\mathrm{Ar}] 3 \mathrm{~d}^{1} /{ }_{18} \mathrm{Sc}^{3+}{ }_{18}[\mathrm{Ar}] 3 \mathrm{~d}^{0}\)
(i) In this complex the central metal ion is Ti3+, which has d1 configuration. This single electron occupies one of the t2g orbitals in the octahedral aqua ligand field. When white light falls on this complex the electron absorbs light and promotes itself to eg level. The spectral data show the absorption maximum is at 20000 cm-1 corresponding to the crystal field splitting energy \(\left(\Delta_{o}\right)\) 239.7 kJmol-1. The transmitted colour associated with this absorption is purple and hence the complex appears purple in colour.
(ii) Thus in \(\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+} \mathrm{d}-\mathrm{d}\) transition takes place.
(iii) But in \(\left[\mathrm{Sc}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+} \mathrm{Sc}^{3+}\) has the outer electronic configuration of 3d0 where d-d transition is not possible and it is colourless.
6.
i) Na2[Ni(EDTA)] - Sodium 2, 2', 2",2'" - (ethane-1,2 diyldinitrilo tetraacetatonickelate)(II)
ii) [Ag(CN)2]- - Dicyanido-kC-argentate (I) ion
iii) [CO(en)3]2(SO4)3 - Tris (ethane 1, 2 diamine)cobalt (III) sulphate
iv) [CO(ONO)(NH3)5]2+ - Pentaamminenitrito - KO cobalt (III) ion
v) [Pt(NH3)2Cl(NO2)] - Diammainechloridonitro - kN - platinum (II)
7.
8.
(i) EDTA is used in the volumetric determination of a wide variety of metal ions in solution.
Eg. Zn2+, Pb2+, Ca2+, CO2+, Ni2+,Cu2+, etc.
(ii) By careful adjustment of the pH and using suitable indication, mixtures of metals can v be analyzed.
Eg. Bi3+in the presence of Pb2+
(iii) Hardness of water due to the presence of Ca2+ and Mg2+ ions is estimated by complexometric titrations using EDTA.
9.
[Co (en)2 Cl2]+ This is an octahedral complex
10.
\(\text {(a) }\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{6}\right]^{3+}:{ }_{24} \mathrm{Cr} \Rightarrow{ }_{18}[\mathrm{Ar}] 4 \mathrm{~s}^{2} 3 \mathrm{~d}^{4} \)
\({ }_{21} \mathrm{Cr}^{3+} \Rightarrow{ }_{18}[\mathrm{Ar}] 3 \mathrm{~d}^{3}\)
(i) d2sp3 hybridisation (octahedral)
(ii) It has three unpaired electrons (n = 3)
(iii) So it is paramagnetic
(iv) Magnetic moment \(\left(\mu_{\mathrm{s}}\right)=\sqrt{\mathrm{n}(\mathrm{n}+2)} \mathrm{BM}\)
\(=\sqrt{3(3+2)}=\sqrt{15}=3.87 \mathrm{BM}\)
\((b) \ \left[\mathrm{Ni}(\mathrm{CN})_{4}\right]^{2-:}{ }_{28} \mathrm{Ni} \Rightarrow[\mathrm{Ar}] 4 \mathrm{~s}^{2} 3 \mathrm{~d}^{8} ;{ }_{26} \mathrm{Ni}^{2+} \Rightarrow{ }_{18}[\mathrm{Ar}] 3 \mathrm{~d}^{8}\)
(i) dsp2 hybridisation
(ii) Geometry - square planar
(iii) No unpaired electrons- It is Diamagnetic
(iv) Magnetic moment (μs) = 0.
11.
(i) [Co(NH3)5 CI]2+
(ii) [CO(NO2)3(NH3)3]
(iii) [Co(NH3)4H2OBr](NO3)2
(iv) [Co(en)2CI2]CI
(v) [Cu(NH3)4]SO4
12.
(i) Every metal atom has two types of valencies Primary valency or ionisable valency Secondary valency or non ionisable valency
(ii) The primary valency corresponds to the oxidation state of the metal ion. It is always satisfied by negative ions.
(iii) Secondary valency corresponds to the coordination number of the metal ion or atom. It is satisfied by either negative ions or neutral molecules.
(iv) The molecules or ions that satisfy secondary valencies are called ligands.
(v) The ligands which satisfy secondary valencies must project in definite directions in space. So the secondary valencies are directional in nature whereas the primary valencies are non - directional in nature.
(vi) The ligands have unshared pair of electrons. These unshared pair of electrons are donated to central metal ion or atom in a compound. Such compounds are called coordination compounds.
Werner's representation
Eg: [Co(NH)6]Cl3
Cl: primary valency (dotted lines)
NH3: secondary valency (solid lines).
Defects of Werner's theory
Werner's theory describes the structures of many co-ordination compounds successfully. However, it does not explain the magnetic and spectral properties.
13.
Most of the elements exhibit, two types of valence namely primary valence and secondary valence and each element tend to satisfy both the valences.
The primary valence is referred the oxidation state of the metal atom.
The secondary valence as the coordination number. For example, according to Werner, the primary and secondary valences of cobalt are 3 and 6 respectively.
The primary valence of a metal ions ae always satisfied by negative ions.
For example in the complex CoCI3.6NH3. The primary valence of Co is +3 and is satisfied by 3CI- ions.
The secondary valence is satisfied by negative ions, neutral molecules, positive ions or the combination of these.
For example, in CoCl3.6NH3 complex primary valence of cobalt +3 and it is satisfied by 3 CI-.
The secondary valence of cobalt is 6 and is satisfied by six neutral ammonia molecules. where as in CoCI6.NH3.
Secondary valence of Co = 5{It is satisfied five neutral molecules and a Cl- ion}
According to Werner, there are two spheres of attraction around a metal atom/ion in a complex.
The inner /coordination sphere:
The groups present in this sphere are firmly attached to the metal.
The outer sphere / ionisation sphere:
The groups present in this sphere are loosely bound to the central metal ion and hence can be separated into ions upon dissolving the complex in a suitable solvent.
The primary valencies are non-directional. while the secondary valencies are directional.
The geometry of the complex is determined by the special arrangement of the groups which satisfy the secondary valence.
| Secondary valence | Geometry |
| 4 | Tetrahedral / Square planar |
| 6 | Octahedral |
14.
(d)
Cation complex is [Co(NH3)4Cl2]+
15.
(d)
Hexacyanido ferrate (III) ion
16.
(d)
Dihydrogenhexaehloro platinate (IV)
17.
(d)
[Co(en)3]3+
18.
(b)
2,4
19.
(d)
crystal field stabilization energy of [V(H2O)6]2+ is higher than the crystal field stabilization of [Ti(H2O)6]2+
20.
(c)
[Co(NH3)3(Cl)3]
21.
Three isomers. If we consider any one of the ligands as reference (say Py), the arrangement of other three ligands (NH3, Br- and Cl-) with respect to (Py) gives three geometrical isomers.
22.
Ti4+ (d0 ⇒ 0BM)
Co2+ (d7 spain free ⇒ t2g5, e2g; n = 3; μ = 3.9BM)
Cu2+ (d9 Low spain ⇒ t2g6, e3g; n = 1; μ = 1.732BM)
Ni2+ (d8 Low spain ⇒ t2g6, e2g; n = 2; μ = 2.44 BM)
23.
In the complex [M(en)2(Ox)]Cl For the central metal ion M3+
The primary valence is = +3
The secondary valence = 6
sum of primary valence and secondary valence = 3 + 6 = 9
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