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Published on: 29/08/2022
QB365 provides a detailed and simple solution for every Possible Book Back Questions in Class 12 Biology Subject - Botany - Chromosomal Basis of Inheritance, English Medium. It will help Students to get more practice questions, Students can Practice these question papers in addition to score best marks.
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Questions + Answers key
Take MCQ Biology Test1.
| s.no | gamete types | Number of progenies |
| 1 | ABC | 349 |
| 2 | Abc | 114 |
| 3 | abC | 124 |
| 4 | AbC | 5 |
| 5 | aBc | 4 |
| 6 | aBC | 116 |
| 7 | ABc | 128 |
| 8 | abc | 360 |
i) What is the name of this test cross?
ii) How will you construct gene mapping from the above given data?
iii) Find out the correct order of genes.
2.
From the above figure identify the type of mutation and explain it.
3.
1.
(i) Three point test cross.
(ii)
If we analyse the loci of two alleles at a time, starting with AB, since AB and ab are parental genotypes, the recombination will be Ab/aB.
The recombinant frequency for these two alleles can be calculated as follows.
\(RF = \frac{Total\ no.\ of \ recombination}{Total\ no.\ of\ progenies}\times100\)
\(\mathrm{RF}=\frac{114+5+4+116}{1200} \times 100 \)
\(\mathrm{RF}=\frac{239}{1200}=19.91 \)
For A and C loci, the recombinants are Ac / aC - RF will be as follows.
\(\mathrm{RF}=\frac{114+134+116+128}{1200} \times 100 \)
\(\mathrm{RF}=\frac{482}{1200}=40.1 \)
For B and C loci, the recombinants are Bc / bC- RF will be as follows.
\(R F=\frac{124+5+4+128}{1200} \times 100 \)
\(R F=\frac{261}{1200}=21.75 \)
All the loci are linked, because all the RF value is less than 50%. In this A - and C loci show highest RF value, they must be farthest apart. Therefore B locis must lie in between them.
The order of genes should be abc. A genetic map can be drawn as follows.
(iii)

2.
(i) A type of structural chromosomal abbrevation.
Reverse tandem duplication
(ii) The duplicated segment is located immediately after the normal segment but the gene sequence order will be reversed.
3.
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