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12th Standard Biology English Medium Botany - Chromosomal Basis of Inheritance 2 Mark Book Back Question Paper and Answer Key 2022 - 2023

Published on: 29/08/2022

QB365 provides a detailed and simple solution for every Possible Book Back Questions in Class 12 Biology Subject - Botany - Chromosomal Basis of Inheritance, English Medium. It will help Students to get more practice questions, Students can Practice these question papers in addition to score best marks.

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Questions:

Generic 5

1 x 5 = 5

s.no	gamete types	Number of progenies
1	ABC	349
2	Abc	114
3	abC	124
4	AbC	5
5	aBc	4
6	aBC	116
7	ABc	128
8	abc	360

i) What is the name of this test cross?
ii) How will you construct gene mapping from the above given data?
iii) Find out the correct order of genes.

Generic 2

2 x 2 = 4

From the above figure identify the type of mutation and explain it.

What is the difference between missense and nonsense mutation?

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Answers Key:

Generic 5

1 x 5 = 5

(i) Three point test cross.
(ii)

If we analyse the loci of two alleles at a time, starting with AB, since AB and ab are parental genotypes, the recombination will be Ab/aB.
The recombinant frequency for these two alleles can be calculated as follows.
\(RF = \frac{Total\ no.\ of \ recombination}{Total\ no.\ of\ progenies}\times100\)
\(\mathrm{RF}=\frac{114+5+4+116}{1200} \times 100 \)
\(\mathrm{RF}=\frac{239}{1200}=19.91 \)
For A and C loci, the recombinants are Ac / aC - RF will be as follows.
\(\mathrm{RF}=\frac{114+134+116+128}{1200} \times 100 \)
\(\mathrm{RF}=\frac{482}{1200}=40.1 \)
For B and C loci, the recombinants are Bc / bC- RF will be as follows.
\(R F=\frac{124+5+4+128}{1200} \times 100 \)
\(R F=\frac{261}{1200}=21.75 \)
All the loci are linked, because all the RF value is less than 50%. In this A - and C loci show highest RF value, they must be farthest apart. Therefore B locis must lie in between them.
The order of genes should be abc. A genetic map can be drawn as follows.
(iii)

Generic 2

2 x 2 = 4

(i) A type of structural chromosomal abbrevation.
Reverse tandem duplication
(ii) The duplicated segment is located immediately after the normal segment but the gene sequence order will be reversed.

Missense Mutation Non-sense Mutation The mutation where the codon for one amino acid is changed into a codon for another amino acid. The mutations where codon for one amino acid is changed into a termination or stop codon.