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Published on: 13/10/2020
12th Standard Chemistry Electro Chemistry English Medium Free Online Test One Mark Questions 2020 - 2021
Download Tamil Nadu 12th Standard Chemistry question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
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1.
The gas that bubbles over the platinum electrode in SHE is ________.
hydrogen
helium
neon
oxygen
2.
The inert electrode is ________.
Cu
Pt
Zn
None of these
3.
λc = μc for, ______.
NaCI
H2SO4
Na2SO4
Al2(SO4)3
4.
The equivalent conductivity of CH3COOH at 25°C is 80 ohm-1 cm2 eq-1 and at infinite dilution 400 ohm-1 cm-1 eq-1. The degree of dissociation of CH3COOH is ______.
1
0.2
0.1
0.3
5.
The specific conductance of a 0.01 M solution of KCI is 0.0014 ohm-1 em-1 at 25°C. Its equivalent conductance is ______.
14 ohm-1 cm2eq-1
140 ohm-1 cm2eq-1
1.4 ohm-1 cm2eq-1
0.14 ohm-1 cm2eq-1
6.
When one coulomb of electricity is passed through an electrolytic solution the mass deposited on the electrode is equal to ______.
equivalent weight
molecular weight
electrochemical equivalent
one gram
7.
What happens during the electrolysis of molten sodium chloride?
Cl2 is released at the cathode
Liquid sodium is obtained at the anode
The emf of the overall reaction is -4.07 V
Cl2 is released at the cathode and Liquid sodium is obtained at the anode
8.
Recharging of lead storage battery involves ______.
anode is reduced to pb
cathode is reduced to pb
cathode is oxidised to pb
anode is oxidised to pbO2
9.
The limiting molar conductivities of HCI, CH3COONa and NaCI are respectively 425, 190 and 150 mho cm2 mol-1 at 25°C. The molar conductivity of 0.1 M acetic acid is 9.2 mho cm2 mol-1. The degree of dissociation of 0.1 M acetic acid is ______.
0.10
0.02
0.19
0.03
10.
A device in which spontaneous chemical reaction generates electric current ________.
Galvanic cell
Voltaic cell
Daniel cell
All the above
11.
Which among the following is the strongest reducing agent?
F2
Cl2
Zn
Li
12.
Which one of the following solution has highest equivalent conductance?
0.1 M NaCI
0.05 M NaCI
0.005 M NaCI
0.25 M NaCI
13.
A certain current liberated 0.504gm of hydrogen in 2 hours. How many grams of copper can be liberated by the same current flowing for the same time in a copper sulphate solution ______.
31.75
15.8
7.5
63.5
14.
The equivalent conductance of M/36 solution of a weak monobasic acid is 6 mho cm2 equivalent-1 and at infinite dilution is 400 mho cm2 equivalent-1. The dissociation constant of this acid is ______.
1.25 x 10−6
6.25 x 10-6
1.25 x 10−4
6.25 x 10 -5
15.
Among the following cells
I) Leclanche cell
II) Nickel – Cadmium cell
III) Lead storage battery
IV) Mercury cell
Primary cells are ____.
I and IV
I and III
III and IV
II and III
16.
During electrolysis of molten sodium chloride, the time required to produce 0.1mole of chlorine gas using a current of 3A is _____.
55 minutes
107.2 minutes
220 minutes
330 minutes
17.
How many faradays of electricity are required for the following reaction to occur MnO4-→ Mn2+
5F
3F
1F
7F
18.
| Electrolyte | KCl | KNO3 | HCl | NaOAC | NaCl |
| Λ- (Scm2 mol-1) |
149.9 | 145.0 | 426.2 | 91.0 | 126.5 |
Calculate ΛoHoAC using appropriate molar conductances of the electrolytes listed above at infinite dilution in water at 25oC_______.
517.2
552.7
390.7
217.5
19.
The button cell used is watches function as follows
Zn (s) + Ag2O (s) + H2O (l) ⇌ 2Ag (s) + Zn2+ (aq) + 2OH-(aq) the half cell potentials are Ag2O (s) + H2O (l) + 2e- → 2Ag (s) + 2OH- (aq) Eo = 34V and Zn (s) → Zn2+ (aq) + 2e− E0 = 0.76V . The cell potential will be_______.
0.84V
1.34V
1.10V
0.42V
20.
1.
(a)
hydrogen
2.
(b)
Pt
3.
(a)
NaCI
4.
(b)
0.2
5.
(a)
14 ohm-1 cm2eq-1
6.
(c)
electrochemical equivalent
7.
(c)
The emf of the overall reaction is -4.07 V
8.
(a)
anode is reduced to pb
9.
(c)
0.19
10.
(d)
All the above
11.
(d)
Li
12.
(c)
0.005 M NaCI
13.
\(\frac{m_{1}}{m_{2}} = \frac{E_{1}}{E_{2}} \)
\(\frac{0.504}{m_{2}} = \frac{1.008}{31.77} \)
m2 = 15.885 g
14.
α = Λ/Λo
= 6/400
Ka = α2C
\(= \frac{6}{400} \times \frac{6}{400} \times \frac{1}{36}\)
= 6.25 x 10-6
15.
(a)
I and IV
16.
mass of 1 mole of CI2 gas = 71
∴ mass of 0.1 mole of Cl2 gas = 7.1 g mol-1
m = Zlt
t = m/ZI
\(= \frac{7.1}{\frac{71}{2 \times 96500} \times 3}\) (2Cl- ➝ Cl2 + 2e-)
\(= \frac{2 \times 96500 \times 7.1}{71 \times 3}\)
= 6433.33s = 107.2 min
17.
7MnO4- + 5e- → Mn2+ + 4H2O
5 moles of electrons i.e., 5F charge is required.
18.
(ΛoHoAC) = [(Λo)HCl + Λo)NaOAC ] - (Λo)NaCl
= (426.2 + 91) - (126.5)
= 390.7
19.
Anodic Oxidation: (Reverse the given reaction)
(Eoox ) = 0.76 V Cathodic reduction
Eocell = (Eoox )+ (Eored)
= 0.76 + 0.34 = 1.1 V
20.
(c)
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