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Published on: 02/09/2022
QB365 provides a detailed and simple solution for every Possible Book Back Questions in Class 12 Chemistry Subject - Carbonyl Compounds, English Medium. It will help Students to get more practice questions, Students can Practice these question papers in addition to score best marks.
Download Tamil Nadu 12th Standard Chemistry question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
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1.
How will you prepare
x. Acetaldehyde from ethyne
2.
How will you prepare
Cinnamic acid from benzaldehyde
3.
How will you prepare Malachitegreen from benzaldehyde
4.
How will you prepare
vii. Benzoic acid from toluene
5.
How will you prepare
vi. Ethane from sodium acetate
6.
How will you prepare
v. Acetophenone from acetylchloride
7.
How will you prepare
Lactic acid from ethanal
8.
How will you prepare
iii. Acetamide from methylcyanide
9.
How will you prepare
Ethylacetate from methylacetate
10.
What is the action of HCN on
(iii) ethanal
11.
What is the action of HCN on
(ii) 2,4-dichlorobenzaldehyde.
12.
How will you convert benzaldehyde into the following compounds?
(iii) α - hydroxyphenylaceticacid.
13.
How will you convert benzaldehyde into the following compounds?
(ii) benzoic acid
14.
How is propanoic acid is prepared starting from
(c) an alkene
15.
How is propanoic acid is prepared starting from
(b) an alkylhalide
16.
A carbonyl compound A having molecular formula C5H10O forms crystalline precipitate with sodium bisulphate and gives positive iodoform test. A does not reduce Fehling solution. Identify A.
17.
What is the action of HCN on
(i) propanone
(ii) 2,4-dichlorobenzaldehyde
iii) ethanal
18.
How will you convert benzaldehyde into the following compounds?
(i) benzophenone
(ii) benzoic acid
(iii) α-hydroxyphenylaceticacid.
19.
Identify X and Y.
\({ CH }_{ 3 }CO{ CH }_{ 2 }{ CH }_{ 2 }COO{ C }_{ 2 }{ H }_{ 5 }\overset { { CH }_{ 3 }MgBr }{ \longrightarrow } X\overset { { H }_{ 3 }{ O }^{ + } }{ \longrightarrow } Y\)
20.
How is propanoic acid is prepared starting from
(a) an alcohol
(b) an alkylhalide
(c) an alkene
21.
How will you prepare
i. Acetic anhydride from acetic acid
ii. Ethylacetate from methylacetate
iii. Acetamide from methylcyanide
iv. Lactic acid from ethanal
v. Acetophenone from acetylchloride
vi. Ethane from sodium acetate
vii. Benzoic acid from toluene
viii. Malachitegreen from benzaldehyde
ix. Cinnamic acid from benzaldehyde
x. Acetaldehyde from ethyne
1.
Acedaldehyde from ethyne:
2.
Cinnamic acid from benzaldehyde:
3.
Malachite green from benzaldehyde:
Benzaldehyde condenses with tertiary aromatic amines like N, N - dimethyl aniline in the presence of strong acids to form triphenyl methane dye.
4.
Benzoic acid from toluene:
Toluene is oxidised by acidified KMnO4
\(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{3} \frac{\mathrm{H}^{+} / \mathrm{KMnO}_{4}}{(\mathrm{O})} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH}\)
5.
Ethane from sodium acetate:
\(\underset{Sodium \ acetate}{2 \mathrm{CH}_{3}} \mathrm{COONa}+2 \mathrm{H}_{2} \mathrm{O} \stackrel{\text { Electrolysis }}{\longrightarrow} \underset{Ethane}{\mathrm{CH}_{3}}-\mathrm{CH}_{3}+2 \mathrm{CO}_{2}+\mathrm{H}_{2}+2 \mathrm{NaOH} \)
This is Kolbe's electrolysis.
6.
Acetophenone frorr acetylchloride:
Friedel Crafts acetylation of, benzene with CH3COCI/AICI3
7.
Lactic acid from ethanal
8.
Acetamide from methyl cyanide:
Partial hydrolysis of alkyl cyanides with cold con HCl gives amides.
9.
Ethylacetate from methyl acetate:
1. In presence of a little acid, methyl acetate is cleaved by ethyl alcohol to form ethyl acetate.
\(\underset{Methyl \ acetate }{\mathrm{CH}_{3} \mathrm{COOCH}_{3}}+ \underset{Propyl \ alcohol} {\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}} \stackrel{\mathrm{H}^{+}}{\rightleftharpoons} \underset { Ethyl \ acetate}{\mathrm{CH}_{3} \mathrm{COOC}_{2} \mathrm{H}_{5}}+\mathrm{CH}_{3} \mathrm{OH} \)
2. This is called 'trans esterification'.
10.
ethanal
11.
2,4-dichlorobenzaldehyde :
12.
13.
14.
An alkene:
15.
An alkylhalide:
16.
An carbonyl compound having molecular formula C5H10O giving positive iodoform test. It does not reduce Fehling solution.So it is 2- pentanone.
∴ (A) is 2-pentanone.
17.
(ii) 2,4-dichlorobenzaldehyde.
(iii) ethanal
18.
(ii) benzoic acid
(iii) α - hydroxyphenylaceticacid.
19.
20.
An alcohol:
An alkylhalide:
An alkene:
21.
(i) Acetic anhydride from acetic acid:
Carboxylic acid on heating in the presence of a strong dehydrating agent such as P2O5 forms acid anhydride.
(ii) Ethylacetate from methyl acetate:
1. In presence of a little acid, methyl acetate is cleaved by ethyl alcohol to form ethyl acetate.
\(\underset{Methyl \ acetate }{\mathrm{CH}_{3} \mathrm{COOCH}_{3}}+ \underset{Propyl \ alcohol} {\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}} \stackrel{\mathrm{H}^{+}}{\rightleftharpoons} \underset { Ethyl \ acetate}{\mathrm{CH}_{3} \mathrm{COOC}_{2} \mathrm{H}_{5}}+\mathrm{CH}_{3} \mathrm{OH} \)
2. This is called 'trans esterification'.
Acetamide from methyl cyanide:
Partial hydrolysis of alkyl cyanides with cold con HCl gives amides.
(iv) Lactic acid from ethanal
Acetophenone frorr acetylchloride:
Friedel Crafts acetylation of, benzene with CH3COCI/AICI3
Ethane from sodium acetate:
\(\underset{Sodium \ acetate}{2 \mathrm{CH}_{3}} \mathrm{COONa}+2 \mathrm{H}_{2} \mathrm{O} \stackrel{\text { Electrolysis }}{\longrightarrow} \underset{Ethane}{\mathrm{CH}_{3}}-\mathrm{CH}_{3}+2 \mathrm{CO}_{2}+\mathrm{H}_{2}+2 \mathrm{NaOH} \)
This is Kolbe's electrolysis.
Benzoic acid from toluene:
Toluene is oxidised by acidified KMnO4
\(\mathrm{C}_{6} \mathrm{H}_{5} \mathrm{CH}_{3} \frac{\mathrm{H}^{+} / \mathrm{KMnO}_{4}}{(\mathrm{O})} \mathrm{C}_{6} \mathrm{H}_{5} \mathrm{COOH}\)
Malachite green from benzaldehyde:
Benzaldehyde condenses with tertiary aromatic amines like N, N - dimethyl aniline in the presence of strong acids to form triphenyl methane dye.
Cinnamic acid from benzaldehyde:
Acedaldehyde from ethyne:
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