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Published on: 01/09/2022
QB365 provides a detailed and simple solution for every Possible Book Back Questions in Class 12 Chemistry Subject - Transition and Inner Transition Elements, English Medium. It will help Students to get more practice questions, Students can Practice these question papers in addition to score best marks.
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1.
Which metal in the 3d series exhibits +1 oxidation state most frequently and why?
2.
Describe the variable oxidation state of 3d series elements.
3.
The E0M2+/M value for copper is positive. Suggest a possible reason for this.
4.
Which is stronger reducing agent Cr2+ or Fe2+?
5.
6.
Why europium (II) is more stable than Cerium (II)?
7.
Out of Lu(OH)3 and La(OH)3 which is more basic and why?
8.
Actinoid contraction is greater from element to element than the lanthanoid contraction, why?
9.
Compare the ionization enthalpies of first series of the transition elements.
10.
Explain why Cr2+ is strongly reducing while Mn3+ is strongly oxidizing.
11.
Compare lanthanoids and actinoids.
12.
Explain the variation in E0M3+/M2+ 3d series.
13.
Which is more stable? Fe3+ or Fe2+? Why ?
14.
Justify the position of lanthanoids and actinoids in the periodic table.
15.
What are inner transition elements?
16.
What are transition metals? Give four examples.
1.
Copper exhibits +1 oxidation state most frequently Cu (29) - electronic configuration 3d104s1 copper ready to lose outer most one electron to attain the stable full filled electronic configuration. Hence it exhibits +1 oxidisation state.
2.
(i) The first transition metal Scandium exhibits only +3 oxidation state, but all other transition elements exhibit variable oxidation states by loosing electrons from (n-1)d orbital and ns orbital as the energy difference between them is very small. At the beginning of the series, +3 oxidation state is stable but towards the end +2 oxidation state becomes stable. The first and last elements show less number of oxidation states and the middle elements with more number of oxidation states
(ii) For example, the first element Sc has only one oxidation state +3; the middle element Mn has six different oxidation states from +2 to +7. The last element Cu shows +1 and +2 oxidation states only.
3.
Elemental copper is more stable than Cu2+. The electronic configuration of copper is 3d10 4s1 completely filled 3d orbital with stable configuration.
But Cu2+ has configuration as 3d9. Hence \(\mathrm{E}_{\mathrm{M}^{2+} / \mathrm{M}}^{0}\) value is positive for Cu2+.
4.
Cr2+ is stronger reducing agent than Fe2+. The standard electrode potential (E0) of Cr2+ is -0.91 V and that of Fe2+ is only -0.44 V.
If the standard electrode potential of a metal is large and negative is a powerful reducing agent, because it loses electrons easily.
Hence Cr2+ is stronger reducing agent.
5.
6.
\(Eu (63)-[\mathrm{Xe}] 4 \mathrm{f}^{7} 5 \mathrm{~d}^{0} 6 \mathrm{~s}^{2}, \mathrm{Eu}^{2+}-[\mathrm{Xe}] 4 \mathrm{f}^{7} \)
\(\mathrm{Ce}(58)-[\mathrm{Xe}] 4 \mathrm{f}^{1} 5 \mathrm{~d}^{1} 6 \mathrm{~s}^{2}, \mathrm{Ce}^{2+}-[\mathrm{Xe}] 4 \mathrm{f}^{1} 5 \mathrm{~d}^{1} \)
Eu2+ has exactly half filled stable electronic configuration. Hence Europium (II) is more stable than Cerium (II).
7.
La(OH)3 is more basic than Lu(OH)3. Due to lanthanide contraction, the size of Ln3+ ions decreases regularly with increase in atomic number. According to Fajan's rule, decrease in size of Ln3+ ions decreases the basic character between Ln3+ and OH- ion in Ln(OH)3. So La(OH)3 is more basic than Lu(OH)3.
8.
(i) In the actinoid series, the elements have poor shielding effect when compared with lanthanide series.
(ii) Hence in the actinoid series, when atomic number increases the effective nuclear charge also increases so actinoid contraction is greater from element to element than the lanthanoid contraction.
9.
As we move from left to right in a transition metal series, the ionization enthalpy increases as expected. This is due to increase in the nuclear charge corresponding to the filling of d electrons. The increase in first ionisation enthalpy with increase in atomic number along a particular series is not regular. The added electron enters (n-1) d orbital and the inner electrons act as a shield and decrease the effect of nuclear charge on valence ns electrons. Therefore, it leads to variation in the ionization energy value.
10.
Mn3+ has large and negative standard electrode potential E0 (-1.18 V) than that of Cr2+ which has only -0.91 V. If the standard electrode potential of a metal is large and negative, the metal is a powerful reducing agent because it loses electrons easily. Hence Mn3+ is strongly oxidizing while Cr2+ is strongly reducing.
11.
| S.No | Lanthanoids | Actinoids |
|---|---|---|
| 1. | Differentiating electron enters in 4f orbital | Differentiating electron enters in 5f orbital |
| 2. | Binding energy of 4f orbitals are higher | Binding energy of 5f orbitals are lower |
| 3. | They show less tendency to form complexes | They show greater tendency to form complexes |
| 4. | Most of the lanthanoids are colourless | Most of the actinoids are coloured For Example: U3+ (red) U4+ (green). |
| 5. | They do not form oxo cations | They do form oxo cations such as UO22+, NpO22++ etc. |
| 6. | Besides +3 oxidation states lanthanoids show +2 and +4 oxidation states in few cases | Besides +3 oxidation states actinoids show higher oxidation states such as +4, +5, +6 and +7 |
12.
(i) In transition series, as we move down from Ti to Zn, the standard reduction potential E0M2+/M3 value is approaching towards less negative value and copper has a positive reduction potential, i. e. elemental copper is more stable than Cu2+.
(ii) E0M2+/M value for manganese and zinc are more negative than regular trend. It is due to extra stability arises due to the half filled d5 configuration in Mn2+ and completely filled d10 configuration in Zn2+.
(iii) The standard electrode potential for the M3+/M2+ half cell gives the relative stability between M3+ and M2+.
(iv) The high reduction potential of Mn3+/Mn2+ indicates Mn2+ is more stable than Mn3+.
(v) Mn3+ has a 3d4 configuration while that of Mn2+ is 3d5. The extra stability associated with a half filled d sub-shell makes the reduction of Mn3+ very feasible \(\left[\mathrm{E}^{\circ}=+1.51 \mathrm{~V}\right]\).
13.
(i) Fe3+ - electronic configuration - [Ar] 3d5
(ii) It has exactly half-filled stable electronic configuration.
(iii) Fe2+ - electronic configuration -[Ar]3d6
(iv) It has only partially filled d-orbitals.
Hence Fe3+ is more stable than Fe2+.
14.
(i) The actual position of Lanthanides in the periodic table is at group number 3 and period number 6. However, in the sixth period after lanthanum, the electrons are preferentially filled in inner 4f sub shell and these fourteen elements following lanthanum show similar chemical properties.
(ii) Similarly the fourteen elements following actinium resemble in their physical and chemical properties. Hence they are placed separately bottom of the modern periodic table.
15.
(i) The elements in which the extra electron enters (n-2) f orbitals are called f-block elements. These elements are called as inner transition elements because they form a transition. Series within the transition elements.
(ii) The f-block elements are also called as rare earth elements. They are divided into lanthanoid series (4f block elements) and actinoid series (5f block elements).
16.
IUPAC defines transition metal as an element whose atom has an incomplete d-sub shell or which can give rise to cations with an incomplete d-sub shell. They occupy the central position of the periodic table, between s and p-block elements.
Examples: Fe, Cu, Ag, Au
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