The incorrect statement is option (n)
Physisorption is an exothermic process. Hence increases in temperature decreases the Physisorption

Mn²⁺ + 2e^- ➝ Mn E^o = -1.18V
Mn²⁺ ➝ Mn³⁺ + e^- E^o = -1.51V
3Mn²⁺➝ Mn³⁺ + 2Mn³⁺ E^o_cell = ?
E^o_cell = (E^o_ox )+ (E^o_red) 
= 1.51 - 1.18 and non spontaneous
= -2.69V
Since E°is ve ΔG is +ve and the given forward cell reaction is non- spontaneous

75 mL\(\frac{M}{5}\)HCl + 25mL\(\frac{M}{5}\)NaOH
No. of moles of HCI = 0.2 x 75 x 10^-3 = 15 x 10^-3
No. of moles of NaOH = 0.2 x 25 x 10^-3
= 5 x 10^-3
No. of moles of HCl after mixing
= 15 x 10^-3 - 5 x 10^-3
= 10 x 10^-3
\(\therefore\) Concentration of HCI = No. of moles of HCI/Vol in litre
= 10 x 10^-3/100 x 10^-3 = 0.1 M
For (iii) solution. pH of 0.1 M HCI = -log₁₀ (0.1) = 1

for n ≠ 1 t_1/2 = \(\frac{2^{n-1} -1}{(n- 1) k[A_{0}]^{-1}}\)
for n = 0; t_1/2 = \(\frac{1}{2 k[A_{0}]^{-1}}\)
t_1/2 = \(\frac{[A_{0}]}{2 k}\)
t_1/2 α [A₀] ...(1)
Given [A₀] = 0.002 M; t_1/2 = 10 min
[A₀] = 0.04M; t_1/2 = ?
Substitute in (1)
10 min α 0.02 M...(2)
t_1/2 α 0.04M ....(3)
(3)(2)
⇒ t_1/2 / 10 min
= 0.04 M/0.02 M
t_1/2 = 2 x 10 min = 20 min

Number of A ions = N_c/8 = 8/8 = 1
Number of B ions = N_f/2 = 6/2 = 3
Simplest formula = AB₃

The complex is [M(H₂O)₅Cl]Cl₂
1000 ml of 1 M solution of the complex gives 2 moles of Cl^- ions 1000 ml of 0.01 M solution of the complex will give 
\(\frac{100 ml \times 0.01M \times 2Cl^-}{1000 ml \times 1M}\)
= 0.002 moles of Cl^- ions

Cr ⇒ [Ar]3d⁵4s¹