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Published on: 02/09/2022
QB365 provides a detailed and simple solution for every Possible Book Back Questions in Class 12 Chemistry Subject - Hydroxy Compounds and Ethers, English Medium. It will help Students to get more practice questions, Students can Practice these question papers in addition to score best marks.
Download Tamil Nadu 12th Standard Chemistry question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
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1.
Isoprophylbenzene on air oxidation in the presence of dilute acid gives ______.
C6H5COOH
C6H5COCH3
C6H5COC6H5
C6H5- OH
2.
On reacting with neutral ferric chloride, phenol gives ______.
red colour
violet colour
dark green colour
no colouration.
3.
Williamson synthesis of preparing dimethyl ether is a / an ______.
SN1 reactions
SN2 reaction
electrophilic addition
electrophilic substitution
4.
Among the following ethers which one will produce methyl alcohol on treatment with hot HI?
(H3C)3C-O-CH3
(CH3-)2-CH-CH2-O-CH3
CH3-(CH2)3-O-CH3
CH3-CH2-\(\underset { \overset { | }{ { CH }_{ 3 } } }{ CH } \)-O-CH3
5.
One mole of an organic compound (A) with the formula C3H8O reacts completely with two moles of HI to form X and Y. When Y is boiled with aqueous alkali it forms Z. Z answers the iodoform test. The compound (A) is ______.
propan – 2-ol
propan -1-ol
ethoxy ethane
methoxy ehane
6.
The reactions
is an example of ______.
Wurtz reaction
cyclic reaction
Williamson reaction
Kolbe reactions
7.
Which of the following compound can be used as antifreeze in automobile rediators?
methanol
ethanol
Neopentyl alcohol
ethan -1, 2-diol
8.
HO CH2 CH2 – OH on heating with periodic acid gives ______.
methanoic acid
Glyoxal
methanol
CO2
9.
The reaction
Can be classified as ______.
dehydration
Williams on alcoholsynthesis
Williamson ether synthesis
dehydrogenation of alcohol
10.
In the reaction Ethanol \(\overset { { PCl }_{ 5 } }{ \longrightarrow } X\overset { alc.KOH }{ \longrightarrow } Y\overset { { H }_{ 2 }{ SO }_{ 4 }/{ H }_{ 2 }O }{ \underset { 298k }{ \longrightarrow } } Z.\) The ‘Z’ is ______.
ethane
ethoxyethane
ethylbisulphite
ethanol
11.
The correct IUPAC name of the compound
4 – chloro – 2,3 – dimethyl pentan – 1-ol
2,3 – dimethyl – 4- chloropentan -1-ol
2,3,4 – trimethyl – 4- chlorobutan -1-ol
4– chloro – 2,3,4 – trimethyl pentan – 1-ol
12.
(CH3)3-C-CH(OH) CH3 \(\overset { con{ H }_{ 2 }{ SO }_{ 4 } }{ \longrightarrow } \)X (major product)
(CH3)3 CCH = CH2
(CH3)2C = C (CH3)2
CH2= C(CH3)CH2-CH2- CH3
CH2= C (CH3) - CH2- CH2- CH3
13.
Which one of the following will react with phenol to give salicyladehyde after hydrolysis.
Dichlo methane
trichloroethane
trichloro methane
CO2
14.
Carbolic acid is _____.
Phenol
Picri cacid
benzoic acid
phenylacetic acid
15.
on treatment with Con H2SO4, predominately gives______.
16.
17.
In the reaction sequence, Ethane \(\overset { HOCl }{ \longrightarrow } A\overset { x }{ \longrightarrow } \) ethan -1, 2 - diol. A and X respectively are ________.
Chloroethane and NaOH
ethanol and H2SO4
2 – chloroethan -1-ol and NaHCO3
ethanol and H2O
18.
The X is _______.
None of these
19.
Which of the following compounds on reaction with methyl magnesium bromide will give tertiary alcohol.
benzaldehyde
propanoic acid
methyl propanoate
acetaldehyde
20.
An alcohol (x) gives blue colour in victormayer’s test and 3.7g of X when treated with metallic sodium liberates 560 mL of hydrogen at 273 K and 1 atm pressure what will be the possible structure of X?
CH3 CH (OH) CH2CH3
CH3 – CH (OH) – CH3
CH3 – C (OH) – (CH3)2
CH3- CH2 –CH (OH) – CH2 – CH3
1.
phenol
2.
(b)
violet colour
3.
(b)
SN2 reaction
4.
5.
6.
(c)
Williamson reaction
7.
(d)
ethan -1, 2-diol
8.
(c)
methanol
9.
Cyclic alcolhol → sodium cyclic alkoxide- Williamson ether synthesis.
10.
11.
(a)
4 – chloro – 2,3 – dimethyl pentan – 1-ol
12.
(CH3)2C = C (CH3)2
13.
trichloro methane
14.
(a)
Phenol
15.
According to Saytzeff rule.
16.
(c)
17.
18.
Hydroboration - Anti Markownikoff product
CH3 – CH2 –CH2 – CH2 – CH2 – OH
19.
20.
CH3 CH (OH) CH2CH3
2R-OH+ 2Na ⟶ 2RONa + H2 ↑
2 moles of alcohol gives 1 mole of H2 which occupies 22.4 L at 273 K and 1 atm number of moles of alcohol
= 2 moles of R -OH/22.4L of H2 x 560 ml
= 0.05 moles
No of moles = mass/molar mass = m/M
= 3.7/0.05 = 74 g mol-1
General formula for (R-OH) Cn H2n + 1OH
n(12) + (2n + 1) (1) + 16 + 1 = 74
14n = 74 - 18
14n = 56
n = 56/14 = 4
The "2" alcohol which contains 4 carbon is CH3 - CH (OH) CH2 - CH3
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