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Published on: 01/09/2022
QB365 provides a detailed and simple solution for every Possible Creative Questions in Class 12 Chemistry Subject - p - Block Elements - II, English Medium. It will help Students to get more practice questions, Students can Practice these question papers in addition to score best marks.
Download Tamil Nadu 12th Standard Chemistry question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Chemistry Test

1.
Acidic character increases from HF to HI. State whether the above statement is True or false and give reason for your answer.
2.
How is SO2 an air pollutant?
3.
Why does ozone act as a powerful oxidising agent?
4.
There is a huge difference between the melting and boiling points of oxygen and sulphur. Why?
5.
How would you account for the following? The electron gain enthalpy with negative sign is less for oxygen than that of sulphur.
6.
(i) Give correct order of boiling point of hydride of group 17.
(ii) Fluorine exhibits only -1 oxidation state whereas other halogens show +1, +3, +5 and +7 oxidation state also Explain.
7.
Although \(\triangle\)H of fluorine is less negative than that of chlorine, but fluorine is a stronger oxidising agent than chlorine, why?
8.
Elements of group 16 show lower value of first ionization enthalpy compared to group 15, why?
9.
Discuss the oxidising power of fluorine.
10.
What is the reaction of Phosphorous with alkali?
11.
What is phosphorescence?
12.
Give two uses of nitric acid.
13.
How is ammonia prepared in the lab?
14.
Give two uses of nitrogen.
15.
How is nitrogen prepared from liquid air?
1.
(i) The given statement is true.
(ii) The relative acidic strength of HF, HCI, HBr and HI depends upon their bond dissociation enthalpies.
(iii) Since, the bond dissociation enthalpy of H-X bond from H-F to H-I as the size of atom increases from F to l. Therefore, the acidic strength increases in the opposite order as:
H - F < H - CI < H - Br < H - I
2.
(i) SO2 present in the atmosphere dissolves in rain water and causes acid rain.
(ii) Acid rain destroys buildings, inhibits plant growth and also causes eye irritation in human.
3.
(i) Ozone acts as a powerful oxidizing agent because ozone liberates nascent oxygen very easily on decomposition.
\({ O }_{ 3 }\longrightarrow { O }_{ 2 }+\left[ O \right] \)
(ii) This nascent or atomic oxygen brings about the oxidations it is very reactive.
4.
(i) Sulphur has great catenation property and forms large molecule having high weight, which results higher melting point.
(ii) While oxygen exists as diatomic molecule of less molecular weight, hence has very low melting point.
5.
(i) The electron gain enthalpy for oxygen is less negative because of its small size due to which the electron repulsions in the relatively small 2p-subshell are comparatively large.
(ii) Hence the Incoming electrons are not accepted with the same ease as in case of sulphur as it has relatively large size.
6.
(i) HCl < HBr < HI < HF
(ii) Fluorine being the most electronegative element cannot have positive oxidation state. Other halogens have d-orbitals, therefore can expand their octet.
7.
This is due to,
(i) Lowbond dissociation enthalpy of F-F-bond
(ii) High hydration enthalpy of F-.
8.
Element of group 15 have stable half-filled p-orbitals hence large amount of energy is required to remove electrons as compared to group 16, which has an incomplete p subshell.
9.
(i) All the halogens have strong oxidising property due to their high electron affinity.
(ii) Fluorine is the strongest oxidising agent. It oxidises other halide ions into halogens in solution or when dry.
\({ F }_{ 2 }+{ 2X }^{ - }\longrightarrow { 2F }^{ - }+{ X }_{ 2 }\) (where X- = Cl-, Br-, I-)
10.
Yellow phosphorus reacts with alkali on boiling in an inert atmosphere liberating phosphine. Phosphorus acts as a reducing agent.
\({ P }_{ 4 }+NaOH+{ H }_{ 2 }O\longrightarrow \underset { Sodiumhypophosphite }{ { 3NaH }_{ 2 }{ PO }_{ 2 } } +\underset { Phosphine }{ { PH }_{ 3 } } \uparrow \)
11.
White Phosphorous glows in the dark due to oxidation which is called as phosphorescence.
12.
(i) Nitric acid is used as a oxidising agent and in the preparation of aqua regia.
(ii) Salts of nitric acid are used in photography (AgNO3) and gun powder for fire arms (NaNO3)·
13.
Ammonia is prepared in the laboratory by heating an ammonium salt with a base.
\({ 2NH }_{ 4 }^{ + }+{ OH }^{ - }\longrightarrow { 2NH }_{ 3 }+{ H }_{ 2 }O\)
\({ 2NH }_{ 4 }Cl+CaO\longrightarrow { CaCl }_{ 2 }+{ 2NH }_{ 3 }+{ H }_{ 2 }O\)
14.
(i) Nitrogen is used for the manufacture of ammonia, nitric acid and calcium Cyanamide etc.
(ii) Liquid nitrogen is used for producing low temperature required in cryosurgery and so in biological preservation.
15.
(i) Nitrogen is separated industrially from liquid air by fractional distillation.
(ii) Pure nitrogen gas can be obtained by the thermal decomposition of sodium azide about 575K.
\(2Na{ N }_{ 3 }\longrightarrow 2Na+{ 3N }_{ 2 }\)
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