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Published on: 21/06/2021
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Questions + Answers key
Take MCQ Chemistry Test1.
Give the IUPAC names for the following:
(i) Crotonaldehyde
(ii) Methyl n-propyl ketone
(iii) Phenyl acetaldehyde.
2.
Write the structure of 'A' and 'B' in the following reaction
\({ C }_{ 6 }{ H }_{ 5 }MgBr+{ CO }_{ 2 }\overset { (i)CO_{ 2 } }{ \underset { (ii){ H }_{ 2 }O/{ H }^{ + } }{ \longrightarrow } } A\overset { { Br }_{ 2 } }{ \underset { FeBr_{ 3 } }{ \longrightarrow } } B\)
3.
Formic acid reduces Tollen's reagent but acetic acid does not - Give reasons.
4.
What is Malachite green dye? Explain its preparation?
5.
How will you convert benzaldehyde to
(I) C6H5COOH
(ii) C6HsCH2OH
(iii) C6HSCH3
1.
| S.No. | Formula | Common name | IUPAC name |
| i. | CH3-CH=CH-CHO | Crotonaldehyde | 2-butenal |
| ii. | \(CH_{ 3 }-\underset { \overset { || }{ O } }{ C } -{ CH }_{ 2 }-{ CH }_{ 2 }-{ CH }_{ 3 }\) | Methyl n-propyl ketone | 2-pentanone |
| iii. | C6HsCH2CHO | Phenyl acetaldehyde | Phenyl ethanal |
2.
\(\underset { Phenyl\ magnesium\\ bromide }{ { C }_{ 6 }{ H }_{ 5 }MgBr } +{ CO_{ 2 }\longrightarrow \quad }{ C }_{ 6 }{ H }_{ 5 }\overset { \underset { || }{ O } }{ C } OMgBr\underset { { H }_{ 2 }O/{ H }^{ + } }{ \longrightarrow } \underset { \quad \quad \quad \quad (A)\\ Benzoic\ acid }{ { C }_{ 6 }{ H }_{ 5 }COOH } \)
(A) C6H5COOH-Benzoic acid
(B)
3.
(i) Formic acid (HCOOH) is unique because it contains both an aldehyde group and carboxyl group also.
(ii) Hence it can act as a reducing agent. It reduces Fehling's solution Tollen's reagent and decolourises pink coloured KMnO4 solution.
(iii) Whereas in acetic acid, there is no aldehyde group and it cannot act as reducing agent.
(iv) Formic acid reduces ammoniacal silver nitrate solution (Tollen's reagent) to metallic silver
HCOOH + Ag2O⟶ H2O + CO2 + 2Ag↓ (metallic silver)
(v) Formic acid reduces Fehling's solution. It reduces blue coloured cupric ions to red coloured cuprous ions.
\(HCOO^{ - }+\underset { (blue) }{ 2{ Cu }^{ 2+ } } +5{ OH }^{ - }\longrightarrow { CO }_{ 3 }^{ 2- }+\underset { (red) }{ { Cu }_{ 2 }O } +3{ H }_{ 2 }O\)
4.
Benzaldehyde condenses with tertiary aromatic amines like N, N - dimethyl aniline in the presence of strong acids to from triphenyl methane dye or malachite green dye.
5.
(i) It is oxidised to benzoic acid by alkaline permanganate.
\({ C }_{ 6 }{ H }_{ 5 }CHO\overset { [O] }{ \longrightarrow } { C }_{ 6 }{ H }_{ 5 }COOH\)
(ii) It is reduced to benzyl alcohol by NaBH4 or LiAlH4
\({ C }_{ 6 }{ H }_{ 5 }CHO\overset { \left[ { H }^{ - } \right] }{ \longrightarrow } { C }_{ 6 }{ H }_{ 5 }{ CH }_{ 2 }OH\)
(iii) It can be reduced to toluene by Clemmenson or Wolff Kishner procedure.
\({ C }_{ 6 }{ H }_{ 5 }CHO\overset { Zn/Hg/HCl }{ \underset { \overset { or }{ { N }_{ 2 }{ H }_{ 4 }/KoH } }{ \longrightarrow } } { C }_{ 6 }{ H }_{ 5 }{ CH }_{ 3 }\)
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