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Published on: 13/05/2022
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Take MCQ Chemistry Test1.
[Ti(H2O)6]3+ is coloured, while [Sc(H2O)6]3+ is colourless- explain.
2.
Arrange the following in order of increasing molar conductivity
(i) Mg[Cr(NH3)(Cl)5]
(ii) Cr(NH3)5Cl]3[CoF6]2
(iii) [Cr(NH3)3Cl3]
3.
Write the formula for the co-ordination compounds.
4.
Write the IUPAC names for the following complexes.
5.
Draw all possible geometrical isomers of the complex [Co(en)2Cl2]+ and identify the optically active isomer.
1.
\({ }_{22} \mathrm{Ti}-{ }_{18}[\mathrm{Ar}] 4 \mathrm{s}^{2} 3 \mathrm{d}^{2} / {}_{21}\mathrm{Sc}-{ }_{18}[\mathrm{Ar}] 4 \mathrm{~s}^{2} 3 \mathrm{~d} \)
\({ }_{22} \mathrm{Ti}^{3+}-{ }_{18}[\mathrm{Ar}] 3 \mathrm{~d}^{1} /{ }_{18} \mathrm{Sc}^{3+}{ }_{18}[\mathrm{Ar}] 3 \mathrm{~d}^{0}\)
(i) In this complex the central metal ion is Ti3+, which has d1 configuration. This single electron occupies one of the t2g orbitals in the octahedral aqua ligand field. When white light falls on this complex the electron absorbs light and promotes itself to eg level. The spectral data show the absorption maximum is at 20000 cm-1 corresponding to the crystal field splitting energy \(\left(\Delta_{o}\right)\) 239.7 kJmol-1. The transmitted colour associated with this absorption is purple and hence the complex appears purple in colour.
(ii) Thus in \(\left[\mathrm{Ti}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+} \mathrm{d}-\mathrm{d}\) transition takes place.
(iii) But in \(\left[\mathrm{Sc}\left(\mathrm{H}_{2} \mathrm{O}\right)_{6}\right]^{3+} \mathrm{Sc}^{3+}\) has the outer electronic configuration of 3d0 where d-d transition is not possible and it is colourless.
2.
(i) \(\mathrm{Mg}\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right) \mathrm{Cl}_{5}\right]^{2-} \rightleftharpoons \mathrm{Mg}^{2+}+\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right) \mathrm{Cl}_{5}\right]^{2-} (2 ions)\)
(ii) \(\begin{aligned}
{\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}_3\left[\mathrm{CoF}_6\right]_2 \rightleftharpoons 3\right.} & {\left[\mathrm{Cr}\left(\mathrm{NH}_3\right)_5 \mathrm{Cl}\right]^{2+} } \\
& (5 \text { ions })
\end{aligned}\)\(+2\left[\mathrm{CoF}_6\right]^{3-}\)
(iii) \(\left[\mathrm{Cr}\left(\mathrm{NH}_{3}\right)_{3} \mathrm{Cl}_{3}\right]= \text{ No ions}\)
If no of ions increases, molar conductivity increases molar conductivity of the complex also INCREASES.
\(\therefore\) The order of the given compound is
[Cr(NH3)3Cl3]<Mg[Cr(NH3)3Cl3] < [Cr(NH3)5Cl3] [CoF6]2
(No ion) (2 ions) (5 ions)
3.
a) potassiumhexacyanidoferrate(II) - Potassiumhexacyanidoferrate(II) - K4[Fe(CN)6]
b) Pentacarbonyliron(0) - [Fe(CO)5]
c) Pentaamminenitrito −kNcobalt(III)ion - [Co(NH3)5(NO2)]2+
d) Hexaamminecobalt(III) Sulphate - [CO(NH3)6](SO4)3
e) Sodiumtetrafluoridodihydroxidochromate(III) - Na2[CrF4(OH)2]
4.
i) Na2[Ni(EDTA)] - Sodium 2, 2', 2",2'" - (ethane-1,2 diyldinitrilo tetraacetatonickelate)(II)
ii) [Ag(CN)2]- - Dicyanido-kC-argentate (I) ion
iii) [CO(en)3]2(SO4)3 - Tris (ethane 1, 2 diamine)cobalt (III) sulphate
iv) [CO(ONO)(NH3)5]2+ - Pentaamminenitrito - KO cobalt (III) ion
v) [Pt(NH3)2Cl(NO2)] - Diammainechloridonitro - kN - platinum (II)
5.
[Co (en)2 Cl2]+ This is an octahedral complex
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