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Published on: 02/06/2021
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Questions + Answers key
Take MCQ Chemistry Test1.
In an octahedral crystal field, draw the figure to show splitting of d orbitals
2.
Give an example for complex of the type [Ma2b2c2] where a, b, c are monodentate ligands and give the possible isomers.
3.
[Ni(CN)4]2- is diamagnetic, while [NiCl4]2- is paramagnetic, explain using crystal field theory.
4.
Write briefly about the applications of coordination compounds in volumetric analysis
5.
Give the difference between double salts and coordination compounds.
1.
The energy of the two eg orbitals will increase by \(\frac{3}{5} \Delta_{O}\) and that of the three t2g will decrease by (2/5) \(\Delta_{O}\)
2.
[Ma2b2C2]\(\pm\)n where a, b, c are monodentate ligands.
[Pt(py2)(NH3)2Cl2]2+. It exhibits both optical and geometrical isomerism. c is isomer exhibit optical isomerism also. While trans isomer exhibits geometrical isomerism only.
3.
1. [Ni(CN)4]2- is a low spin square planar complex as it contains strong field CN- ligand in it.
2. Oxidation state of Ni in complex is +2 Electronic Configuration of Ni2+ is 3d8 4s0
Crystal field splitting in square planar complex.
1. No unpaired electrons, so the complex is diamagnetic.
2. [NiCl4]2- is a high spin tetrahedral complex as it contains weak field Cl- ligand in it.
3. Oxidation state of Ni in complex in +2
4. Electronic Configuration of Ni2+ is 3d8 4s6.
It has two unpaired electrons, so the complex is paramagnetic.
4.
(i) EDTA is used in the volumetric determination of a wide variety of metal ions in solution.
Eg. Zn2+, Pb2+, Ca2+, CO2+, Ni2+,Cu2+, etc.
(ii) By careful adjustment of the pH and using suitable indication, mixtures of metals can v be analyzed.
Eg. Bi3+in the presence of Pb2+
(iii) Hardness of water due to the presence of Ca2+ and Mg2+ ions is estimated by complexometric titrations using EDTA.
5.
| S. No | Double salts | Co-ordination compound |
|---|---|---|
| 1. | They usually contain two simple salt in equimolar proportions | The simple salts from which they are formed may or may not be in equimolar proportion. |
| 2. | They exists only in the solid state. In aqueous solution they dissociate completely into ions. | They exist in the solid state as well as in aqueous solution. This is because even in solution, the complex ion does not dissociate into ions. |
| 3. | They are ionic compounds and do not contain any co-ordinate bond. | They may or may not be ion but the complex part always contain coordinate bonds |
| 4. | The properties of the double salts are same as those of its constituent compounds. | The properties of the coordination compounds are different for its constituent bonds. |
| 5. | In a double salt, the metal ion show their normal valency. | In a coordinate compound the metal ion satisfies its two types of valence called primary & secondary valenices. |
| 6. | A double salt loses its identity and dissociates into its constitute simple ions in solution. | The complex ion does not lose its identity and never dissociate to give simple ions. |
| Example: FeSO4 (NH4)2 SO4.6H2O | Example: K4[Fe(CN)6), K3[Fe(SCN)6) |
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