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TN 12th Computer Applications மின்னணு தரவு பரிமாற்றம் Sample Question Papers Study Material - QB365 Set A

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TN 12th Computer Applications மின் - வணிக பாதுகாப்பு அமைப்புகள் Sample Question Papers Study Material - QB365 Set A

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12th Standard

TN 12th Computer Applications மின்னணு செலுத்தல் முறைகள் Sample Question Papers Study Material - QB365 Set A

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12th Standard

TN 12th Computer Applications மின் - வணிகம் Sample Question Papers Study Material - QB365 Set A

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12th Standard

TN 12th Computer Applications திறந்த மூல கருத்துருக்கள் Sample Question Papers Study Material - QB365 Set A

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12th Standard

TN 12th Computer Applications வலையமைப்பு வடமிடல் Sample Question Papers Study Material - QB365 Set A

12th Standard English Medium Chemistry Subject Hydroxy Compounds and Ethers Book Back 2 Mark Questions with Solution Part - I

Published on: 01/06/2021

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Std: 12th Standard - Chemistry

chapter: - Book back Questions

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Questions:

Generic 3

4 x 3 = 12

Is it possible to oxidise t – butyl alcohol using acidified dichromate to form a carbonyl compound.

Can we use nucelophiles such as NH₃,CH₃O ^- for the Nucleophilic substitution of alcohols

Arrange the following in the increasing order of their boiling point and give a reason for your ordering
(i) Butan – 2- ol, Butan -1-ol, 2 –methylpropan -2-ol
(ii) Propan -1-ol, propan -1,2,3-triol, propan -1,3 – diol, propan -2-ol

Predict the major product, when 2-methyl but -2-ene is converted into an alcohol in each of the following methods.
(i) Acid catalysed hydration
(ii) Hydroboration
(iii) Hydroxylation using Baeyer's reagent

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Answers Key:

Generic 3

4 x 3 = 12

Tertiary alcohols do not undergo oxidation reaction under normal conditions, but at elevated temperature under strong oxidizing, agent cleavage of C-C-bond takes place to give a mixture of carboxylic acid.

Yes, we can use nucleophiles such as NH₃, CH₃O^- for the nucleophilic substitution of alcohol.
Example
\(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}+\mathrm{NH}_{3} \rightarrow \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{NH}_{2}+\mathrm{H}_{2} \mathrm{O} \)
\(\mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OH}+\mathrm{CH}_{2} \mathrm{~N}_{2} \rightarrow \mathrm{C}_{2} \mathrm{H}_{5} \mathrm{OCH}_{3}+\mathrm{N}_{2}\)

(i) 2-methyl propan-2-o1 < Butan-2-ol < Butan-1-ol

(ii) propan-2-ol < propan-1-ol < propan -1,3- diol < propan-1,2,3-triol