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Published on: 13/05/2022
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latest Book back QuestionsDownload Tamil Nadu 12th Standard Chemistry question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Chemistry Test1.
Which of the following fluro compounds is most likely to behave as a Lewis base?
BF3
PF3
CF4
SiF4
2.
Which will make basic buffer?
50 mL of 0.1M NaOH+25mL of 0.1M CH3COOH
100 mL of 0.1M CH3COOH+100 mL of 0.1M NH4OH
100 mL of 0.1M HCl+200 mL of 0.1M NH4OH
100 mL of 0.1M HCl+100 mL of 0.1M NaOH
3.
Conjugate base for Bronsted acids H2O and HF are _______.
OH- and H2FH+, respectively
H3O+ and F-, respectively
OH- and F-, respectively
H3O+ and H2F+, respectively
4.
pH of a saturated solution of Ca(OH)2 is 9. The Solubility product (Ksp) of Ca(OH)2 _______.
0.5 × 10-15
0.25 × 10-10
0.125 × 10-15
0.5 × 10-10
5.
The solubility of BaSO4 in water is 2.42 × 10-3gL-1 at 298K. The value of its solubility product(Ksp) will be (Given molar mass of BaSO4 =233g mol-1)
1.08 × 10-14mol2L-2
1.08 × 10-12mol2L-2
1.08 × 10-10mol2L-2
1.08 × 10-8mol2L-2
1.
BF3 → electron deficient → Lewis acid
PF3 → electron rich → Lewis base
CF4 → neutral → neither Lewis acid nor base
SiF4 → neutral → neither Lewis acid nor base
2.
Basic buffer is the solution which has weak base and its salt.
NH4OH + HCI → NH4CI +H2O + NH4OH
200 ml 100 ml salt 100 ml weak base
3.
H2O + H2O ⇌ H3O+ + OH-
acid 1 base 1 acid 2 base 2
HF + H2O ⇌ H3O+ + F-
acid 1 base 1 acid 2 base 2
∴ Conjugate bases are OH- and F- respectively.
4.
Ca(OH)2 ⇌ Ca2+ + 2OH-
Given that pH = 9
pOH = 14 - 9 = 5
[pOH = - log10 [OH]]
[OH-] = 10 [pOH]
[OH] = 10-5 M
Ksp = [Ca2+] [OH-]
= 10-5/2 x (10-5)2 = 0.5 x 10-15
5.
BaSO4 ⇌ Ba2+ + SO42-
Ksp = (s) (s)
Ksp = (s)2
= (2.42 × 10-3gL-1)2
\(=\frac{2.42 \times 10^{-3} gL^{-1}}{233 \text{ g mol}^{-1}}\)
= (0.01038 x 10-3)2
= (1.038 x x 10-5)2
= 1.077 x 10-10
= 1.08 × 10-10mol2L-2
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