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12th Standard English Medium Chemistry Subject Metallurgy Creative 2 Mark Questions with Solution Part - I

Published on: 21/06/2021

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Std: 12th Standard - Chemistry

chapter: - Creative Questions

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Questions:

Generic 2

5 x 2 = 10

Write the two similarities between calcination and roasting.

Why are sulphide ores converted to oxide form before reduction to metal?

Name the various refining process.

Name some reducing agents used to convert Metal oxides to metal

Name some common methods of ore concentration.

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Answers Key:

Generic 2

5 x 2 = 10

(i) The end product of both the processes is oxide of metal.
(ii) Volatile impurities are removed from the ore and surface area for the further reaction increases.

(i) Sulphide ores thermodynamically are more stable than CS₂and hence cannot be converted by using coke as reducing agent.
(ii) Moreover CO₂ is more volatile and thermodynamically more stable than CS₂.
(iii) Thus \(\Delta G^{ 0 }\) of a metal sulphide is not compensated by the energy of reaction of metal sulphide, with coke.
(iv) Hence, it is better to convert the sulphide ore to oxide form and then subject to smelting (i.e) carbon reduction method.

Distillation, liquation, electrolytic refining, zone refining, vapour phase method, van -Arkel method

Metal oxides to metal : Carbon, carbon monoxide, hydrogen, aluminum and metals like sodium.

Gravity separation, froth flotation, leaching, magnetic separation