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Published on: 21/06/2021
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Questions + Answers key
Take MCQ Chemistry Test1.
Starting from the following reagents, how will your prepare ethanenitrile.
i) CH3Br
ii) CH3CONH2
iii) CH3CH=NOH
2.
Convert aniline to p-nitro aniline
3.
Aniline reacts with Br2/H2O to give a tribromo derivative. How would you convert aniline to get a monobromo derivate?
4.
Outline the preparation of (a) para nitroaniline from aniline, (b) tri bromo benzene from tribromo aniline
5.
An Organic compound (A) with molecular formula C6H7N gives (B) with HNO2 / HCI at 273 K. The aqueous solution of (B) on heating gives compound (C) which gives violet colour with netural FeCI3. Identify the compounds (A), (B) and (C) and write the equations.
1.
(i) Aryl cyanide cannot be prepared in this method because of their less reactivity towards nucleophilic substitution. Aryl cyanides are prepared using Sandmeyers reactions.
\(KCH+\underset { methyl \ bromide }{ { CH }_{ 3 }-Br } \rightarrow \underset { ethanenitrile }{ { CH }_{ 3 }-CN } +KBr\)
(ii) By dehydration' of primary amides a aldoximes with P2O5
\(\underset { Acetamide }{ { CH }_{ 3 }-CO{ NH }_{ 2 } } \xrightarrow [ { -H }_{ 2 }O ]{ { P }_{ 2 }{ O }_{ 5 } } \underset { Ethaneitrile }{ { CH }_{ 3 }-{ CN } } \)
(iii) \(\underset { Acetaldoximes }{ { CH }_{ 3 }-CH=NOH } \xrightarrow [ { -H }_{ 2 }O ]{ { P }_{ 2 }{ O }_{ 5 } } \underset { Ethaneitrile }{ { CH }_{ 3 }-{ CN } } \)
2.
To get para product, the - NH2 group is protected by acetylation with acetic anhydride. Then, the nitrated product is hydrolysed to form the product.
3.
To get mono bromo compounds, -NH2 is first acylated to reduce its activity.
4.
(i) p-nitroaniline is prepared from aniline in three stages as follows:
(ii)
5.
(i) An organic compound (A) with molecular formula C6H7N is identified as Aniline C6H5NH2
(ii) Aniline on treatment with HNO2 / HCl at 273 K gives a clear solution of Benzene diazonium chloride C6H5N2CI the compound (B).
\({ C }_{ 6 }{ H }_{ 5 }{ NH }_{ 2 }+{ HNO }_{ 2 }\xrightarrow [ 273K ]{ NCl } \underset { Benzene \ diazonium \ chloride }{ { C }_{ 6 }{ H }_{ 5 }{ N }_{ 2 }Cl } \)
(iii) An aqueous solution of benzene diazonium chloride on heating gives phenol C6H5OH and it is compound (C).
\({ C }_{ 6 }{ H }_{ 5 }{ N }_{ 2 }Cl+{ HOH }\underrightarrow { \triangle } { C }_{ 6 }{ H }_{ 5 }OH-{ N }_{ 2 }+HCl\)
| A | C6H5NH2 | Aniline |
| B | C6H5N2Cl | Benzene diazonium chloride |
| C | C6H5OH | Phenol |
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