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Published on: 13/05/2022
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Take MCQ Chemistry Test1.
An element A occupies group number 15 and period number 3, reacts with chlorine to give compound B. The compound B on hydrolysis gives a dibasic acid C. The compound C on heating undergoes auto oxidation and reduction to give a tribasic acid D. Identify the elements A compounds B, C and D. Write the reactions.
2.
An element 'A' occupies group number 15 and period number 3. It reacts with chlorine to give B which further reacts with chlorine to give C at 273K. Both B and C are chlorinating agents for organic compounds. C is a better chlorinating agent because it chlorinates metals also. Breasts with SO3 and reduces it to SO2 B has a pyramidal shape. C has trigonal bipyramidal shape by sp3d hybridisation. Identify the element A and the compounds B and C. Write the reactions.
3.
An element A occupies group number 15 and period number 3, exhibits allotropy and it is tetra atomic. A reacts with caustic soda to give B which is having rotten fish odour. A reacts with chlorine to give C which has a pungent odour Identify A, B and C. Write the reactions.
4.
(i) \(\mathrm{PCl}_{5}+\mathrm{Ag} \longrightarrow \text { ? } \)
(ii) \(\mathrm{AgCl}_{(s)}+\mathrm{NH}_{3(\mathrm{aq})} \longrightarrow ? \)
(iii) \(\mathrm{PCl}_{3} \stackrel{\text { Moist air }}{\longrightarrow} \text { ? } \)
(iv) \(\mathrm{PCl}_{5} \stackrel{\text { Moist air }}{\longrightarrow} ? \)
(v) \(\mathrm{NaH}_{2} \mathrm{PO}_{2}+\mathrm{HCl} \longrightarrow ?\)
5.
1.
(i) As per the position in the periodic table, the element A is phosphorus as below:
(ii) Phosphorus reacts with dry chlorine to form phosphorus trichloride as below
\(\underset { (A) }{ { P }_{ 4 } } +6{ Cl }_{ 2 }\longrightarrow \underset { (B) }{ { 4PCl }_{ 3 } } \)
Hence, compound B is phosphorus trichloride.
(iii) PCl3 on hydrolysis gives phosphorus acid H3PO3, which is dibasic acid,
\(\underset { (B) }{ { PCl }_{ 3 } } +3{ H }_{ 2 }O\longrightarrow { 3HCl }+\underset { (C) }{ { H }_{ 3 }{ PO }_{ 3 } } \)
Hence, compound C is phosphorus acid.
(iv) H3PO3 on heating undergo auto oxidation and reduction producing phosphoric acid md phosphine as below:
\(\underset { (c) }{ { 4H }_{ 3 }{ PO }_{ 3 } } \overset { \Delta }{ \longrightarrow } { PH }_{ 3 }+\underset { (b) }{ { 3H }_{ 3 }{ PO }_{ 4 } } \)
Phosphoric acid is a tribasic acid. Hence, compound D is phosphoric acid.
Thus A = Phosphorus
B = Phosphorus trichloride
C = Phosphorus acid
D = Phosphoric acid
2.
(i) The element which occupies group number 15 and period number 3 is phosphorus. Therefore A is phosphorus. Phosphorus reacts with chlorine to give PCI3There fore compound B is phosphorus trichloride and it has a pyramidal shape.
P4 + 6Cl2 \(\longrightarrow \) 4PCl3
PCl3 further reacts with Cl2 to give PCl5
Therefore, the compound C is phosphorus pentachloride and it has a trigonal bipyramidal shape.
PCI + CI\(\longrightarrow \) PCI
Thus, A= Phosphorus
B = Phosphorus trichloride (PCI3)
C = Phosphorous pentachloride (PCI5)
3.
(i) The element which occupies group number 15 and period number 3 is phosphorus. Hence, A is phosphorus This is further supported by the fact that A exhibits allotropy and A is tetra atomic.
(ii) Phosphorus reacts with caustic soda to form phosphine as below:
4P + 3 NaOH + 3H2O \(\longrightarrow \) PH3 + 3 NaH2PO2
Hence, B is phosphine PH3 which has rotten fish odour.
(iii) Phosphorus reacts with dry chlorine to form phosphorus trichloride which has a pungent odour.
P4 + 6 Cl2\(\longrightarrow \) 4PCl3
Thus, A = Phosphorus
B = Phosphine
C = Phosphorus trichloride
4.
(i) PCl5 + 2Ag \(\longrightarrow \) 2 AgCl + PCl3
(ii) AgCI(s)+ 2NH3(aq) \(\longrightarrow \)[Ag(NH3)2]CI(aq)
(iii) PCl3 + 3H2O \(\longrightarrow \) H3PO3 + 3HCI
(iv) PCl5 + H2O \(\longrightarrow \) POCl3 + 2HCI
(v) NaH2PO2 + HCI \(\longrightarrow \) H3PO2 + NaCl
5.
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