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Published on: 01/06/2021
QB365 provides detailed and simple solution for every Book back Questions in class 12 Chemistry Subject. It will helps to get more idea about question pattern in every book back questions with solution.
Download Tamil Nadu 12th Standard Chemistry question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Chemistry Test1.
Formation of water due to the reaction of H2 and O2 in the presence of Cu proceeds as follows. Steps in the reaction H2 + 1/2O2 → H2O can be given as
2.
Thermal decomposition of KClO3 in presence of MnO2 proceeds as follows.
Steps in the reaction 2KClO3 → 2KCl + 3O2 can be given as
3.
The mechanism of Fridel crafts reaction is given below
\({ C }_{ 6 }{ H }_{ 5 }+{ { CH }_{ 3 }Cl\overset { anhydrous\\ \quad { Alcl }_{ 3 } }{ \longrightarrow } }{ C }_{ 6 }{ H }_{ 5 }{ CH }_{ 3 }+HCl\)
4.
In a coagulation experiment 10 mL of a colloid (X) is mixed with distilled water and 0.1M solution of an electrolyte AB so that the volume is 20 mL. It was found that all solutions containing more than 6.6 mL of AB coagulate with in 5 minutes. What is the flocculation values of AB for sol (X)?
1.
2Cu + \(\frac{1}{2}\)O2 → Cu2O
It is an intermediate.
Cu2O + H2 → H2O + 2Cu
2.
2KClO3 + 6MnO2 → 6MnO3 + 2KCl
It is an intermediate
6MnO3 → 6MnO2 + 3O2
3.
The action of catalyst is explained as follows
CH3Cl + AlCl3 → [CH3 ]+[AlCl4]-
It is an intermediate.
C6H6 + [CH3+][AlCl4]- → C6H5CH3 + AlCl3 + HCl
4.
A minimum of 6.6 ml of AB is required to coagulated the sol.
The number of moles of AB in the sol is
= \(\cfrac { 6.6\times 0.1 }{ 20 } \)
= 0.033 moles
This means that minimum of 0.033 moles or 33 millimoles are required to coagulate 1litre of sol.
∴ Flocculating value of AB for sol = 33.
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