12th Standard Syllabus & Materials
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TN 12th English Poem - 6 - Incident of the French Camp Sample Question Papers Study Material - QB365 Set A
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TN 12th English Prose - 6 - On the Rule of the Road Sample Question Papers Study Material - QB365 Set A
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TN 12th English Prose - 5 - The Chair Sample Question Papers Study Material - QB365 Set A
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TN 12th English Supplementary - 4 - The Midnight Visitor Sample Question Papers Study Material - QB365 Set A
NEW12th Standard
TN 12th English Poem - 4 - Ulysses Sample Question Papers Study Material - QB365 Set A
NEW12th Standard
TN 12th English Prose - 4 - The Summit Sample Question Papers Study Material - QB365 Set A
Published on: 13/05/2022
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latest Book back QuestionsDownload Tamil Nadu 12th Standard Chemistry question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Chemistry Test1.
Formation of water due to the reaction of H2 and O2 in the presence of Cu proceeds as follows. Steps in the reaction H2 + 1/2O2 → H2O can be given as
2.
Thermal decomposition of KClO3 in presence of MnO2 proceeds as follows.
Steps in the reaction 2KClO3 → 2KCl + 3O2 can be given as
3.
The mechanism of Fridel crafts reaction is given below
\({ C }_{ 6 }{ H }_{ 5 }+{ { CH }_{ 3 }Cl\overset { anhydrous\\ \quad { Alcl }_{ 3 } }{ \longrightarrow } }{ C }_{ 6 }{ H }_{ 5 }{ CH }_{ 3 }+HCl\)
4.
In a coagulation experiment 10 mL of a colloid (X) is mixed with distilled water and 0.1M solution of an electrolyte AB so that the volume is 20 mL. It was found that all solutions containing more than 6.6 mL of AB coagulate with in 5 minutes. What is the flocculation values of AB for sol (X)?
1.
2Cu + \(\frac{1}{2}\)O2 → Cu2O
It is an intermediate.
Cu2O + H2 → H2O + 2Cu
2.
2KClO3 + 6MnO2 → 6MnO3 + 2KCl
It is an intermediate
6MnO3 → 6MnO2 + 3O2
3.
The action of catalyst is explained as follows
CH3Cl + AlCl3 → [CH3 ]+[AlCl4]-
It is an intermediate.
C6H6 + [CH3+][AlCl4]- → C6H5CH3 + AlCl3 + HCl
4.
A minimum of 6.6 ml of AB is required to coagulated the sol.
The number of moles of AB in the sol is
= \(\cfrac { 6.6\times 0.1 }{ 20 } \)
= 0.033 moles
This means that minimum of 0.033 moles or 33 millimoles are required to coagulate 1litre of sol.
∴ Flocculating value of AB for sol = 33.
12th Standard Syllabus & Materials
12th Standard
TN 12th English Supplementary - 3 - The Hour of Truth (Play) Sample Question Papers Study Material - QB365 Set A
NEW12th Standard
TN 12th English Poem - 3 - All the World’s a Stage Sample Question Papers Study Material - QB365 Set A
NEW12th Standard
TN 12th English Prose - 3 - In Celebration of Being Alive Sample Question Papers Study Material - QB365 Set A
NEW12th Standard
TN 12th English Supplementary - 2 - Life of Pi Sample Question Papers Study Material - QB365 Set A
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