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Published on: 13/05/2022
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Questions + Answers key
Take MCQ Chemistry Test1.
What are transition metals? Give four examples.
2.
Complete the following.
a. 3MnO42- + 4H+ ⟶?
b. C6H5CH3 \(\overset { acidified }{ \underset { KMnO_{ 4 } }{ \longrightarrow } } \)?
c. MnO4- + Fe2+ ⟶?
d. KMnO4 \(\overset { \triangle }{ \underset { Red\ hot }{ \longrightarrow } } \) ?
e. Cr2O72- + 6I- + 14H+ ⟶?
f. Na2Cr2O7 + 2KCl ⟶?
3.
What is lanthanoid contraction and what are the effects of lanthanoid contraction?
4.
5.
Explain the oxidation states of 4d series elements.
1.
IUPAC defines transition metal as an element whose atom has an incomplete d-sub shell or which can give rise to cations with an incomplete d-sub shell. They occupy the central position of the periodic table, between s and p-block elements.
Examples: Fe, Cu, Ag, Au
2.
a. 3MnO42- + 4H+ ⟶ 2MnO4- + MnO2 + 2H2O
(Manganate ion) (Permanganate ion) Manganese dioxide
b. C6H5CH3 \(\overset { acidified }{ \underset { KMnO_{ 4 } }{ \longrightarrow } } \) C6H5COOH
Toluene Benzoic Acid
c. 2MnO4- + 10Fe2++16H+ \(\underrightarrow { { 8H }^{ + } } \) 2Mn2++ 10Fe3+ + 8H2O
d. 2KMnO4 \(\overset { \triangle }{ \underset { Red\ hot }{ \longrightarrow } } \) K2MnO4 + MnO2 + O2
(Potassium Permanganate) (Potassium Manganate)
e. Cr2O72- + 6I- + 14H+ \(\underrightarrow { { (O) }}\) 2Cr3+ + 3I2 + 7H2O
(Iodide ion) Iodine
f. Na2Cr2O7 + 2KCl ⟶ K2Cr2O7 + 2NaCl
(Sodium dichromate) (Potassium dichromate)
3.
Lanthanoid contraction:
As we move across 4f series, the atomic and ionic radii of lanthanoids show gradual decrease with increase in atomic number. This decrease in ionic size is called lanthanoid contraction.
Effects (consequence) of lanthanoid contraction:
1. Basicity difference:
As we move from Ce3+ to Lu3+, the basic character of Ln3+ ions decrease. Due to the decrease in the size of Ln3+ ions, the ionic character of Ln -OH bond decreases (covalent character increases) which results in the decrease in the basicity.
2. Similarities among lanthanoid:
In the complete f - series only 10 pm decrease in atomic radii and 20 pm decrease in ionic radii is observed because of this very small change in radii of lanthanoids, their chemical properties are quite similar.
3. The elements of the second and third transition series resemble each other more closely than the elements of the first and second transition series.
4.
5.
The oxidation states of 4d metals vary from +3 for Y to +8 for Ru and Os.
The highest oxidation state of 4d elements are found in their compounds with the higher electronegative elements like O, F & Cl.
Example: In RuO4, OsO4 & WCl6
The oxidation state of Ru and Os is +8.
The oxidation state of W is +6.
Generally in going down a group, a stability of higher oxidation state increases while that of lower oxidation state decreases.
4d series (5th period) - Yttrium to Cadmium (10 elements)
| Elements | Oxidation states |
|---|---|
| Y | +3 |
| Zr | +3, +4 |
| Nb | +2, +3, +4, +5 |
| Mo | +2, +3, +4, +5, +6 |
| Tc | +2, +4, +5, +7 |
| Ru | +2, +3, +4, +5, +6, +7 +8 |
| Rh | +2, +3, +4, +6 |
| Pd | +2, +3, +4 |
| Ag | +1, +2, +3 |
| Cd | +2 |
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