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Published on: 13/05/2022
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Questions + Answers key
Take MCQ Physics Test1.
Write briefly the underlying principle used in Davison-Germer experiment to verify wave nature of electrons experimentally. What is the de-Broglie wavelength of an electron with kinetic energy (KE) 120 eV?
2.
Determine the value of the de Broglie wavelength associated with the electron orbiting in the ground state of hydrogen atom (Given En = -(13.6 n2) eV and Bohr radius r0 = 0.53 Å). How will the de Broglie wavelength change when it is in the first excited state?
3.
For photo electronic effect in sodium, the figure shows the plot of cut-off voltage versus frequency of incident radiation. Calculate
(i) threshold frequency
(ii) work function for sodium.

4.
Write the application of x-rays.
5.
The ground state energy of the hydrogen atom is -13.6 eV. If an electron makes a transition from an energy level -1.51 eV to -3.4 eV, calculate the wavelength of the spectral line emitted and name the series of hydrogen spectrum to which it belongs.
1.
Principle: Diffraction effects are observed for beams of electrons scattered by the crystals.
λ = \(\frac { h }{ p } =\frac { h }{ \sqrt { 2mE_{ k } } } =\frac { h }{ \sqrt { 2meV } } \)
= \(\frac { 6.63\times { 10 }^{ -34 } }{ \sqrt { 2\times 9.1\times 10^{ -31 }\times 1.6\times 10^{ -19 }\times 120 } } \)
λ = 0.112 nm.
2.
In ground state, the kinetic energy of the electron is
K = -E = \(\frac { +13.6eV }{ 1^{ 2 } } \) =13.6 x 1.6 x 10-19 J
de Broglie wavelength,
λ = \(\frac { h }{ p } =\frac { h }{ \sqrt { 2mK } } \)
λ1 = -\(\frac { 6.63\times { 10 }^{ -34 } }{ \sqrt { 2\times 9.1\times 10^{ -31 }\times 2.18\times 10^{ -18 } } } \)
= 9.33 x 10-9 = 0.33 nm
Kinetic energy in the first excited state (n = 2)
K = -E = + \(\frac { 13.6 }{ 2^{ 2 } } \) eV = +3.4 eV
= 3.4 x 1.6 x 10-19 J
= 0.54 x 10-18 J
de Broglie wavelength,
λ2 = \(\frac { h }{ \sqrt { 2mK } } \)
= \(\frac { 6.63\times { 10 }^{ -34 } }{ \sqrt { 2\times 9.1\times { 10 }^{ -31 }\times 0.544\times { 10 }^{ -15 } } } \)
= 2 x 0.33 nm = 0.66 mm.
3.
(i) The threshold frequency is the frequency of incident light at which kinetic energy of ejected photoelectron is zero.
∴ From fig. threshold frequency,
v0 = 4.5 x 1014 Hz
(ii) Work function, W = hv0
= 6.6 x 10-34 x 4.5 x 1014 joule
= \(\frac { 6.6\times { 10 }^{ -34 }\times 4.5\times 10^{ 14 } }{ 1.6\times { 10 }^{ -19 } } \) eV
= 1.85 eV
4.
X-rays are being used in many fields. Let us list a few of them.
(i) Medical diagnosis X-rays can pass through flesh more easily than through bones. Thus an x-ray radiograph containing a deep shadow of the bones and a light shadow of the flesh may be obtained. X-ray radiographs are used to detect fractures, foreign bodies, diseased organs, etc.
(ii) Medical therapy Since x-rays can kill diseased tissues, they are employed to cure skin diseases, malignant tumors, etc.
(iii) Industry X-rays are used to check for flaws in welded joints, motor tires, tennis balls, and wood. At the customs post, they are used for the detection of contraband goods.
(iv) Scientific research X-ray diffraction is an important tool to study the structure of the crystalline materials - that is, the arrangement of atoms and molecules in crystals.
5.
Energy differnce = Energy of emitted photon
= E2 - E1
= -1.51 - (-3.4) = 1.89 eV
= 1.89 x 1.6 x 10-19 J
λ = \(\\ \frac { hc }{ { E }_{ 2 }-{ E }_{ 1 } } \)
= \(\frac { 6.6\times { 10 }^{ -34 }\times 3\times { 10 }^{ 8 } }{ 1.89\times 1.6\times 10^{ -19 } } =\frac { 19.8 }{ 3.024 } \) x 10-7
= 6.548 x 10-7 m = 6548 Å
The wavelength belongs to the Balmer series of the hydrogen spectrum.
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