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Published on: 13/05/2022
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Questions + Answers key
Take MCQ Physics Test1.
Write the applications of mobile communication.
2.
For a BJT circuit shown, assume that the 'β' of the transistor is very large and VBE= 0.7 V. The mode of operation.
3.
For a BJT, the common - base current gain α = 0.98 and the collector base junction reverse bias saturation ICU = 0.6μA. This BJT is connected in the common emitter mode and operated in the active region with a base drive current ID= 20 μA. The collector current IC for this mode of operating is
4.
Write any two distinguishing features between Insulators, Metals and semiconductors and insulators an the basis of energy band diagrams.
5.
Explain and classify transistor as an oscillator.
1.
(i) It is used for personal communication and cellular phones offer voice and data connectivity with high speed.
(ii) Transmission of news across the globe is done within a few seconds.
(iii) Using Internet of Things (UIT), it is made possible to control various devices from a single device. Example: home automation using a mobile phone.
(iv) It enables smart classrooms, online availability of notes, monitoring student activities etc. in the field of education.
2.
VBE =0.7V
Input junction is a forward biased.
Since,
VBE = 0.7V
VCE = VBE+ VCB
VCB = VCE-VBE
To determine VCB we find IC
\({ I }_{ C }\cong { I }_{ C }\frac { 2-{ V }_{ BE } }{ { R }_{ 2 } } =\frac { 2-0.7 }{ 1k\Omega } \)
IC = 1.3mA
VCE = VCC - IC (R1 + R2)
= 10 - 1.3mA (10K + 1K)
VCE = - 4.3 V
VCE =-4.3V-0.7
VCB = - 5V
3.
α = 0.98
ICu = 0.6 μA
\(\alpha =\frac { \beta }{ 1+\beta } \)
(or)
\(0.98=\frac { 1 }{ \frac { 1 }{ \beta } +1 } \)
β = 49
ICEO = (1 + β)ICBO
= (1 + 49) x 0.6μA
ICEO = 30 μA
= (1 + 49) x 0.6 μA
ICEO = 30 μA
IC = βIB+ ICEO
= 49 x 20 μA + 30 μA
IC = 1.01 mA
4.
Insulators:
(i) The valence band and the conduction band are separated by a large energy gap.
(ii) The forbidden energy gap is approximately 6 eV in insulators.
(iii) The gap is very large that electrons from valence band cannot move into conduction band even on the application of strong external electric field or the increase in temperature.
Metals
(i) In metals, the valence band and conduction band overlap.
(ii) Hence, electrons can move freely into the conduction band which results in a large number of free electrons in the conduction band.
Semiconductors
(i) In semiconductors, there exists a narrow forbidden energy gap (E < 3eV) between - g the valence band and the conduction band.
(ii) Free electrons are small in number, the conductivity of the semiconductors is not as high as that of the conductors.
5.
(i) An oscillator basically converts de energy into ac energy of high frequency ranging from a few Hz to several MHz.
(ii) There are two types of oscillators
a) Sinusoidal
b) Non-sinusoidal.
(iii) Sinusoidal oscillators generate oscillations in the form of sine wave at constant amplitude and frequency.
(iv) Non-sinusoidal oscillators generate complex non-sinusoidal waveforms like square wave, Triangular - wave or Sawtooth -wave
(v) Sinusoidal oscillations can be of two types:
a) Damped
b) undamped.
(vi) If the amplitude of the electrical oscillations decreases with time due to energy loss, is called damped oscillations
(vii) The amplitude of the electrical oscillations remains constant with time in undamped oscillations.
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Computer Applications

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