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Published on: 01/09/2022
QB365 provides a detailed and simple solution for every Possible Book Back Questions in Class 12 Maths Subject - Complex Numbers, English Medium. It will help Students to get more practice questions, Students can Practice these question papers in addition to score best marks.
Download Tamil Nadu 12th Standard Maths question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Maths Test1.
If \(\omega =cis\cfrac { 2\pi }{ 3 } \), then the number of distinct roots of \(\left| \begin{matrix} z+1 & \omega & { \omega }^{ 2 } \\ \omega & z+{ \omega }^{ 2 } & 1 \\ { \omega }^{ 2 } & 1 & z+\omega \end{matrix} \right| \)=0
1
2
3
4
2.
The value of \(\left( \cfrac { 1+\sqrt { 3 } i}{ 1-\sqrt { 3}i } \right) ^{ 10 }\) is
\(cis\cfrac { 2\pi }{ 3 } \)
\(cis\cfrac { 4\pi }{ 3 } \)
\(-cis\cfrac { 2\pi }{ 3 }\)
\(-cis\cfrac { 4\pi }{ 3 }\)
3.
If \(\omega \neq 1\) is a cubic root of unity and \(\left| \begin{matrix} 1 & 1 & 1 \\ 1 & { -\omega }^{ 2 }-1 & { \omega }^{ 2 } \\ 1 & { \omega }^{ 2 } & { \omega }^{ 7 } \end{matrix} \right| \) = 3k, then k is equal to
1
-1
\(\sqrt { 3i } \)
\(-\sqrt { 3i } \)
4.
5.
If \(\alpha \) and \(\beta \) are the roots of x2+x+1 = 0, then \({ \alpha }^{ 2020 }+{ \beta }^{ 2020 }\) is
-2
-1
1
2
6.
7.
8.
If (1+i)(1+2i)(1+3i)...(1+ni) = x + iy, then \(2\cdot 5\cdot 10...\left( 1+{ n }^{ 2 } \right) \) is
1
i
x2+y2
1+n2
9.
10.
The principal argument of \(\cfrac { 3 }{ -1+i } \) is
\(\cfrac { -5\pi }{ 6 } \)
\(\cfrac { -2\pi }{ 3 } \)
\(\cfrac { -3\pi }{ 4 } \)
\(\cfrac { -\pi }{ 2 } \)
11.
If z = x + iy is a complex number such that |z+2| = |z−2|, then the locus of z is
real axis
imaginary axis
ellipse
circle
12.
If \(\frac { z-1 }{ z+1 } \) is purely imaginary, then |z| is
\(\frac { 1 }{ 2 } \)
1
2
3
13.
z1, z2 and z3 are complex number such that z1 + z2 + z3 = 0 and |z1| = |z2| = |z3| = 1 then z12 + z22 + z33 is
3
2
1
0
14.
If z is a complex number such that \(z \in \mathbb{C} \backslash \mathbb{R}\) and \(z+\frac { 1 }{ z } \epsilon R\), then |z| is
0
1
2
3
15.
If |z1| = 1, |z2| = 2, |z3| = 3 and |9z1z2 + 4z1z3 + z2z3| = 12, then the value of |z1+z2+z3| is
1
2
3
4
16.
17.
If |z| = 1, then the value of \(\frac { 1+z }{ 1+\overline { z } }\) is
z
\(\bar { z } \)
\(\cfrac { 1 }{ z } \)
1
18.
If \(\left| z-\frac { 3 }{ z } \right| =2\), then the least value |z| is
1
2
3
5
19.
If |z - 2 + i | ≤ 2, then the greatest value of |z| is
\(\sqrt { 3 } -2\)
\(\sqrt { 3 } +2\)
\(\sqrt { 5 } -2\)
\(\sqrt { 5 } +2\)
20.
If z is a non zero complex number, such that 2iz2 = \(\bar { z } \) then |z| is
\(\cfrac { 1 }{ 2 } \)
1
2
3
21.
If \(z=\cfrac { \left( \sqrt { 3 } +i \right) ^{ 3 }\left( 3i+4 \right) ^{ 2 } }{ \left( 8+6i \right) ^{ 2 } } \) , then |z| is equal to
0
1
2
3
22.
The conjugate of a complex number is \(\cfrac { 1 }{ i-2 } \). Then the complex number is
\(\cfrac { 1 }{ i+2 } \)
\(\cfrac { -1 }{ i+2 } \)
\(\cfrac { -1 }{ i-2 } \)
\(\cfrac { 1 }{ i-2 } \)
23.
The area of the triangle formed by the complex numbers z, iz and z+iz in the Argand’s diagram is
\(\cfrac { 1 }{ 2 } \left| z \right| ^{ 2 }\)
|z|2
\(\cfrac { 3 }{ 2 } \left| z \right| ^{ 2 }\)
2|z|2
24.
The value of \(\sum_{n=1}^{13}\left(i^{n}+i^{n-1}\right)\) is
1+ i
i
1
0
25.
in+in+1+in+2+in+3 is
0
1
-1
i
1.
Comparing the two given lines with
\(\vec { r } =\vec { a } +t\vec { b } ,\vec { r } =\vec { c } +s\vec { d } \)
we have, \(\vec { a } =-\hat { -1 } -3\hat { j } -5\hat { k } ,\vec { b } =3\hat { i } +5\hat { j } +7\hat { k } ,\vec { c } =2\hat { i } +4\hat { j } +6\hat { k } \) and \(\vec { d } =\hat { i } +4\hat { j } +7\hat { k } \)
We know that the two given lines are coplar, if \((\vec { c } -\vec { a } ).(\vec { b } \times \vec { d } )\)=0
Here, \(\vec { b } \times \vec { d } \left| \begin{matrix} \hat { i } & \hat { j } & \hat { k } \\ 3 & 5 & 7 \\ 1 & 4 & 7 \end{matrix} \right| =7\hat { i } -14\hat { j } +7\hat { k } \) and \(\vec { c } -\vec { a } =3\hat { i } +7\hat { j } +11\hat { k } \)
Then, \((\vec { c } -\vec { a } ).(\vec { b } \times \vec { d } )=(3\hat { i } +7\hat { j } +11\hat { k } )(7\hat { i } -14\hat { j } +7\hat { k } )\)
Therefore the two given lines are coplanar.Then we find the non parametric form of vector equation of the plane containing the two given coplanar lines. We know that the plane containing the two given coplanar lines is
\((\vec { r } -\vec { a } ).(\vec { b } \times \vec { d } )\)=0
which implies that \((\vec { r } -(-\hat { i } -3\hat { j } -5\hat { k } )).(7\hat { i } -14\hat { j } +7\hat { k } )\)=0. Thus, the required non-parametric vector equation of the plane containing the two given coplanar lines is \(\vec { r } .(\hat { i } -2\hat { j } +\hat { k } )\)=0.
2.
(a)
\(cis\cfrac { 2\pi }{ 3 } \)
3.
(d)
\(-\sqrt { 3i } \)
4.
(b)
5.
(b)
-1
6.
(b)
7.
(b)
8.
(c)
x2+y2
9.
(b)
10.
(c)
\(\cfrac { -3\pi }{ 4 } \)
11.
(b)
imaginary axis
12.
(b)
1
13.
(d)
0
14.
(b)
1
15.
(b)
2
16.
(b)
17.
(a)
z
18.
(a)
1
19.
(d)
\(\sqrt { 5 } +2\)
20.
(a)
\(\cfrac { 1 }{ 2 } \)
21.
(c)
2
22.
(b)
\(\cfrac { -1 }{ i+2 } \)
23.
(a)
\(\cfrac { 1 }{ 2 } \left| z \right| ^{ 2 }\)
24.
(a)
1+ i
25.
(a)
0
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