12th Standard Syllabus & Materials
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TN 12th Computer Applications வலையமைப்பு வடமிடல் Sample Question Papers Study Material - QB365 Set A
Published on: 12/10/2020
12th Standard Physics English Medium Free Online Test Book Back 1 Mark questions with Answer Key Part Two
Download Tamil Nadu 12th Standard Physics question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Physics Test1.
The alloys used for muscle wires in Robots are _____.
Shape memory alloys
Gold copper alloys
Gold silver alloys
Two dimensional alloys
2.
The variation of frequency of carrier wave with respect to the amplitude of the modulating signal is called ______.
Amplitude modulation
Frequency modulation
Phase modulation
Pulse width modulation
3.
4.
Mp denotes the mass of the proton and Mn denotes mass of a neutron. A given nucleus of binding energy B, contains Z protons and N neutrons. The mass M(N, Z) of the nucleus is given by _____.(where c is the speed of light)
M (N,Z) = NMn + ZMp - Bc2
M (N,Z) = NMn + ZMp + Bc2
M (N,Z) = NMn + ZMp - B/c2
M (N,Z) = NMn + ZMp + B/c2
5.
The threshold wavelength for a metal surface whose photoelectric work function is 3.313 eV is _____.
4125 \(\mathring { A } \)
3750\(\mathring { A } \)
6000\(\mathring { A } \)
2062.5\(\mathring { A } \)
6.
A ray of light strikes a glass plate at an angle 60o. If the reflected and refracted rays are perpendicular to each other, the refractive index of the glass is, _____.
\(\sqrt3\)
\(\frac{3}{2}\)
\(\sqrt{\frac{3}{2}}\)
2
7.
Two short bar magnets have magnetic moments 1.20 Am2 and 1.00 Am2 respectively. They are kept on a horizontal table parallel to each other with their north poles pointing towards south. They have a common magnetic equator and are separated by a distance of 20.0 cm. The value of the resultant horizontal magnetic induction at the mid-point O of the line joining their centres is (Horizontal components of Earth’s magnetic induction is 3.6 × 10–5 Wb m–2 )
3.60 × 10-5 Wb m-2
3.5 × 10-5 Wb m-2
2.56 × 10-4 Wb m-2
2.2 × 10-4 Wb m-2
8.
An inductor 20 mH, a capacitor 50 μF and a resistor 40Ω are connected in series across a source of emf V = 10 sin 340 t. The power loss in AC circuit is
0.76 W
0.89 W
0.46 W
0.67 W
9.
Which of the following is an electromagnetic wave?
α - rays
β - rays
\(\gamma\) - rays
all of them
10.
A parallel plate capacitor stores a charge Q at a voltage V. Suppose the area of the parallel plate capacitor and the distance between the plates are each doubled then which is the quantity that will change?
Capacitance
Charge
Voltage
Energy density
1.
They are thin strands of wire made of shape memory alloys. They can contract by 5% when electric current is passed through them.
2.
(b)
Frequency modulation
3.
(d)
4.
B = ∆m x c2
∆m = \(\frac{B}{c^2}\)
N Mn + Z Mp - M(N,Z) = \(\frac{B}{c^2}\)
N (N,Z) = N Mn + ZMp - \(\frac{B}{c^2}\)
5.
\(\lambda_0 =\frac{h c}{\phi} \)
\(=\frac{6.626 \times 10^{-34} \times 3 \times 10^8}{3.313 \times 1.6 \times 10^{-19}} \)
\( =\frac{19.8782400}{5.3} \times 10^{-7} \)
\(\lambda_0 =3.750 \times 10^{-7} \simeq 3750 \stackrel{o}A\)
6.
n = tan ip = tan 60o = \(\sqrt{3}\)
7.
(c)
2.56 × 10-4 Wb m-2
8.
L = 20 x 10-3H. C = 50 x 10-6 F, R= 40Ω
enf V = 10 sin 340 t
\(\therefore V_0=10 \mathrm{~V}, \omega=340 \)
\(X_1=1 \omega^{\prime}=20 \times 10^3 \times 340 \)
\(=6800 \times 10^{-1}=6.8 \Omega \)
\(X_C=\frac{1}{C .} \)
\(=\frac{1}{50 \times 10^{-\alpha} \times 340}=\frac{10^{\circ}}{17000}=\frac{10^{\prime}}{17}=58.823 \Omega \)
\(Z=\sqrt{R^2+\left(X_6-X_1\right)^2} \)
\(=\sqrt{(40)^2+(58.82-6.8)^2} \)
\(=\sqrt{(40)^2+(52.02)^2} \)
\(=65.62 \Omega\)
The peak current in the circuit is,
\(I_0=\frac{V_0}{Z}=\frac{10}{65.62} \)
\(\cos 0=\frac{R}{Z}=\frac{40}{65.62} \)
\(\text{Power loss in A.C. circuit }=V_{r m} 1_{r \rightarrow \infty} \cos \phi \)
\(=\frac{1}{2} V_{\mathrm{o}} I_{\mathrm{c}} \cos \phi \)
\(=\frac{1}{2} \times 10 \times \frac{10}{65.62} \times \frac{40}{65.62}\)
\(\frac{2000}{4305.98}\)
= 0.46 W
9.
(c)
\(\gamma\) - rays
10.
Energy density uE \(=\frac{U}{volume}\)
If A' = 2A d ' = 2d
Then V ' = 2A x 2d = 4Ad = 4V
Then volume would be increased. So, energy density will change.
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