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TN 12th Computer Applications மின்னணு செலுத்தல் முறைகள் Sample Question Papers Study Material - QB365 Set A

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TN 12th Computer Applications மின் - வணிகம் Sample Question Papers Study Material - QB365 Set A

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TN 12th Computer Applications திறந்த மூல கருத்துருக்கள் Sample Question Papers Study Material - QB365 Set A

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12th Standard Physics Unit 1 Electrostatics One Mark Question and Answer

Published on: 27/08/2019

Electrostatics

Download Tamil Nadu 12th Standard Physics question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.

Questions + Answers key

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QB365 Student Learing Managemnet System

Std: 12th Standard - Physics

chapter: - Model Question paper

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Questions:

Multiple Choice Question

4 x 1 = 4

The value of constant 'K' in coulomb law is _____________.

(a)

0.9 x 10⁹ Nm² C²

(b)

9 x 10^-9 Nm²C²

(c)

9 x 10⁹ Nm^-2 C^-2

(d)

9 x 10⁹ Nm² C^-2

An electric field \(\vec { E } =10x\hat { i } \) exists in a certain region of space. Then the potential difference V = V_o – V_A, where V_o is the potential at the origin and V_A is the potential at x = 2 m is _____.

(a)

10 V

(b)

-20 V

(c)

+20 V

(d)

-10 V

The total electric flux for the following closed surface which is kept inside water

(a)

\(\frac { 80q }{ { \varepsilon }_{ 0 } } \)

(b)

\(\frac { q }{ { 40\varepsilon }_{ 0 } } \)

(c)

\(\frac { q }{ { 80\varepsilon }_{ 0 } } \)

(d)

\(\frac { q }{ { 160\varepsilon }_{ 0 } } \)

An electric dipole is placed at an alignment angle of 30^o with an electric field of 2 x 10⁵ NC^-1. It experiences a torque equal to 8 N m. The charge on the dipole if the dipole length is 1 cm is

(a)

4 mC

(b)

8 mC

(c)

5 mC

(d)

7 mC

Match the following

5 x 1 = 5

permittivity of free space

Electrostatic Induction

Electrostatic shielding

Dielectric

Air

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Answers Key:

Multiple Choice Question

4 x 1 = 4

(d)
9 x 10⁹ Nm² C^-2

\(\vec {E}\) = 10x\(\hat{i},\) when x = 2 m
\(\vec {E}\) = 10 x 2 x \(\hat{i}\) = 20\(\hat{i}\)
Since, \(E=\frac{-dV}{dx}\therefore V=+20 V\)

\(Φ=\frac { q_{net} }{ { \varepsilon }_{ 0 } } \)
q_net = - q + q + 2q = 2q
Relative permittivity of water = 80
\(\therefore Φ=\frac { q }{{ \varepsilon }_{ r } { \varepsilon }_{ 0 } } \)
\(=\frac{2q}{{ 80 \times \varepsilon }_{ 0 }}=\frac{q}{{ 40 \varepsilon }_{ 0 }}\)