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Published on: 24/10/2025
Download CBSE Class 6th Standard CBSE Mathematics question papers, sample papers, important questions, and previous year solved papers in PDF format. Get free study materials, NCERT solutions, and exam preparation resources for Class 6th Standard CBSE Mathematics
Questions + Answers key
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1.
The cost of a bench is Rs.6291. Find the cost of 269 benches.
2.
For making 12 shirts of the same size, if 12 m 6 cm of cloth is needed. Then, how much cloth will be required for each such shirt?
3.
A garment factory produced 216315 shirts, 182736 trousers and 58,704 jackets in a year. What is the total production of all the three items in that year?
4.
A box contains 50 packets of biscuits, each weighing 120 g. How many such boxes can be loaded in a van, which cannot carry beyond 900 kg?
5.
Find the sum of greatest and the smallest six-digit numbers formed by digits 2,0,4, 7, 6, 3 using each digit only once.
6.
The distance between the park and the house of a student is 2 km 260 m. Every day he walks both ways between the parks and his house. Find the total distance covered by him in a week's time.
7.
The monthly fee for a student in a school is Rs.480. If there are 620 students in the school. Then, find the total monthly collection of fees.
8.
Read these numbers. Write them using placement boxes and then write their expanded forms.
(i) 475320 (ii) 9847215 (iii) 97645310 (iv) 30458094
(a) Which is the smallest number?
(b) Which is the greatest number?
(c) Arrange these numbers in ascending and descending orders.
9.
Read and expand the numbers wherever there are blanks.
| Number | Number name | Expansion |
| 3,00,000 | Three lakhs | 3 \(\times\) 1,00,000 |
| 3,50,000 | Three lakhs fifty thousands | 3 \(\times\) 1,00,000+ 5 \(\times\)10,000 |
| 3,53,500 | Three lakhs fifty three thousands five hundreds | 3 \(\times\) 1,00,000+ 5 \(\times\) 10,000 + 3 \(\times\) 1,000+ 5 \(\times\) 100 |
| 4,57,928 | ||
| 4,07,928 | ||
| 4,00,829 | ||
| 4,00,029 |
10.
Find the greatest and the smallest numbers. 6895, 23787, 24569, 24659.
1.
Rs.1692279
2.
m 5 cm
3.
According to the question,
A garment factory produced shirts = 216315
Produced trousers = 182736
Produced jackets = 58704
∴Total production of all the three items in that year
= Sum of all items
= 216315 + 182736 + 58704 = 457755
Hence, the total production of all the three items in that year is 457755.
4.
Given, total number of packets = 50
Weight of each packet = 120 g
Weight of a box = 50 \(\times\) 120 g = 6000 g= 6 kg [∵ 1000 g = 1 kg]
∴ Required number of boxes = \(\frac{900}{6}=150\)
5.
Given digits are 2, 0, 4, 7, 6, 3.
Using each digit only once,
The greatest six-digit number is 764320.
The smallest six-digit number is 203467.
Now, sum of these numbers
= 764320 + 203467 = 967787
6.
31 km 640 m
7.
Rs.297600
8.
After reading these numbers, we have
(i) 475320 Four lakhs seventy five thousands three hundred twenty.
(ii) 9847215 Ninety eight lakhs forty seven thousands two hundreds fifteen.
(iii) 97645310 Nine crores seventy six lakhs forty five thousands three hundreds ten.
(iv) 30458094 Three crores four lakhs fifty eight thousands ninety four.
The placement boxes is shown as below:
| Number | Crores | Ten lakhs | Lakhs | Ten thousands | Thousand | Hundreds | Tens | Ones |
| 475320 | - | - | 4 | 7 | 5 | 3 | 2 | 0 |
| 9847215 | - | 9 | 8 | 4 | 7 | 2 | 1 | 5 |
| 97645310 | 9 | 7 | 6 | 4 | 5 | 3 | 1 | 0 |
| 30458094 | 3 | 0 | 4 | 5 | 8 | 0 | 9 | 4 |
Expanded forms of given numbers are as follow:
(i) 475320 = 4 \(\times\)100000 + 7 \(\times\) 10000 + 5\(\times\) 1000 + 3 \(\times\) 100 +2\(\times\)10+ 0 \(\times\) 1
(ii) 9847215 = 9 \(\times\) 1000000 + 8 \(\times\) 100000 + 4 \(\times\) 10000 + 7 \(\times\) 1000 + 2 \(\times\) 100 + 1 \(\times\)10 + 5 \(\times\) 1
(iii) 97645310 = 9 \(\times\) 10000000 + 7 \(\times\) 1000000 + 6 \(\times\) 100000 + 4 \(\times\) 10000 + 5 \(\times\) 1000 + 3 \(\times\) 100 + 1 \(\times\) 10 + 0 \(\times\)1
(iv) 30458094 = 3\(\times\) 10000000 + 4 \(\times\) 100000 + 5 \(\times\) 10000 + 8 \(\times\) 1000 + 0 \(\times\) 100 + 9\(\times\) 10 + 4 \(\times\) 1
(a) The smallest number = 475320
(b) The greatest number = 97645310
(c) Ascending order of given numbers are as follow:
475320 < 9847215 < 30458094 < 97645310
Descending order of given numbers are as follow:
97645310> 30458094 > 9847215> 475320.
9.
The remaining blanks are shown as below with appropriate number, name and expansion
| Number | Number name | Expansion |
| 4,57,928 | Four lakhs fifty seven thousands nine hundreds twenty eigh | 4 \(\times\) 10,00,00 + 5 \(\times\) 10,000 + 7 \(\times\) 1,000+ 9 \(\times\) 100 + 2 \(\times\) 10 + 8 \(\times\)1 |
| 4,07,928 | Four lakhs seven thousands nine hundreds twenty eight | 4 \(\times\) 1,00,000+ 7 \(\times\) 1,000 + 9 \(\times\) 100 + 2 \(\times\) 10 + 8 \(\times\) 1 |
| 4,00,829 | Four lakhs eight hundreds twenty nine | 4 \(\times\) 1,00,000 + 8 \(\times\) 100 + 2 \(\times\) 10 + 9 \(\times\) 1 |
| 4,00,029 | Four lakhs twenty nine | 4 \(\times\) 1,00,000+ 2 \(\times\) 10 + 9 \(\times\) 1 |
10.
We have, 6895, 23787, 24569, 24659
Here, 6895 is a 4-digit number and other numbers are 5 digits, so it is clear that 6895 is the smallest number. Now, in remaining three numbers, the digit at ten thousands place is same in each number. So, we compare the thousands place digit.
∵ 4>3
Again, in two numbers, digit at thousands place is same. So, we compare the hundreds place digit.
∵ 6>5
∴ The greatest number is 24659 and smallest number is 6895.
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