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Published on: 24/10/2025
Download CBSE Class 6th Standard CBSE Mathematics question papers, sample papers, important questions, and previous year solved papers in PDF format. Get free study materials, NCERT solutions, and exam preparation resources for Class 6th Standard CBSE Mathematics
Questions + Answers key
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1.
The perimeter of a regular hexagon is 12 m. Find the length of the side.
2 m
3 m
4 m
6 m
2.
The perimeter of a regular pentagon is 10m. Find the length of the side.
1 m
2 m
5 m
10 m
3.
The perimeter of a square is 8 m. Find the length of the side.
1 m
2 m
4 m
8 m
4.
The perimeter of an equilateral triangle is 9 m. Find the length of the side.
1 m
2 m
3 m
9 m
5.
Find the distance travelled by Sangeeta if she takes 5 rounds of a square park of side 10 m.
200 m
100 m
400 m
800 m
6.
The perimeter of a regular hexagon of side 1m is
3 m
2 m
4 m
6 m
7.
The perimeter of a regular pentagon of side 1m is
5 m
10 m
15 m
20 m
8.
The perimeter of an equilateral triangle of side 1 m is
1 m
2 m
3 m
6 m
9.
The perimeter of a square of side 1 m is
1 cm
2 cm
3 cm
4 m
10.
Find the cost of fencing a rectangular park of length 10 m and breadth 5 m at the rate of Rs. 10 per metre.
Rs.300
Rs.600
Rs.150
Rs.1200
11.
An athlete takes 10 rounds of a rectangular park, 40 m long and 30 m wide. Find the total distance covered by him.
1400 m
700 m
70 m
2800 m
12.
Find the perimeter of a rectangle whose length and breadth are 9 em and 1 em respectively.
10 cm
20 cm
30 cm
40 cm
13.
Meenu wants to put a lace border all around a rectangular table cover 2 m long and 1m wide. Find the length of the lace required by Meenu.
3 m
4 m
5 m
6 m
14.
A page is 25 em long and 20 em wide. Find the perimeter of this page.
90cm
45 cm
500 cm
5 cm
15.
Apala went to a park 20 m long and 10 m wide. She took one complete round of it. The distance covered by her is
30 m
60 m
20 m
10 m
16.
Perimeter of a regular hexagon =
3 x Length of a side
4 x Length of a side
5 x Length of a side
6 x Length of a side.
17.
Perimeter of a regular pentagon =
4 x Length of a side
3 x Length of a side
6 x Length of a side
5 x Length of a side.
18.
Area of a square =
side x side
4x Length of a side
2 x Length of a side
6 x Length of a side.
19.
Area of a rectangle =
Length x Breadth
Length + Breadth
2 x (Length + Breadth)
2 x (Length x Breadth).
20.
Perimeter of an equilateral triangle =
2 x Length of a side
3 x Length of a side
4 x Length of a side
6 x Length of a side.
21.
Perimeter of a square=
4 x Length of a side
2 x Length of a side
3 x Length of a side
6 x Length of a side
22.
Perimeter of a rectangle =
Length x Breadth
Length + Breadth
2 x (Length + Breadth)
2 x (Length x Breadth)
23.
The top of a table is 1 m 20 cm wide and 1 m 50 cm long. The perimeter of this top is
5.30 m
5.40 m
5.50 m
5.60 m
24.
Cost of fencing a rectangular park of length 200 m and width 150 m at the rate of Rs.25 per metre is
Rs.17500
Rs.1750
Rs.1705
Rs.10750
25.
The perimeter of an equilateral triangle of side 5 cm each is
\(\frac { \sqrt { 3 } }{ 4 } \times 15cm\)
\(\frac { \sqrt { 3 } }{ 4 } \times 10cm\)
10 cm
15 cm
26.
The perimeter of a square, whose each side is 1m 30cm 10 mm, is
5.4 m
5.14 m
5.24 m
5.04 m
27.
The side of a square is 10 cm. How many times will the new perimeter become, if the side of the square is doubled?
2 times
4 times
6 times
8 times
28.
The perimeter of a rectangle, whose sides are 1m 30 cm and 70 cm, is
20 m
4 m
0.2 m
2 m 30 cm
29.
The perimeter of a triangle whose sides are 1.2cm, 3.4 cm and 1.7 cm, is
6.3 cm
6.2 m
6.5 cm
6.4 cm
30.
A square shaped park ABCD of side 100 m has two equal rectangular flower beds each of size 10m \(\times\) 5 m (see the figure). Length of the boundary of the remaining park is
360m
400 m
340 m
460 m
1.
Length of side =\(\frac{12}{6}\)=2 m
2.
Length of side =\(\frac{10}{5}\)=2 m
3.
Length of side =\(\frac{8}{4}\)=2 m
4.
Length of side = \(\frac{9}{3}\)=3 m
5.
Distance = 5 x 4 x 10 = 200 m
6.
Perimeter = 6 x 1 = 6 m
7.
Perimeter = 5 x 1 = 5 m
8.
Perimeter = 3 x 1 = 3 m
9.
Perimeter = 4 x 1 = 4 m
10.
Cost = 10 x 2 x (10 + 5) = Rs. 300
11.
Total distance covered = 10 x 2 x (40 + 30) = 1400 m
12.
Perimeter = 2(9 + 1) = 20 cm
13.
Length of the lace = 2(2 + 1) = 6 m
14.
Perimeter = 2(25 + 20) = 90 cm
15.
Distance covered = 2(20 + 10) = 60 m
16.
(d)
6 x Length of a side.
17.
(d)
5 x Length of a side.
18.
(a)
side x side
19.
(a)
Length x Breadth
20.
(b)
3 x Length of a side
21.
(a)
4 x Length of a side
22.
(c)
2 x (Length + Breadth)
23.
(b)
5.40 m
24.
(a)
Rs.17500
25.
(d)
15 cm
26.
(c)
5.24 m
27.
(a)
2 times
28.
(b)
4 m
29.
(a)
6.3 cm
30.
(b)
400 m
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