cbse 6th Standard Mathematics Mensuration Model Questions Papers Study Material - QB365 Set C | QB365

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cbse 6th Standard Mathematics Mensuration Model Questions Papers Study Material - QB365 Set C

Published on: 24/10/2025

Question Set C

cbse 6th Standard Mathematics Mensuration Model Questions Papers Study Material - QB365

Download CBSE Class 6th Standard CBSE Mathematics question papers, sample papers, important questions, and previous year solved papers in PDF format. Get free study materials, NCERT solutions, and exam preparation resources for Class 6th Standard CBSE Mathematics

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Std: 6th Standard CBSE - Mathematics

chapter: Mensuration - Model Questions Papers

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Questions:

Generic 2

7 x 2 = 14

Give five examples of situations where you need to know the perimeter.

Find the areas of the rectangles whose sides are 2 km and 3 km

A piece of wire is 12 cm long. What will be the length of each side, if the wire is used to form an equilateral triangle?

How many equilateral triangles of a side 2 cm long can be formed with a wooden strip of length 60 cm?

Find the perimeter of the following figures

Find the perimeter of the given figure

Generic 3

4 x 3 = 12

A piece of string is 30 cm long. What will be the length of each side, if the string is used to form a regular hexagon?

Find the perimeter of the following figures.

Perimeter = AB + BC + CD + DE + EF + FA
=__+__+__+__+__+__+__=__

10.

Measure and write the lengths of the four sides of a page of your notebook. The sum of the lengths of the four sides.
= AB + BC + CD + DA
=__cm+__cm+__cm+__cm=__cm
What is the perimeter of the page?

11.

An athlete takes 10 rounds of a rectangular field. which is 30 m long and 20 m wide. Find the total distance covered by him.

Generic 5

2 x 5 = 10

12.

By splitting the following figures into rectangles, find their areas (the measures are given in centimetres).

13.

Five square flower beds each of sides 1 m are dug on a piece of land 5 m long and 4 m wide. What is the area of the remaining part of the land?

Multiple Choice Question

5 x 1 = 5

14.

The perimeter of an equilateral triangle of side 1 m is

(a)

1 m

(b)

2 m

(c)

3 m

(d)

6 m

15.

Perimeter of a rectangle =

(a)

Length x Breadth

(b)

Length + Breadth

(c)

2 x (Length + Breadth)

(d)

2 x (Length x Breadth)

16.

The perimeter of an equilateral triangle of side 5 cm each is

(a)

\(\frac { \sqrt { 3 } }{ 4 } \times 15cm\)

(b)

\(\frac { \sqrt { 3 } }{ 4 } \times 10cm\)

(c)

10 cm

(d)

15 cm

17.

The side of a square is 10 cm. How many times will the new perimeter become, if the side of the square is doubled?

(a)

2 times

(b)

4 times

(c)

6 times

(d)

8 times

18.

Following figures are formed by joining six unit squares. Which figure has the smallest perimeter?

(a)

(ii)

(b)

(iii)

(c)

(iv)

(d)

(i)

Fill up / 1 Marks

4 x 1 = 4

19.

The perimeter of a square whose area is 64 m²is -----

20.

The area of a rectangular park whose length is 30 m and width is 20 m, is------

21.

Standard unit of area is ------

22.

The amount of region enclosed by a plane closed figure is called its --------

True or False

4 x 1 = 4

23.

A farmer who wants to fence his field, must find the perimeter of the field.

(a)

False

(b)

True

24.

Area of a square is doubled if the side of the square is doubled

(a)

True

(b)

False

25.

Perimeter of rectangle is (l + b).

(a)

True

(b)

False

26.

If the side of a square is doubled, then its area becomes four times.

(a)

False

(b)

True

Match the following

4 x 1 = 4

27.

28.

29.

30.

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Answers Key:

Generic 2

7 x 2 = 14

Ex. 1. Perimeter of the top of study table
Ex. 2. Perimeter of a park
Ex. 3. Perimeter of a page of our notebook
Ex. 4. Perimeter of a field
Ex. 5. Perimeter of a wall of a room

The area of the rectangle is 6 sq km.

4 cm

The perimeter of the given figure is 20 cm.

The perimeter of the given figure is 133 cm.

Perimeter of the figure ABCDEF = Sum of measurements of all sides
= AB + BC + CD + DE+ EF+ FA=100+120+90 + 45 +60+80 = 495 m

Generic 3

4 x 3 = 12

Here, length of string will be the perimeter of regular hexagon.
∴ Perimeter of regular hexagon = 30
We know that, a regular hexagon has 6 equal sides
Perimeter of a regular hexagon = 6 \(\times\) Length of a side
\(\therefore \quad Length\quad of\quad a\quad side=\frac { Perimeter\quad of\quad a\quad regular\quad hexagon }{ 6 } \)
\(=\frac { 30 }{ 6 } cm=5cm\)
Hence, the length of each side of a regular hexagon is 5cm.

The perimeter of the given figure is 495 m

10.

Let ABCD be the page of a notebook.
On measuring, AB = CD = 15 cm and BC = DA = 20 cm

Then, the sum of the lengths of four sides
= AB + BC + CD + DA
= 15 cm + 20 cm + 15 cm + 20 cm
= (I5 + 20 + 15 + 20) cm = 70 cm
Hence, the sum of the four sides is 70 em.
Now, perimeter of the page = Sum of the lengths of four sides
=70 cm

11.

Given, length of rectangular field (I) = 30 m
and breadth of rectangular field (b) = 20 m
Total distance covered by the athlete in one round = Perimeter of field (rectangle)
= 2 (I + b) = 2 (30 + 20) = 100 m
Since, the distance covered in one round = 100 m
So, the distance covered in 10 rounds = 10 \(\times\) 100 = 1000 m.

Generic 5

2 x 5 = 10

12.

Let the given figure is divided into rectangles A, Band C and their length and breadth are written on the figure.
For rectangle A,
Length = 2 cm and breadth = 1 cm
∴ Area of the rectangle A = Length \(\times\) Breadth
=2 \(\times\) 1=2 sq cm
For rectangle B,
Length = 5 ern and breadth = 1 cm

∴ Area of the rectangle B
= Length \(\times\) Breadth = 5 \(\times\)1 = 5 sq cm
For rectangle C,
Length = 2 cm and breadth = 1cm
∴ Area of the rectangle C = Length \(\times\) Breadth
=2 \(\times\) 1=2 sqcm
Now, total area of the given figure = Area of rectangle A + Area of rectangle B + Area of rectangle C
= (2 + 5 + 2) sq cm = 9 sq cm
Hence, the area of the given figure is 9 sq cm

13.

Given, length of the piece of land = 5 m
and breadth of the piece of land = 4 m
Area of the piece of land = Length \(\times\) Breadth
= 5 m \(\times\) 4 m= 20 sq m
Given, side of one square flower bed = 1m
∴ Area of one square flower bed = Side \(\times\) Side
= (1m \(\times\) 1rn) = 1sq m
Then, area of 5 such flower beds = 5 \(\times\) Area of one square flower bed
= 5 \(\times\) 1sq m = 5 sq m
Now, area of the remaining part of land
= Area of the piece of land - Area of 5 square flower beds
= (20 - 5)sq m =15 sq m
Hence, the area of the remaining part of the land is 15 sq m.

Multiple Choice Question

5 x 1 = 5

14.

Perimeter = 3 x 1 = 3 m

15.

16.

(d)
15 cm

17.

(a)
2 times

18.

(d)
(i)

Fill up / 1 Marks

4 x 1 = 4

19.

Area of a square = Side \(\times\) Side⇒64= Side \(\times\) Side
⇒8\(\times\) 8= Side\(\times\)Side ⇒ Side = 8m
Perimeter = 4\(\times\)ide= 4\(\times\)8 =32 m

20.

Area of rectangular park = I x b = 30 x 20 = 600 sq m.

21.

We know that, standard unit of area is cm²or m².

22.

The region enclosed by a plane closed figure is called its area.

True or False

4 x 1 = 4

23.