14560 is also divisible by 4.
14560 is also divisible by 8.

12159 is not divisible by 4.
12159 is not divisible by 8.

Here, we have 79152.
The number formed by the last three digits is 152.
152 is divisible by 8.
Hence, 79152 is divisible by 8.

37 + 7

47 + 2

0

2

We have, 31 \(\Rightarrow\) 31= 3+5+23
where 3, 5 and 23 are odd prime numbers.

We have, 21 \(\Rightarrow\) 21 = 3 + 5 + 13
where 3, 5 and 13 are odd prime numbers.

All prime numbers upto 100 are 2,3,5,7,11,13,17,19, 23,29,31,37,41,43,47,53,59,6.1,67,71,73,79,83, 89 and 97. Out of these prime numbers, pairs of prime numbers having same digits are
(i) 13,31 (ii) 17,71 (iii) 37,73 (iv) 79, 97
Hence, there are 4 pairs of such types.

Let the two even numbers be 4 and 8.
Their sum = 4 +8 = 12 (even number)
Taking one more example.
Let the two even numbers be 6 and 20.
Their sum = 6 + 20 = 26 (even number)
Hence, we can say that the sum of any two even numbers is an even number.

Yes

Yes

Multiples of 9 upto 100 are as follows:
9 x 1= 9
9 x 2 = 18
9 x 3 = 27
9 x 4 = 36
9 x 5 = 45
9 x 6 = 54
9 x 7 = 63
9 x 8 = 72
9 x 9 = 81
Hence, all the multiples of 9 upto 100 are 9,18,27,36,45, 54, 63, 72, 81, 90 and 99.

Multiples of 9,
9 x 1= 9; 9 x 2 = 18; 9 x 3 = 27; 9 x 4 = 36 ; 9 x 5 = 45
\(\therefore\) First five multiples of 9 are 9, 18, 27, 36 and 45.