Candidate’s EMIS No 

1

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1

1. Name of the candidate in Capital Letters followed by initial leaving one box blank. (Do not write Miss/Master)

R

A

N

J

I

T

H

A

3. Father’s name in Capital Letters followed by initial leaving one box blank. (Do not write Mr./Dr./Prof)

G

U

R

U

4. Mother’s Name in Capital Letters followed by initial leaving one box blank. (Do not write Mrs./Dr./Prof)

U

M

A

 

A - Anu
B - Bakiya
C- Chandru
D - Divya
E - Elakiya
F - Farook
G - Ganesh
H - Hema
I - Irin
J - James
K - Kala
L - Lalli
M - Maha
N - Nandhini
O - Ophiliya
P - Prabha
Q - Qasim
R - Raja
S - Srija
T - Teju
U - Uma
V - vikki
W - William
X - Xavier
Y - Yash
Z - Zamira

1. Fill the date of withdrawal.
2. Fill the account number is the proper place.
3. Fill the branch of bank
4. Fill the Name of the account holder.
5. Fill the amounf to be withdrawn in words.
6. Fill the amount to be withdrawn in numbers.
7. Put the signature ofthe account holder.

Given numbers are 48 and 28
HCF of 48 and 28
\(\Rightarrow\) (48, 48 - 28)
48 \(\rightarrow\) 2 \(\times\) 2 \(\times\) 2 \(\times\) 2 \(\times\) 3
20 \(\rightarrow\) 2 \(\times\) 2 \(\times\) 5
HCF = 2 \(\times\) 2 = 4
Also find : HCF of 48 and 4
48 \(\rightarrow\) 2 \(\times\) 2 \(\times\) 2 \(\times\) 2 \(\times\) 3
4 \(\rightarrow\) 2 \(\times\) 2
HCF=2 \(\times\) 2 = 4
Difference = 4 - 4 = 0 [same HCF]

(i) By Euclid's game
Given numbers = 25 and 35
HCF\(\Rightarrow\)(25, 35) = HCF(25, 35 - 25)
= (25, 10)
= (25 - 10, 10) = (15, 10)
= (5, 10)
= (5, 10 - 5)
= (5, 5)
(ii) By Euclid's game
Given numbers = 36 and 12
HCF of 36 and and 12 \(\Rightarrow\)(36, 12)
\(\Rightarrow\) (36 -12, 12)
\(\Rightarrow\)(24, 12)
\(\Rightarrow\)(24 - 12, 12)
\(\Rightarrow\)(12, 12)
\(\therefore\) HCF = 12.
(iii) 
Given numbers are 15 and 29
By Euclid's game:
HCF of 15 and 29 is
\(\Rightarrow\)(15, 29)
\(\Rightarrow\)(15, 29 - 15)
\(\Rightarrow\)(15, 14)
\(\Rightarrow\)(15 - 14, 14)
\(\Rightarrow\)(1, 14)\(\Rightarrow\) (1, 14 - 1) \(\Rightarrow\)(1, 13)
\(\Rightarrow\)(1, 13 -1) \(\Rightarrow\)(1, 12) \(\Rightarrow\)(1, 12 -1), (1, 11) (1, 1)
\(\therefore\) HCF = 1

Fibonaxxi sequence 1,1,2,3,5,8,13,21,34,55

Steps	Pattern 1	Pattern 2
i)	1+3 = 4	5 -1 =4
ii)	1+3+8= 12	13--1
iii)	1+3+8+21 = 33	34-1
iv)	1+3+8+21+55=88	89-1

(i) 50, 51, 53, 56, 60 
The next three numbers will be 65, 71, 78 .......
(ii) 77, 69, 61, 53 
The next three numbers will be 45, 37, 29 .....
(iii) 10, 20, 40, 80
The next three numbers will be 160, 320, 640 .....
(iv) \(\cfrac { 21 }{ 33 } ,\cfrac { 321 }{ 444 } ,\cfrac { 4321 }{ 5555 } \)
The next three numbers will be \(\cfrac { 54321 }{ 66666 } ,\cfrac { 654321 }{ 777777 } ,\cfrac { 7654321 }{ 888888 } ,\)

(i) 1 \(\times\) 1 = 1
11 \(\times\) 11 = 121
111 \(\times\) 111 = 12321
1111 \(\times\) 1111 = 1234321
11111 \(\times\) 11111 = 123454321
(ii)