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Published on: 31/07/2018
In Decimals contains important questions in CBSE 6th Standard Mathematics. It also covered with the most important questions in Decimals.
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Questions + Answers key
Take MCQ Mathematics Test
1.
Simplify 714.2 + 42.29 - 414.205 - 2.999
2.
Find 0.29 + 0.36
3.
Write 2 rupees 5 paise and 2 rupees 50 paise in decimals.
4.
Which is greater? 2.09 or 2.19
5.
Write 407.2 in expanded form.
6.
Seema has Rs 2000, she bought readymade garments for Rs 987.50, medicines for Rs 210.25, groceries for Rs 530.25. She donated Rs 200 for charity.
(a) How much money is left with her?
(b) Mention the value you depict form this.
7.
Ravi purchased 5 kg 400 g rice, 2 kg 20 g sugar and 10 kg 850 g flour. Find the total weight of his purchases.
8.
Anil got Rs 1000 as pocket money. He spent Rs 439.74 in playing games and Rs 246.40 in food. How mush did he save?
9.
Subtract the sum of 71.47 and 47.71 from the sum of 97.79 and 46.2, then find the value.
10.
What should be subtracted from 117.47 to get 47.95?
11.
During three days of a week, a rickshaw puller earns Rs 40.20, rs 60.10 and Rs 55, respectively. What is his total earning during these days?
12.
Simplify 53.5 - 34.68 + 64.75 - 28.9.
13.
\(19+\frac { 5 }{ 10 } +\frac { 7 }{ 100 } \) in decimal form is written as
19.75
19.057
19.705
19.57
14.
Lowest form of decimal 0.005 is
\(\frac { 3 }{ 1000 } \)
\(\frac { 1 }{ 200 } \)
\(\frac { 2 }{ 200 } \)
\(\frac { 5 }{ 100 } \)
15.
15.8 - 6.73 is equal to
8.07
9.07
9.13
9.25
16.
23.564 correct to the tenths place is
21
23.55
23.6
23.76
17.
0.023 lies between
0.2 and 0.3
0.02 and 0.03
0.03 and 0.029
0.026 and 0.024
18.
9 cm 8 mm = _______________ cm
19.
Fraction \(\frac { 7 }{ 25 } \) is equal to the decimal number ________________
20.
\(9+\frac { 2 }{ 10 } +\frac { 6 }{ 100 } \) is equal to the decimal number _____________
21.
3 Hundredths + 2 tenths = _____________
22.
2 km 590 m is equal to __________ km
23.
13 rupees 30 paise = Rs 13.03
24.
2 kg 52 g is equal to 2.052 g.
25.
180 m 28 cm = 180.028 m
26.
The place value of a digit at the tenths place is 1/10 times the same digit at ones place.
27.
In the decimal form, fraction \(\frac { 25 }{ 8 } =3.125\)
1.
339.286
2.
We have, 0.29+0.36
\(\quad Ones\quad Tenths\quad Hundreadths\\ \quad \quad 0\quad \quad \quad \quad 2\quad \quad \quad \quad \quad 0\\+\quad 0\quad \quad \quad \quad 3\quad \quad \quad \quad \quad 6\\\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\\ \quad \quad0\quad\quad\quad\quad6\quad\quad\quad\quad\quad5\\\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\_\)
\(\therefore\) 0.29+0.36=0.65
3.
We have, 2 rupees 5 paise = Rs 2+ 5 paise
=Rs 2 + Rs \(\left( 5\times \frac { 1 }{ 100 } \right) \) = Rs (2+0.50) = Rs 2.50
4.
\(2.09=2+\frac { 0 }{ 10 } +\frac { 9 }{ 100 } ,2.19=2+\frac { 1 }{ 10 } +\frac { 9 }{ 100 } \)
Compare the whole part of 2.09 and 2.19 we get 2 = 2
So, compare the tenths part, we get 0 < 1
Hence, 2.19 > 2.09
5.
\(400+00+7+\frac { 2 }{ 10 } \)
6.
(a) Total money that Seem a has = Rs 2000.
Cost of readymade garments = Rs 987.50
Cost of medicines = Rs 210.25
Cost of groceries = + Rs 530.25
__________
Total cost = Rs 1728.00
___________
Money donate for charity = Rs 200
=Rs 1728.00
Total money spent = + Rs 200
____________
Rs 1928
____________
Money she had = Rs 2000
Spent money = - Rs 1928
_________
Balance = Rs 072
_________
So, Rs 72 are left with her.
(b) Humanity, helpfulness.
7.
Weight of rice purchased by Ravi
= 5 kg 400 g = 5 kg + 400 g
\(= 5 kg+ 400\times{1\over 1000}kg\) \(\begin{bmatrix} \because 1\ g={1\over 1000} kg\end{bmatrix}\)
\(=5\ kg+{400\over1000}\)kg = (5+ 0.400) kg = 5.400 kg
Weight of sugar purchased by Ravi
= 2 kg 20 g = 2 kg+ 20 g
\(= 2 kg+ 20\times{1\over1000}kg\) \(\begin{bmatrix} \because 1\ g={1\over 1000} kg\end{bmatrix}\)
\(=2\ kg+{20\over1000}kg\) = (2+ 0.020) kg = 2.020 kg
Weight of flour purchased by Ravi
= 10 kg 850 g = 10 kg + 850 g
\(=10\ kg+850\times{1\over 1000}kg\) \(\begin{bmatrix} \because 1\ g={1\over 1000} kg\end{bmatrix}\)
\(=10\ kg+{850\over1000}kg\) (10 + 0.850) kg = 10.850 kg
\(\therefore\) Total weight of his purchases
\(\quad5.400\\\quad2.020\\+10.850\\\_\_\_\_\_\_\_\_\\\ \ 18.270\\\_\_\_\_\_\_\_\_\)
Hence, the total weight of all his purchases is 18.270 kg.
8.
Rs 313.86
9.
24.81
10.
To get the required number, we have
117.47 - 47.95 = 69.52
11.
| Earning om 1st day | = | Rs 40.20 |
| Earning om 2 nd day | = | Rs 60.10 |
| Earning on 3rd day | = | +Rs 55.00 |
| \(\therefore\) Total earning | = | Rs 155.30 |
12.
Converting the given decimals into like decimals
we get
53.5 - 34.68 + 64.75 - 28.9
= (53.50 + 64.75)-(34.68 + 28.90)
= 118.25 - 63.58
= 54.67
13.
(d)
19.57
14.
(b)
\(\frac { 1 }{ 200 } \)
15.
(b)
9.07
16.
(c)
23.6
17.
(b)
0.02 and 0.03
18.
( )
9.8 cm
19.
( )
0.28
20.
( )
9.26
21.
( )
0.23
22.
( )
2.590 km
23.
(b)
24.
(b)
25.
(b)
26.
(a)
27.
(a)
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