2nd Term Model SA Question

Download Tamil Nadu 6th Standard Maths question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.

Questions:

Fill in the blanks

5 x 1 = 5

In an isosceles triangle ______________ angles are equal.

250 ml + ½ l = _______________ l

The least number that should be added to 57 so that the sum is exactly divisible by 2, 3, 4 and 5 is ______________

The sum of distinct prime factors of 30 is_______.

3753 is divisible by 9 and hence divisible by _________ .

Multiple Choice Question

5 x 1 = 5

If two sides of a triangle are 5 cm and 9 cm, then the third side is ______________

(a)

5 cm

(b)

3 cm

(c)

4 cm

(d)

14 cm

Discount is subtracted from ____________ to get S.P.

(a)

M.P.

(b)

C.P.

(c)

Loss

(d)

Profit

What time will it be 5 hours after 22:35 hours?

(a)

2:30 hours

(b)

3:35 hours

(c)

4:35 hours

(d)

5:35 hours

If the number 6354 * 97 is divisible by 9, then the value * is

(a)

(b)

(c)

(d)

10.

The difference between two successive odd numbers is

(a)

(b)

(c)

(d)

Generic 2

6 x 2 = 12

11.

Is a triangle possible with the angles 90°, 90° and 0°? Why?

12.

A fruit seller bought a basket of fruits for Rs. 500. During the transit some fruits were damaged. So, he was able to sell the remaining fruits for Rs. 480. Find the profit or loss in his business.

13.

A calf drinks 5.750 l of water, convert into ml

14.

The average rainfall of Tamilnadu is 998 mm. convert it into cm.

15.

The traffic lights at three different road junctions change after every 40 seconds, 60 seconds and 72 seconds respectively. If they changed simultaneously together at 8 a.m at the junctions, at what time will they simultaneously change together again?

16.

Find the HCF of each set of numbers using prime factorisation method.
(i) 18, 24 (ii) 51, 85 (iii) 61, 76 (iv) 84, 120 (v) 27, 45, 81 (vi) 45, 55, 95

Generic 3

9 x 3 = 27

17.

Convert the tree diagram into an algebraic expression.

18.

Convert '3a+b' into Tree diagram

19.

Draw a line segment measuring 7.8 cm. Mark a point B above it at a distance of 5 cm. Through B draw a line parallel to the given line segment.

20.

Draw a line segment AB = 7 cm and mark a point P on it. Draw a line perpendicular to the given line segment at P.

21.

A table is bought for Rs. 4500 and sold for Rs. 4800. Find the profit or loss.

22.

Convert the following:
(i) 20 minutes into seconds
(ii) 5 hours 35 minutes 40 seconds into seconds
(iii) 3 ½ hours into minutes
(iv) 580 minutes into hours
(v) 25200 seconds into hours

23.

Convert into lower units:
(i) 15 km (m, cm, mm)
(ii) 12 kg (g, mg)

24.

Find the smallest number that can be divided by 254 and 508 which leaves the remainder 4.

25.

Find the HCF of the numbers 40 and 56 by division method.

Generic 5

8 x 5 = 40

26.

Convert the following questions into tree diagrams:
(i) The number of people who visited a library in the last 5 months were 1210, 2100, 2550, 3160 and 3310. Draw the tree diagram of the total number of people who had used the library for the 5 months.
(ii) Ram had a bank deposit of Rs. 7,55,250 and he had withdrawn Rs. 5,34,500 for educational purpose. Find the amount left in his account. Draw a tree diagram for this.
(iii) In a cycle factory, 1,600 bicycles were manufactured on a day. Draw tree diagram to find the number of bicycles produced in 20 days.
(iv) A company with 30 employees decided to distribute Rs. 90,000 as a special bonus equally among its employees. Draw tree diagram to show how much will each receive?

27.

Study the given figure and identify the following triangles.
(a) equilateral triangle
(b) isosceles triangles
(c) scalene triangles
(d) acute triangles
(e) obtuse triangles
(f) right triangles

28.

Draw a line and mark a point R at a distance of 4.8 cm above the line. Through R draw a line parallel to the given line.

29.

Construct a line perpendicular to the given line through a point above it.

30.

Can a triangle be formed with the following sides? If yes, name the type of triangle.
(i) 8 cm, 6 cm, 4 cm
(ii) 10 cm, 8 cm, 5 cm
(iii) 6.2 cm, 1.3 cm, 3.5 cm
(iv) 6 cm, 6 cm, 4 cm
(v) 3.5 cm, 3.5 cm, 3.5 cm
(vi) 9 cm, 4 cm, 5 cm

31.

Prepare a bill for the following purchases at Aavin sales counter in Coimbatore on 25-06-2018 bearing the Bill number 160.
1. 5 packets Milk Khoa of 100 gm @ Rs. 40 each
2. 5 packets of Butter Milk @ Rs. 8 each
3. 6 packets Milk of 500ml @ Rs. 25 each
4. 5 packets Ghee of 100gm @ Rs. 40 each

32.

Find the duration between 6 a.m and 4 p.m

33.

There are four Mobile Phones in a house. At 5 a.m, all the four Mobile Phones will ring together. Thereafter, the first one rings every 15 minutes, the second one rings every 20 minutes, the third one rings every 25 minutes and the fourth one rings every 30 minutes. At what time, will the four Mobile Phones ring together again?

True or False

5 x 1 = 5

34.

Vanmathi bought 4 books each weighing 500 g. Total weight of 4 books is 2 kg.

(a)

True

(b)

False

35.

Pugazhenthi ate 100 g of nuts which is equal to 0.1 kg.

(a)

True

(b)

False

36.

The LCM of two successive numbers is the product of the numbers

(a)

True

(b)

False

37.

The HCF of 17 and 18 is 1

(a)

True

(b)

False

38.

If a number is divisible by 6, then it must be divisible by 3.

(a)

True

(b)

False

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Answers Key:

Fill in the blanks

5 x 1 = 5

()
two

()
\(\frac{3}{4}\) l

()
10

()
3

Multiple Choice Question

5 x 1 = 5

(a)
5 cm

(a)
M.P.

(b)
3:35 hours

(a)
2

10.

(b)
2

Generic 2

6 x 2 = 12

11.

No, It is not possible with angles 90°, 90°, 0°.
Because there cannot be two right angles in a triangle

12.

C.P. = Rs. 500
S.P. = Rs. 480
Here, C.P. > S.P. \(\Rightarrow\) Loss = C.P. - S.P. = Rs. 500 - Rs. 480 = Rs. 20

13.

Quantity of water drunk by the calf = 5.750 l 1l = 1000 ml

= 5750 ml

14.

The average rainfall = 998 mm = 998.0 \(\times \frac { 1 }{ 10 } \) cm

1 cm = 10 mm
\(\frac { 1 }{ 10 } \)cm = 1 mm
= 99.8 cm

15.

Given: 40 seconds, 60 seconds and 72 seconds

LCM = \(2 \times 2 \times 5 \times 2 \times 3 \times 3\) = 360 seconds
Also given, they changed simultaneously together at 8 a.m.
Therefore 360 seconds = 6 min
⇒ 1 hour = 60 min
Therefore 8 a.m. + 6 min = 8.00 + 0.06
Time = 8.06 a.m.
After 360 seconds, therefore 8.06 a.m. will they simultaneously change together again.

16.

i) 18, 24

Therefore HCF = 2 \(\times\) 3 = 6
ii) 51, 85

Therefore HCF = 17
iii) 61, 76

Therefore HCF = 1
iv) 84, 120

Therefore HCF = 3 \(\times\) 2 \(\times\) 2 = 12
v) 27, 45, 81

Therefore HCF = 3 \(\times\) 3 = 9
vi) 45, 55, 95

Therefore HCF = 5

Generic 3

9 x 3 = 27

17.

Tree diagram

Algebraic expression
8b \(\div \) 6

18.

Tree diagram

Algebraic expression
3a + b

19.

Construction:
1. Draw a line segment XY = 7.8 cm. Mark a point A on the line.
2. Place the set square on XY. Mark a point B above XY such that AB = 5 cm.
3. Using a scale and set square draw a line BC through B.
4. The line BC is parallel to XY. That is BC || XY.

20.

Given AB = 7 cm

Construction:
1. Draw a line segment AB =7 cm and take a point P anywhere on the line.
2. Place the set square on the line AB.
3. Draw a line PQ through P.
4. The line PQ is perpendicular to the line AB at P. That is PQ f \(\perp\) AB

21.

C.P. = Rs. 4500
S.P. = Rs. 4800
Here, C.P. < S.P. \(\Rightarrow\) Profit = S.P. - C.P.
= Rs. 4800 - Rs. 4500 = Rs. 300

22.

(i) 20 minutes into seconds
1 min = 60 seconds
Therefore 20 min = 60 \(\times\) 20 = 1200 seconds
(ii) 5 hours 35 minutes 40 seconds into seconds.
1 hour = 3600 seconds
5 hour = 5 \(\times\) 3600 = 18000 sec.
1 min = 60 see
35 min = 35 \(\times\) 60 = 2100 see
Therefore 5 hours 35 minutes 40 seconds
= (18000 + 2100 + 40) sec
= 20140 seconds
(iii) 3 1/2 hours into minutes
1 hour = 60 min
7 1/2 hours = 60 \(\times\) 7/2 = 210 minutes
(iv) 580 minutes into hours
60 min = 1 hour
580 min = 1/60 \(\times\) 580
= 58/6 = 9 4/6
= 9 hours 40 min (4 / 6 = 40 min)
(v) 25200 seconds into hours.
3600 sec = 1 hour
25200 sec = 1 /3600 \(\times\) 25200 = 252 / 36 = 7 hours

23.

15 km (m, cm, mm)
1 km = 1000 m
1 m = 100 cm
1 cm= 10mm
* 1 km = 1000 m
15 km = 15 \(\times\) 1000 m
= 15000 m
* 1 m = 100 m
15000 m = 15000 \(\times\) 100
= 150000 cm
* 1 cm = 10 mm
Therefore 1500000 em = 10 \(\times\) 1500000
= 15000000 mm
Ans : 15 km = 15000 m, 1500000 cm, 15000000mm
(ii) 12kg (g, mg)
1000 g = 1 kg
1000mg = 1 g
* 1000g = 1 kg
12kg = 12 \(\times\) (1000) g
= 12000 g
* 1g = 1000mg
12000 g = 12000 \(\times\) 1000 mg
= 12000000 mg

24.

All common multiples of 254 and 508 will be divisible by both the numbers. Let us find the LCM of 254 and 508 (by division method).
LCM of 254, 508 = 2 \(\times\) 2 \(\times\) 127 = 508
Thus, 508 is the smallest common number that is divisible by 254 and 508. Now, as we need remainder 4 while dividing, the required number is 4 more than the LCM and so, the required number is 508 + 4 =512.

25.

The product of common factors of 40 and 56
= 2 \(\times\) 2 \(\times\) 2 = 8 and so, HCF (40, 56) = 8
Dividing by the common factor 2, (in 3 steps)
HCF = Product of common factors
= 2 \(\times\) 2 \(\times\) 2 = 8

Generic 5

8 x 5 = 40

26.

(i) Given
1^st month = 1210
2^nd month = 2100
3^rdmonth = 2550
4^th month = 3160
5^thmonth = 3310
Tree diagram

Total = 1210 + 2100 + 2550 + 3160 + 3310.
ii) Given
Ram had a bank deposit = Rs. 7,55,250
He had withdrawn = Rs. 5,34,500
Therefore the amount left in his amount
= Rs. 7,55,250 - Rs. 5,34,500
Tree diagram

iii) Given
No. of bicycles produced in 1 day = 1,600
No. of bicycles produced in 20 days
= 1600 \(\times\) 20
Tree Diagram

iv) Given
Total amount = Rs. 90,000
No. of employees = 30
= 90,000 / 30
Tree Diagram

27.

(a) Equilateral Triangle :
ABC (AB = BC = CA = 4 cm)
(b) Isoceles Triangles :
ABC,AEF
(c) Scalene Triangles :
AEB, AED, ADF, AFC, ABD, ADC, ABF, AEC
(d) Acute Triangles :
ABC, AEF, ABF, AEC
(e) Obtuse Triangles :
AEB, AFC
(f) Right Triangles :
ADB, ADC, ADE, ADF

28.

Step 1: Using a scale draw a line AB and mark a point Q on the line.
Step 2: Place the set square in such a way that the vertex of the right angle coincides with Q and one of the edges of right angle lies along AB. Mark the point R such that QR = 4.8 cm.
Step 3: Place the scale and the set square as shown in the figure.
Step 4: Hold the scale firmly and slide the set square along the edge of the scale until the other edge touches the point R. Draw a line RS through R.
Step 5: The line RS is parallel to AB. That is, RS ║AB.

29.

Step 1: Draw a line PQ. Take a point X anywhere above the line PQ.
Step 2: Place one of the arms of the right angle of a set square along the line PQ and the other arm of its right angle touches the point X.
Step 3: Draw a line through the point X meeting PQ at Y.
Step 4: The line XY is perpendicular to the line PQ at Y. That is, XY \(\bot \) PQ

30.

(i) 8 cm, 6 cm, 4 cm
The sum of two smaller sides
= 6 cm + 4 cm = 10 cm > 8 cm, the third side.
It is greater than the third side
So, yes a triangle can be formed.
Type: Scalene triangle.
(ii) 10 cm, 8 cm, 5 cm.
The sum of two smaller sides
= 8 cm + 5 cm = 13 cm > 10 cm, the third side.
It is greater than the third side.
Therefore, yes a triangle can be formed.
Type: Scalene triangle.
(iii) 6.2 cm, 1.3 cm, 3.5 cm.
The sum oftwo smaller sides
= (1.3 + 3.5) cm = 4.8 cm < 6.2 cm It is
lesser than the third side.
Therefore, no a triangle cannot be formed.
(iv) 6 cm, 6 cm, 4 cm.
The sum of two smaller sides
= 6 cm + 4 crn = 10 cm > 6 cm, the third side.
It is greater than the third side.
Therefore, yes a triangle can be formed
Type: Isoceles triangle.
(v) 3.5 cm, 3.5 cm, 3.5 cm
The sum of two smaller sides = (3.5 + 3.5) cm = 7 cm > 3.5 cm
Therefore, it s greater than the third side.
Yes a triangle can be formed.
Type: Equilateral triangle
(vi) 9 cm, 4 cm, 5 cm
The sum of two smaller sides = 4 cm + 5 cm = 9 cm = 9 cm
Therefore, it s equal to the third side.
No, a triangle cannot be formed.

31.

1.	Milk Khoa \(\Rightarrow\) 5 \(\times\) Rs. 40	= Rs. 200
2.	Butter Milk \(\Rightarrow\) 5 \(\times\) Rs. 8	= Rs. 40
3.	Milk \(\Rightarrow\) 6 \(\times\) Rs. 25	= Rs. 150
4.	Ghee \(\Rightarrow\) 5 \(\times\) Rs 40	= Rs. 200
	Total	= Rs. 590

CASH BILL AAVIN PARLOUR, COIMBATORE
Bill No. 160 Date : 25.06.2018
Sl. No.	Items	Rate (in Rs.)	Quantity (packets)	Amount (in Rs.)
1.	Milk Khoa	40/packet	5	200
2.	Butter milk	8/packet	5	40
3.	Milk	25/packet	6	150
4.	Ghee	40/packet	5	200
	Total			590

32.

Method-1	Method-2
Conversion of 6 a.m to Railway time = 06:00 hours Conversion of 4 p.m to Railway time = (4+12) hours = 16:00 hours Time duration between 6 a.m and 4 p.m = The difference between 16 hours and 6 hours = 16 hours - 6 hours = 10 hours	= 6 hours + 4 hours = 10 hours

33.

This is a LCM related sum. So, we need to find the LCM of 15, 20, 25 and 30.

The LCM of 15, 20, 25 and 30 is 2 \(\times\) 2 \(\times\) 3 \(\times\) 5 \(\times\) 5
= 300 minutes = 5 \(\times\) 60 minutes = 5 \(\times\) 1 hour = 5 hours
Thus, the four Mobile Phones will ring together again at 10.00 a.m.