6th Standard Syllabus & Materials
6th Standard
Tamilnadu 6th Standard Tamil இயல் 3 - எல்லாரும் இன்புற - பெயர்ச்சொல் Important Questions And Answers Study Material - QB365 Set B
NEW6th Standard
Tamilnadu 6th Standard Tamil இயல் 3 - எல்லாரும் இன்புற - பெயர்ச்சொல் Important Questions And Answers Study Material - QB365 Set A
NEW6th Standard
Tamilnadu 6th Standard Tamil இயல் 2 - கூடித் தொழில் செய் - சுட்டு எழுத்துகள், வினா எழுத்துகள் Important Questions And Answers Study Material - QB365 Set B
NEW6th Standard
Tamilnadu 6th Standard Tamil இயல் 2 - கூடித் தொழில் செய் - சுட்டு எழுத்துகள், வினா எழுத்துகள் Important Questions And Answers Study Material - QB365 Set A
NEW6th Standard
Tamilnadu 6th Standard Tamil பருவம் 1 - இயல் 1 - மொழி -தமிழ்த்தேன் - இன்பத்தமிழ் Important Questions And Answers Study Material - QB365
NEW6th Standard
Tamilnadu 6th Standard Social Science T3 - குடிமையியல் - உள்ளாட்சி அமைப்பு - ஊரகமும் நகர்ப்புறமும் Important Questions And Answers Study Material - QB365 Set B
Published on: 04/10/2019
Term 2 Geometry
Download Tamil Nadu 6th Standard Maths question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Maths Test1.
Draw a line segment measuring 7.8 cm. Mark a point B above it at a distance of 5 cm. Through B draw a line parallel to the given line segment.
2.
Find the distance between the given lines using a set square at two different points on each of the pairs of lines and check whether they are parallel.
3.
Draw a line segment AB = 7 cm and mark a point P on it. Draw a line perpendicular to the given line segment at P.
4.
Can a triangle be formed with the angles 80°, 30°, 40°?
5.
Can a triangle be formed with 7 cm, 7 cm and 7 cm as its sides?
6.
Complete the following table :
| Types of Triangle /Its Angles | Acute angled triangle | Right angled triangle | Obtuse angled triangle |
| Any two angles | Always acute angles | i. | Always acute angles |
| Third angle | ii. | Right angle | iii. |
7.
Draw a line segment PQ = 12 cm. Mark two points M, N at a distance of 5 cm above the line segment PQ. Through M and N draw a line parallel to PQ.
8.
Draw a line and mark a point R at a distance of 4.8 cm above the line. Through R draw a line parallel to the given line.
9.
Draw a line segment AB = 6.5 cm and mark a point M above it. Through M draw a line parallel to AB.
10.
Two angles of the triangles are given. Find the third angle.
(i) 80°, 60°
(ii) 75°, 35°
(iii) 52°, 68°
(iv) 50°, 90°
(v) 120°, 30°
(vi) 55°, 85°
1.
Construction:
1. Draw a line segment XY = 7.8 cm. Mark a point A on the line.
2. Place the set square on XY. Mark a point B above XY such that AB = 5 cm.
3. Using a scale and set square draw a line BC through B.
4. The line BC is parallel to XY. That is BC || XY.
2.
Let
l || m and P || Q
Distance between the lines are 1cm.
Each of the pairs of lines are same distance.
3.
Given AB = 7 cm
Construction:
1. Draw a line segment AB =7 cm and take a point P anywhere on the line.
2. Place the set square on the line AB.
3. Draw a line PQ through P.
4. The line PQ is perpendicular to the line AB at P. That is PQ f \(\perp\) AB
4.
The sum of three angles = 80°+ 30°+ 40° = 150° (not equal to 180°)
In a triangle, the sum of three angles is 180°.
So, a triangle cannot be formed with the given angles.
5.
If three sides are equal, then definitely a triangle can be formed, as the triangle inequality is satisfied.
6.
| Types of Triangle /Its Angles | Acute angled triangle | Right angled triangle | Obtuse angled triangle |
| Any two angles | Always acute angles | i. Always acute angles | Always acute angles |
| Third angle | ii. acute angle | Right angle | iii. Obtuse angle |
7.
| Step 1: Using a scale, draw a line segment PQ = 12 cm. Mark two points A and B on the line segment. |  |
| Step 2: Using the set square as shown, mark points M and N such that AM = BN = 5 cm. |  |
| Step 3: Using the scale, join M and N. MN is parallel to PQ. That is, MN ║ PQ. |  |
8.
| Step 1: Using a scale draw a line AB and mark a point Q on the line. |  |
| Step 2: Place the set square in such a way that the vertex of the right angle coincides with Q and one of the edges of right angle lies along AB. Mark the point R such that QR = 4.8 cm. |  |
| Step 3: Place the scale and the set square as shown in the figure. |  |
| Step 4: Hold the scale firmly and slide the set square along the edge of the scale until the other edge touches the point R. Draw a line RS through R. |  |
| Step 5: The line RS is parallel to AB. That is, RS ║AB. |  |
9.
| Step 1: Draw a line. Mark two points A and B on the line such that AB = 6.5 cm. Mark a point M anywhere above the line. |  |
| Step 2: Place the set square below AB in such a way that one of the edges that form a right angle lies along AB. Place the scale along the other edge of the set square as shown in the figure. |  |
| Step 3: Holding the scale firmly, Slide the set square along the edge of the scale until the other edge of the set square reaches the point M. Through M draw a line as shown. |  |
| Step 4: The line MN is parallel to AB. That is, MN ║AB |  |
10.
(i) 80°, 60°
The sum of 3 angles of triangle = 180°
Let A = 80° , B = 60° , C = ?
A + B + C = 180°
80° + 60° + C = 180°
= 180° - (80° + 60°)
C = 180° - 140° = 40°
Therefore third angle = 40°
(ii) 75°, 35°
The sum of 3 angles of triangle = 180°
Let A = 75°, B = 35°, C = ?
A + B + C = 180°
75° + 35° + C = 180°
= 180° - (75° + 35°)
C = 180° - 110° = 70°
Therefore third angle = 70°
(iii) 52°, 68°
The sum of 3 angles of triangle = 180°
Let A = 52°, B = 68°, C = ?
A + B + C = 180°
52 + 68 + C = 180°
= 180° - (52° + 68°)
C = 180° - 120° = 60°
Therefore third angle = 60°
(iv) 50°, 90°
The sum of 3 angles of triangle = 180°
Let A = 50°, B = 90°, C = ?
A + B + C = 180°
50° + 90° + C = 180°
= 180° - (50° + 90°)
C = 180° - 140° = 40°
Therefore third angle = 40°
(v) 120°, 30°
The sum of 3 angles of triangle = 180°
Let A = 120°, B = 30°, C = ?
A + B + C = 180°
75° + 35° + C = 180°
= 180° - (120°+ 30°)
C = 180° - 150 = 30°
Therefore third angle = 30°
(vi) 55°, 85°
The sum of 3 angles of triangle = 180°
Let A = 55°, B = 85°, C = ?
A + B + C = 180°
55° + 85° + C = 180°
= 180° - (55° + 85°)
C = 180° - 140°= 40°
Therefore third angle = 40°
6th Standard Syllabus & Materials
6th Standard
Tamilnadu 6th Standard Social Science T3 - குடிமையியல் - உள்ளாட்சி அமைப்பு - ஊரகமும் நகர்ப்புறமும் Important Questions And Answers Study Material - QB365 Set A
NEW6th Standard
Tamilnadu 6th Standard Social Science T3 - குடிமையியல் - மக்களாட்சி Important Questions And Answers Study Material - QB365 Set B
NEW6th Standard
Tamilnadu 6th Standard Social Science T3 - குடிமையியல் - மக்களாட்சி Important Questions And Answers Study Material - QB365 Set A
NEW6th Standard
Tamilnadu 6th Standard Social Science T3 - புவியியல் - பேரிடரைப் புரிந்து கொள்ளுதல் Important Questions And Answers Study Material - QB365 Set B
Tamilnadu Stateboard 6th Standard Subjects
Tamilnadu Stateboard Standards
