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Published on: 09/10/2019
Term 3 Perimeter and Area
Download Tamil Nadu 6th Standard Maths question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Maths Test1.
From one vertex of an equilateral triangle with side 40 cm, an equilateral triangle with 6 cm side is removed. What is the perimeter of the remaining portion?
2.
Find the cost of fencing a square plot of side 12 m at the rate of Rs. 15 per metre
3.
Find the length of the rectangular blackboard whose perimeter is 6 m and the breadth is 1 m.
4.
Find the perimeter of a triangle whose sides are 3 cm, 4 cm and 5 cm
5.
The side of a square is 5 cm. Find its perimeter.
6.
From all possible shapes of perimeter 80 cm with 9 identical squares, each of side 4 cm.
7.
Draw a square B whose side is twice of the square A. Calculate the perimeters of the squares A and B.
8.
How many different rectangles can be made with a 48 cm long string? Find the possible pairs of length and breadth of the rectangles.
9.
The length of a rectangle is three times its breadth. If its perimeter is 64 cm, find the sides of the rectangle
10.
The table given below contains some measures of the rectangle. Find the unknown values
| S. No | Length | Breadth | Perimeter | Area |
|---|---|---|---|---|
| i) | 5 cm | 8 cm | ? | ? |
| ii) | 13 cm | ? | 54cm | ? |
| iii) | ? | 15 cm | 60 cm | ? |
| iv) | 10 m | ? | ? | 120 square metre |
| v) | 4 feet | ? | 20 square feet |
1.
Perimeter (P) = a + b + C
= (40 + 40 + 40) cm
= 120 cm
Removed portion = 6 cm
\(\therefore\) Perimeter of the remaining
portion = (120 - 6)
= 114 cm
2.
Side of a square plot = 12 m
Perimeter of the square plot = (4 \(\times\) s) units
= 4 × 12 = 48m
Cost of fencing the plot at the rate of Rs. 15 per metre = 48 × 15 = Rs. 720
3.
Perimeter of the black board, P = 6 m
Breadth of the black board, b = 1 m
length, l = ?
2 (l + b) = 6
2 (l + 1) = 6
\(l+1={6\over2}\)
= 3
l = 3 – 1
= 2 m
The length of the black board is 2 m.
4.
a = 3 cm
b = 4 cm
c = 5 cm
P = (a + b + c) units
= 3 + 4 + 5 = 12 cm
Perimeter of the triangle is 12 cm.
5.
s = 5 cm
P = (4 × s) units
= 4 × 5
= 20 cm
Perimeter of the square is 20 cm
6.
Perimeter = 80 cm
No. of identical shapes = 9
Side of square = 4 cm
Possible shape:
\(\therefore\) P = 80cm
7.
To prove: Square B = 2 (Square A)
Let the side of the square B = 4 cm
P = 4s = 4 \(\times\) 4 = 1.6.cm
Next, The side of the square A = 2 cm
P = 4s = 4 \(\times\) 2 = 8 cm
\(\therefore\) Square B = 16 = 2 (8) = 2 square A
\(\therefore\) Perimeter of square B is twice that of square A.
8.
Length of the string = 48 cm
No. of possible pairs = 12
12 pairs,
The possible pairs of length and breadth of the rectangles are,
(1, 23), (2, 22), (3, 21), (4, 20), (5, 19); (6, 18), (7, 17), (8,16), (9,15),(10,14), (11, 13), (12, 12)
12 different rectangles can be made.
9.
l = 3b
P = 64 cm
2 (I + b) = 64
2(3b + b) = 64
2 (4b) = 64
\(8b=64\Rightarrow b=\cfrac { 64 }{ 8 } 8\)cm
I = 3 (8) = 24 crn
The sides of the rectangle I = 24 cm, b = 8 cm
10.
(i) Given:
Length (1) = 5 cm
breadth (b) = 8 cm
Perimeter = 2 (I + b)
= 2 (5 + 8)
= 2 \(\times\)13 = 26 cm
Are a (A) = lb = 5 \(\times\) 8 = 40 cm2
(ii) Given :
Length (1) = 13 cm
Perimeter (P) = 54 cm
To find: b and A
\(b=\cfrac { P-2l }{ 2 } \)
= \(\cfrac { 54-2(13) }{ 2 } \)
= \(\cfrac { 54-26 }{ 2 } =\cfrac { 28 }{ 2 } =14\)
b = 14 cm
Area (A) = lb = 13 \(\times\) 14
A = 182 cm2
(iii) Given:
Breadth (b) = 15 cm
Perimeter (P) = 60 cm
To find: 1 and A
\(I=\cfrac { P-2b }{ 2 } \)
= \(\cfrac { 60-2(15) }{ 2 } =\cfrac { 60-30 }{ 2 } =\cfrac { 30 }{ 2 } \)
1 = 15 cm
A = lb = 15 \(\times\) 15 = 225
A = 225 cm2
(iv) Given :
Length (1) = 10m
Area (A) = 120 sq. m
To find: band P
\(b=\cfrac { A }{ l } \)
= \(\cfrac { 120 }{ 10 } =12\)
b = 12m
P = 2 (1 + b)
= 2(10 + 12)
= 2 \(\times\) 22 = 44
P = 44 m
(v) Given:
Breadth (b) = 4 feet
Area (A) = 20 s. feet
To find: 1 and P
\(\therefore l=\cfrac { A }{ b } \)
= \(\cfrac { 20 }{ 4 } =5\)
1= 5 feet
P = 2(I + b)
= 2(5 + 4)
= 2(9) = 18
P = 18 feet
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Tamilnadu Stateboard 6th Standard Subjects
Tamilnadu Stateboard Standards
