6th Standard Syllabus & Materials
6th Standard
Tamilnadu 6th Standard Tamil இயல் 3 - எல்லாரும் இன்புற - பெயர்ச்சொல் Important Questions And Answers Study Material - QB365 Set B
NEW6th Standard
Tamilnadu 6th Standard Tamil இயல் 3 - எல்லாரும் இன்புற - பெயர்ச்சொல் Important Questions And Answers Study Material - QB365 Set A
NEW6th Standard
Tamilnadu 6th Standard Tamil இயல் 2 - கூடித் தொழில் செய் - சுட்டு எழுத்துகள், வினா எழுத்துகள் Important Questions And Answers Study Material - QB365 Set B
NEW6th Standard
Tamilnadu 6th Standard Tamil இயல் 2 - கூடித் தொழில் செய் - சுட்டு எழுத்துகள், வினா எழுத்துகள் Important Questions And Answers Study Material - QB365 Set A
NEW6th Standard
Tamilnadu 6th Standard Tamil பருவம் 1 - இயல் 1 - மொழி -தமிழ்த்தேன் - இன்பத்தமிழ் Important Questions And Answers Study Material - QB365
NEW6th Standard
Tamilnadu 6th Standard Social Science T3 - குடிமையியல் - உள்ளாட்சி அமைப்பு - ஊரகமும் நகர்ப்புறமும் Important Questions And Answers Study Material - QB365 Set B
Published on: 18/06/2021
QB365 provides detailed and simple solution for every book back questions in class 6 Maths subject.It will helps to get more idea about question pattern in every book back questions with solution.
Download Tamil Nadu 6th Standard Maths question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Maths Test1.
(i) Find the sum of \(5\cfrac { 4 }{ 9 } \)and \(3\cfrac { 1 }{ 6 } \)
(ii) Subtract \(7\cfrac { 1 }{ 6 } \) from \(12\cfrac { 3 }{ 8 } \)
(iii) Subtract the sum of \(6 \frac{1}{6}\) and \(3 \frac{1}{5}\) from the sum of \(9 \frac{2}{3} \text { and } 2 \frac{1}{2}\)
2.
A rabbit has to cover \(26{1\over4}\)m to fetch its food. If it covers \(1{3\over4}\)m in one jump, then how many jumps will it take to fetch its food?
3.
Complete the fifth row in the Leibnitz triangle which is based on subraction.
4.
Multiply the following:
\(i)\ {2\over3}\times6\)
\(ii)\ 8{1\over3}\times5\)
\(iii)\ {3\over8}\times{4\over5}\)
\(iv)\ {3{5\over7}}\times1{1\over13}\)
5.
Answer the following:
i) Find the sum of \(1\over7\)and \(3\over9\).
ii) What is the total of \(3{1\over3}\)and \(4{1\over6}\) ?
iii) Simplify: \(1{3\over5}+5{4\over7}\)
iv) Find the difference between \(8\over 9\)and \(2\over7\)
v) Subtract \(1{3\over 5}\)from \(2{1\over3}\)
vi) Simplify : \(7{2\over7}-3{4\over 21}\)
1.
\(5\cfrac { 4 }{ 9 } \) and \(3\cfrac { 1 }{ 6 } \)
\(\Rightarrow \cfrac { 49 }{ 9 } +\cfrac { 19 }{ 6 } \)
LCM of 9 and 6 is 18
= \(\cfrac { 49\times 2 }{ 9\times 2 } +\cfrac { 19\times 3 }{ 6\times 3 } \)
= \(\cfrac { 98 }{ 18 } +\cfrac { 57 }{ 18 } \)
= \(\cfrac { 98+57 }{ 18 } =\cfrac { 155 }{ 18 } \)
= \(8\cfrac { 11 }{ 18 } \)
(ii) \(7\cfrac { 1 }{ 6 } \Rightarrow \cfrac { 43 }{ 6 } \)
\(12\cfrac { 3 }{ 8 } \Rightarrow \cfrac { 99 }{ 8 } \)
Now to find : \(\cfrac { 99 }{ 8 } -\cfrac { 43 }{ 6 } \)
LCM = 24
= \(\cfrac { 99\times 3 }{ 8\times 3 } -\cfrac { 43\times 4 }{ 6\times 4 } \)
= \(\cfrac { 297 }{ 24 } -\cfrac { 172 }{ 24 } \)
= \(\cfrac { 297-172 }{ 24 } =\cfrac { 125 }{ 24 } \)
= \(5\cfrac { 5 }{ 24 } \)
(iii) To find
\(\left( 9\cfrac { 2 }{ 3 } +2\cfrac { 1 }{ 2 } \right) -\left( 6\cfrac { 1 }{ 6 } +3\cfrac { 1 }{ 5 } \right) \)
\(\Rightarrow \left( \cfrac { 29 }{ 3 } +\cfrac { 25 }{ 2 } \right) -\left( \cfrac { 37 }{ 6 } +\cfrac { 16 }{ 5 } \right) \)
\(\Rightarrow \) LCM of 3 and 2 is 6
LCM of 6 and 5 is 30
\(\Rightarrow \left( \cfrac { 29\times 2 }{ 3\times 2 } +\cfrac { 5\times 3 }{ 2\times 3 } \right) -\left( \cfrac { 37\times 5 }{ 6\times 5 } +\cfrac { 16\times 6 }{ 5\times 6 } \right) \)
\(\Rightarrow \left( \cfrac { 58 }{ 6 } +\cfrac { 15 }{ 6 } \right) -\left( \cfrac { 185 }{ 30 } +\cfrac { 96 }{ 30 } \right) \)
\(\Rightarrow \left( \cfrac { 58+15 }{ 6 } \right) -\left( \cfrac { 185+96 }{ 30 } \right) \)
\(\Rightarrow \cfrac { 73 }{ 6 } -\cfrac { 281 }{ 30 } \)
LCM of 6 and 30 is 30
\(\Rightarrow \cfrac { 73\times 5 }{ 6\times 5 } -\cfrac { 281 }{ 30 } \)
\(\cfrac { 365 }{ 30 } -\cfrac { 281 }{ 30 } =\) 
= \(2\cfrac { 4 }{ 5 } \)
2.
Total distance = \(26\frac { 1 }{ 4 } \) m
= \(\cfrac { 105 }{ 4 } \)
A rabbit covers in 1 jump = \(1\frac { 3 }{ 4 } \)
= \(\cfrac { 7 }{ 4 } \)m
\(\cfrac { 7 }{ 4 } \) m = 1 jump
\(\cfrac { 105 }{ 4 } m=\cfrac { 7 }{ 7/4 } \times \cfrac { 105 }{ 4 } \)
= \(\cfrac { 4 }{ 7 } \times \cfrac { 105 }{ 4 } =15\)
3.
\(\cfrac { 1 }{ 4 } -\cfrac { 1 }{ 5 } =\cfrac { 5-4 }{ 20 } =\cfrac { 1 }{ 20 } \)
\(\cfrac { 1 }{ 12 } -\cfrac { 1 }{ 20 } =\cfrac { 5-3 }{ 60 } =\cfrac { 2 }{ 60 } =\cfrac { 1 }{ 30 } \)
\(\cfrac { 1 }{ 12 } -\cfrac { 1 }{ 30 } =\cfrac { 5-2 }{ 60 } =\cfrac { 3 }{ 60 } =\cfrac { 1 }{ 20 } \)
\(\cfrac { 1 }{ 20 } ,\cfrac { 1 }{ 30 } ,\cfrac { 1 }{ 20 } \)
4.
(i) \(\cfrac { 2 }{ 3 } \times 6=2\times =4\)
(ii) \(8\cfrac { 1 }{ 3 } \times 5\)
= \(\cfrac { 25 }{ 3 } \times 5=\cfrac { 25\times 5 }{ 3 } =\cfrac { 125 }{ 3 } =41\cfrac { 2 }{ 3 } \)
(iii) \(\cfrac { 3 }{ 8 } \times \cfrac { 4 }{ 5 } \)
= \(\cfrac { 3 }{ 8 } \times \cfrac { 4 }{ 5 } =\cfrac { 3\times 1 }{ 2\times 5 } =\cfrac { 3 }{ 10 } \)
(iv) \(3\cfrac { 5 }{ 7 } \times 1\cfrac { 1 }{ 13 } \)
= \(\cfrac { 26 }{ 7 } \times \cfrac { 14 }{ 13 } \)
= 2 \(\times\) 2 = 14
5.
(i) \(\cfrac { 1 }{ 7 }\ and\ \cfrac { 3 }{ 9 } \)
To find: \(\cfrac { 1 }{ 7 } +\cfrac { 3 }{ 9 } \)
LCM of 7 and 9 is 63
\(\Rightarrow \cfrac { 1 }{ 7 } \times \cfrac { 9 }{ 9 } +\cfrac { 3 }{ 9 } \times \cfrac { 7 }{ 7 } \)
= \(\cfrac { 9 }{ 63 } +\cfrac { 21 }{ 63 } =\cfrac { 9+21 }{ 63 } =\cfrac { 30 }{ 63 } =\cfrac { 10 }{ 21 } \)
(ii) \(3\cfrac { 1 }{ 3 } \ and\ 4\cfrac { 1 }{ 6 } \)
To find : \(3\cfrac { 1 }{ 3 } +4\cfrac { 1 }{ 6 } \)
= \(\cfrac { 10 }{ 3 } +\cfrac { 25 }{ 6 } \)
LCM of 3 and 6 is 6
= \(\cfrac { 10\times 2 }{ 3\times 2 } +\cfrac { 25 }{ 6 } \)
= \(\cfrac { 20 }{ 6 } +\cfrac { 25 }{ 6 } =\cfrac { 20+25 }{ 6 } =\cfrac { 45 }{ 6 } =\cfrac { 15 }{ 2 } =7\cfrac { 1 }{ 2 } \)
(iii) \(\cfrac { 8 }{ 5 } +\cfrac { 39 }{ 7 } \)
LCM of 5 and 7 is 35
= \(\cfrac { 8\times 7 }{ 5\times 7 } +\cfrac { 39\times 5 }{ 7\times 5 } \)
= \(\cfrac { 56 }{ 35 } +\cfrac { 195 }{ 35 } =\cfrac { 56+195 }{ 35 } =\cfrac { 251 }{ 35 } \)
= \(7\cfrac { 6 }{ 35 } \)
(iv) \(\cfrac { 8 }{ 9 } and\cfrac { 2 }{ 7 } \)
To find \(\cfrac { 8 }{ 9 } -\cfrac { 2 }{ 7 } \)
LCM 9 and 7 is 63
= \(\cfrac { 8\times 7 }{ 9\times 7 } -\cfrac { 2\times 9 }{ 7\times 9 } \)
= \(\cfrac { 56 }{ 63 } -\cfrac { 18 }{ 63 } =\cfrac { 56-18 }{ 63 } =\cfrac { 38 }{ 63 } \)
(v) \(1\cfrac { 3 }{ 5 } ,2\cfrac { 1 }{ 3 } \)
To find \(2\cfrac { 1 }{ 3 } -1\cfrac { 3 }{ 5 } \)
\(\Rightarrow \cfrac { 7 }{ 3 } -\cfrac { 8 }{ 5 } \)
LCM 3 and 5 is 15
= \(\cfrac { 7\times 5 }{ 3\times 5 } -\cfrac { 8\times 3 }{ 5\times 3 } \)
= \(\cfrac { 35 }{ 15 } -\cfrac { 24 }{ 15 } =\cfrac { 35-24 }{ 15 } =\cfrac { 11 }{ 15 } \)
(vi) \(7\cfrac { 2 }{ 7 } -3\cfrac { 4 }{ 21 } \)
\(\cfrac { 51 }{ 7 } -\cfrac { 67 }{ 21 } \)
LCM of 7 and 21 is 21
\(\Rightarrow \cfrac { 51\times 3 }{ 7\times 3 } -\cfrac { 67 }{ 21 } \)
= \(\cfrac { 153 }{ 21 } -\cfrac { 67 }{ 21 } =\cfrac { 153-27 }{ 21 } \)
= \(\cfrac { 86 }{ 21 } =4\cfrac { 2 }{ 21 } \)
6th Standard Syllabus & Materials
6th Standard
Tamilnadu 6th Standard Social Science T3 - குடிமையியல் - உள்ளாட்சி அமைப்பு - ஊரகமும் நகர்ப்புறமும் Important Questions And Answers Study Material - QB365 Set A
NEW6th Standard
Tamilnadu 6th Standard Social Science T3 - குடிமையியல் - மக்களாட்சி Important Questions And Answers Study Material - QB365 Set B
NEW6th Standard
Tamilnadu 6th Standard Social Science T3 - குடிமையியல் - மக்களாட்சி Important Questions And Answers Study Material - QB365 Set A
NEW6th Standard
Tamilnadu 6th Standard Social Science T3 - புவியியல் - பேரிடரைப் புரிந்து கொள்ளுதல் Important Questions And Answers Study Material - QB365 Set B
Tamilnadu Stateboard 6th Standard Subjects
Tamilnadu Stateboard Standards
