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Published on: 13/05/2022
QB365 provides detailed and simple solution for every book back questions in class 6 Maths subject.It will helps to get more idea about question pattern in every book back questions with solution.
latest Book back QuestionsDownload Tamil Nadu 6th Standard Maths question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Maths Test1.
(i) Find the sum of \(5\cfrac { 4 }{ 9 } \)and \(3\cfrac { 1 }{ 6 } \)
(ii) Subtract \(7\cfrac { 1 }{ 6 } \) from \(12\cfrac { 3 }{ 8 } \)
(iii) Subtract the sum of \(6 \frac{1}{6}\) and \(3 \frac{1}{5}\) from the sum of \(9 \frac{2}{3} \text { and } 2 \frac{1}{2}\)
2.
A rabbit has to cover \(26{1\over4}\)m to fetch its food. If it covers \(1{3\over4}\)m in one jump, then how many jumps will it take to fetch its food?
3.
Complete the fifth row in the Leibnitz triangle which is based on subraction.
4.
Multiply the following:
\(i)\ {2\over3}\times6\)
\(ii)\ 8{1\over3}\times5\)
\(iii)\ {3\over8}\times{4\over5}\)
\(iv)\ {3{5\over7}}\times1{1\over13}\)
5.
Answer the following:
i) Find the sum of \(1\over7\)and \(3\over9\).
ii) What is the total of \(3{1\over3}\)and \(4{1\over6}\) ?
iii) Simplify: \(1{3\over5}+5{4\over7}\)
iv) Find the difference between \(8\over 9\)and \(2\over7\)
v) Subtract \(1{3\over 5}\)from \(2{1\over3}\)
vi) Simplify : \(7{2\over7}-3{4\over 21}\)
1.
\(5\cfrac { 4 }{ 9 } \) and \(3\cfrac { 1 }{ 6 } \)
\(\Rightarrow \cfrac { 49 }{ 9 } +\cfrac { 19 }{ 6 } \)
LCM of 9 and 6 is 18
= \(\cfrac { 49\times 2 }{ 9\times 2 } +\cfrac { 19\times 3 }{ 6\times 3 } \)
= \(\cfrac { 98 }{ 18 } +\cfrac { 57 }{ 18 } \)
= \(\cfrac { 98+57 }{ 18 } =\cfrac { 155 }{ 18 } \)
= \(8\cfrac { 11 }{ 18 } \)
(ii) \(7\cfrac { 1 }{ 6 } \Rightarrow \cfrac { 43 }{ 6 } \)
\(12\cfrac { 3 }{ 8 } \Rightarrow \cfrac { 99 }{ 8 } \)
Now to find : \(\cfrac { 99 }{ 8 } -\cfrac { 43 }{ 6 } \)
LCM = 24
= \(\cfrac { 99\times 3 }{ 8\times 3 } -\cfrac { 43\times 4 }{ 6\times 4 } \)
= \(\cfrac { 297 }{ 24 } -\cfrac { 172 }{ 24 } \)
= \(\cfrac { 297-172 }{ 24 } =\cfrac { 125 }{ 24 } \)
= \(5\cfrac { 5 }{ 24 } \)
(iii) To find
\(\left( 9\cfrac { 2 }{ 3 } +2\cfrac { 1 }{ 2 } \right) -\left( 6\cfrac { 1 }{ 6 } +3\cfrac { 1 }{ 5 } \right) \)
\(\Rightarrow \left( \cfrac { 29 }{ 3 } +\cfrac { 25 }{ 2 } \right) -\left( \cfrac { 37 }{ 6 } +\cfrac { 16 }{ 5 } \right) \)
\(\Rightarrow \) LCM of 3 and 2 is 6
LCM of 6 and 5 is 30
\(\Rightarrow \left( \cfrac { 29\times 2 }{ 3\times 2 } +\cfrac { 5\times 3 }{ 2\times 3 } \right) -\left( \cfrac { 37\times 5 }{ 6\times 5 } +\cfrac { 16\times 6 }{ 5\times 6 } \right) \)
\(\Rightarrow \left( \cfrac { 58 }{ 6 } +\cfrac { 15 }{ 6 } \right) -\left( \cfrac { 185 }{ 30 } +\cfrac { 96 }{ 30 } \right) \)
\(\Rightarrow \left( \cfrac { 58+15 }{ 6 } \right) -\left( \cfrac { 185+96 }{ 30 } \right) \)
\(\Rightarrow \cfrac { 73 }{ 6 } -\cfrac { 281 }{ 30 } \)
LCM of 6 and 30 is 30
\(\Rightarrow \cfrac { 73\times 5 }{ 6\times 5 } -\cfrac { 281 }{ 30 } \)
\(\cfrac { 365 }{ 30 } -\cfrac { 281 }{ 30 } =\) 
= \(2\cfrac { 4 }{ 5 } \)
2.
Total distance = \(26\frac { 1 }{ 4 } \) m
= \(\cfrac { 105 }{ 4 } \)
A rabbit covers in 1 jump = \(1\frac { 3 }{ 4 } \)
= \(\cfrac { 7 }{ 4 } \)m
\(\cfrac { 7 }{ 4 } \) m = 1 jump
\(\cfrac { 105 }{ 4 } m=\cfrac { 7 }{ 7/4 } \times \cfrac { 105 }{ 4 } \)
= \(\cfrac { 4 }{ 7 } \times \cfrac { 105 }{ 4 } =15\)
3.
\(\cfrac { 1 }{ 4 } -\cfrac { 1 }{ 5 } =\cfrac { 5-4 }{ 20 } =\cfrac { 1 }{ 20 } \)
\(\cfrac { 1 }{ 12 } -\cfrac { 1 }{ 20 } =\cfrac { 5-3 }{ 60 } =\cfrac { 2 }{ 60 } =\cfrac { 1 }{ 30 } \)
\(\cfrac { 1 }{ 12 } -\cfrac { 1 }{ 30 } =\cfrac { 5-2 }{ 60 } =\cfrac { 3 }{ 60 } =\cfrac { 1 }{ 20 } \)
\(\cfrac { 1 }{ 20 } ,\cfrac { 1 }{ 30 } ,\cfrac { 1 }{ 20 } \)
4.
(i) \(\cfrac { 2 }{ 3 } \times 6=2\times =4\)
(ii) \(8\cfrac { 1 }{ 3 } \times 5\)
= \(\cfrac { 25 }{ 3 } \times 5=\cfrac { 25\times 5 }{ 3 } =\cfrac { 125 }{ 3 } =41\cfrac { 2 }{ 3 } \)
(iii) \(\cfrac { 3 }{ 8 } \times \cfrac { 4 }{ 5 } \)
= \(\cfrac { 3 }{ 8 } \times \cfrac { 4 }{ 5 } =\cfrac { 3\times 1 }{ 2\times 5 } =\cfrac { 3 }{ 10 } \)
(iv) \(3\cfrac { 5 }{ 7 } \times 1\cfrac { 1 }{ 13 } \)
= \(\cfrac { 26 }{ 7 } \times \cfrac { 14 }{ 13 } \)
= 2 \(\times\) 2 = 14
5.
(i) \(\cfrac { 1 }{ 7 }\ and\ \cfrac { 3 }{ 9 } \)
To find: \(\cfrac { 1 }{ 7 } +\cfrac { 3 }{ 9 } \)
LCM of 7 and 9 is 63
\(\Rightarrow \cfrac { 1 }{ 7 } \times \cfrac { 9 }{ 9 } +\cfrac { 3 }{ 9 } \times \cfrac { 7 }{ 7 } \)
= \(\cfrac { 9 }{ 63 } +\cfrac { 21 }{ 63 } =\cfrac { 9+21 }{ 63 } =\cfrac { 30 }{ 63 } =\cfrac { 10 }{ 21 } \)
(ii) \(3\cfrac { 1 }{ 3 } \ and\ 4\cfrac { 1 }{ 6 } \)
To find : \(3\cfrac { 1 }{ 3 } +4\cfrac { 1 }{ 6 } \)
= \(\cfrac { 10 }{ 3 } +\cfrac { 25 }{ 6 } \)
LCM of 3 and 6 is 6
= \(\cfrac { 10\times 2 }{ 3\times 2 } +\cfrac { 25 }{ 6 } \)
= \(\cfrac { 20 }{ 6 } +\cfrac { 25 }{ 6 } =\cfrac { 20+25 }{ 6 } =\cfrac { 45 }{ 6 } =\cfrac { 15 }{ 2 } =7\cfrac { 1 }{ 2 } \)
(iii) \(\cfrac { 8 }{ 5 } +\cfrac { 39 }{ 7 } \)
LCM of 5 and 7 is 35
= \(\cfrac { 8\times 7 }{ 5\times 7 } +\cfrac { 39\times 5 }{ 7\times 5 } \)
= \(\cfrac { 56 }{ 35 } +\cfrac { 195 }{ 35 } =\cfrac { 56+195 }{ 35 } =\cfrac { 251 }{ 35 } \)
= \(7\cfrac { 6 }{ 35 } \)
(iv) \(\cfrac { 8 }{ 9 } and\cfrac { 2 }{ 7 } \)
To find \(\cfrac { 8 }{ 9 } -\cfrac { 2 }{ 7 } \)
LCM 9 and 7 is 63
= \(\cfrac { 8\times 7 }{ 9\times 7 } -\cfrac { 2\times 9 }{ 7\times 9 } \)
= \(\cfrac { 56 }{ 63 } -\cfrac { 18 }{ 63 } =\cfrac { 56-18 }{ 63 } =\cfrac { 38 }{ 63 } \)
(v) \(1\cfrac { 3 }{ 5 } ,2\cfrac { 1 }{ 3 } \)
To find \(2\cfrac { 1 }{ 3 } -1\cfrac { 3 }{ 5 } \)
\(\Rightarrow \cfrac { 7 }{ 3 } -\cfrac { 8 }{ 5 } \)
LCM 3 and 5 is 15
= \(\cfrac { 7\times 5 }{ 3\times 5 } -\cfrac { 8\times 3 }{ 5\times 3 } \)
= \(\cfrac { 35 }{ 15 } -\cfrac { 24 }{ 15 } =\cfrac { 35-24 }{ 15 } =\cfrac { 11 }{ 15 } \)
(vi) \(7\cfrac { 2 }{ 7 } -3\cfrac { 4 }{ 21 } \)
\(\cfrac { 51 }{ 7 } -\cfrac { 67 }{ 21 } \)
LCM of 7 and 21 is 21
\(\Rightarrow \cfrac { 51\times 3 }{ 7\times 3 } -\cfrac { 67 }{ 21 } \)
= \(\cfrac { 153 }{ 21 } -\cfrac { 67 }{ 21 } =\cfrac { 153-27 }{ 21 } \)
= \(\cfrac { 86 }{ 21 } =4\cfrac { 2 }{ 21 } \)
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Tamilnadu Stateboard Standards
