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Published on: 18/06/2021
QB365 provides detailed and simple solution for every book back questions in class 6 Maths subject.It will helps to get more idea about question pattern in every book back questions with solution.
Download Tamil Nadu 6th Standard Maths question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Maths Test1.
Find the area of the given 'L' shaped rectangular figure by dividing it into squares of equal sizes.
Take side: 7cm
2.
Find the number of tiles required to fill the are a of following ligures
(i)

(ii)

(iii)

(iv)

3.
Draw a square B whose side is twice of the square A. Calculate the perimeters of the squares A and B.
4.
A rectangle has length 40 cm and breadth 20 cm. How many squares with side 10 cm can be formed from it.
5.
Find the perimeter and area of the following shapes
1.

No. of Squares = 7
Area of each square = 7 \(\times\) 7 = 49
\(\therefore\) Area of 'L' shaped figure = 7 \(\times\)49 = 343 cm2
2.
(i) 4 square tiles horizontally and 4 square tiles vertically.
\(\Rightarrow\) 4 \(\times\) 4 = 16 sq. units.
No. of tiles tilled = 7
No. of tiles required = 16 -7 = 9
(ii) 4 square tiles vertically and 3 square tiles horizontally .
Area \(\Rightarrow\) 4 \(\times\) 3 = 12 sq. units.
No. of tiles filled = 6
(iii) 4 square tiles vertically and 3 square files horizontally.
Area = 4 \(\times\) 3 = 12 sq. units.
No. of tiles filled = 6
Required tiles = 12 - 6 = 6
(iv) 4 square tiles horizontally and 4 square tiles vertically.
Area = 4 \(\times\) 4 = 16 sq. units.
No. of tiles filled = 8
Required tiles = 16 - 8 = 8
3.
To prove: Square B = 2 (Square A)
Let the side of the square B = 4 cm
P = 4s = 4 \(\times\) 4 = 1.6.cm
Next, The side of the square A = 2 cm
P = 4s = 4 \(\times\) 2 = 8 cm
\(\therefore\) Square B = 16 = 2 (8) = 2 square A
\(\therefore\) Perimeter of square B is twice that of square A.
4.
length = 40 cm
breadth = 20 cm
Side of the square = 10 cm
Area of the rectangle = lb
= ( 40 \(\times\) 20)cm2
= 800 cm2
(side) s = 10cm
Area of a square (S2) = 102 = 100 cm2
No. of square = \(\cfrac { 800 }{ 100 } =8\)
5.
(i) Given :
Perimeter = 12 times 4 cm
= 12 \(\times\) 4 = 48 cm
Area \(\Rightarrow\) Given = 5 squares
= 5 \(\times\) area of square
= 5 \(\times\) (sider)2
= 5 \(\times\) 42
\(\therefore\) A = 5 \(\times\) 16 = 80 Cm2
\(\therefore\) P = 48 cm, A = 80 cm2
(ii) Given :
Perimeter = 4 times 4 cm + 4 times 5cm
= 4 (4) + 4 (5)
= 16 + 20 = 36 cm
Area = 4 triangles + 1 square
= \(4\left( \frac { 1 }{ 2 } bh \right) +1\left( s \right) ^{ 2 }\)
= \(4\left( \frac { 1 }{ 2 } \left( 5 \right) \left( 4 \right) \right) +1\left( { 3 }^{ 2 } \right) \)
= 4 \(\times\) 5 \(\times\) 2 + 9
= 40 + 9 = 49 cm2
(iii) Given :
Perimeter = (50 + 12 + l3 + 40 + 10 +10 + 10 + 5) cm
= 150 cm
= \(\left( lb+\cfrac { 1 }{ 2 } bh+{ s }^{ 2 } \right) { cm }^{ 2 }\)
= \(\left( 50\times 5 \right) +\cfrac { 1 }{ 2 } \times 12\times 5+{ 10 }^{ 2 }\)
= 250 + 30 + 100
= 380 cm2
\(\therefore\) P = 150 cm, A = 380 cm2
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