(i) Yes
(ii) 5
(iii) 
     
Sums are 17, 19, 20, 21 and 23.

1 picture represents 10 vehicles
(i) There were 9 × 10 = 90 motor cycles sold.
(ii) True.
(iii) There were 4 × 10 = 40 bicycles sold.
(iv) There were 7 cars and 3 vans pictures. Therefore 70 + 30 = 100 cars and vans sold.
(v) There were 7 cars, 3 vans, 9 motor cycles, 2 buses and 4 bicycles sold. Therefore, 70 + 30 + 90 + 20 + 40 = 250 vehicles sold.

Number of green cubes = 3
Number of blue cubes = 9
Number of yellow cubes = 4
Number of orange cubes = 8
(a) Ratio of orange to yellow cubes = \(\frac { Number\ of\ orange\ cubes }{ Number\ of\ yellow\ cubes } \)
 =\(\frac { 8 }{ 4 } =\frac { 2 }{ 1 } \) = 2 : 1
Ratio of orange to yellow cubes = 2 : 1
(b) \(\frac { Number\ of\ green\ cubes }{ Number\ of\ blue\ cubes } =\frac { 3 }{ 9 } =\frac { 1 }{ 3 } \)
Ratio of green to blue cubes = 1 : 3
(c) The ratios can be Orange:
Yellow, Orange: blue, Orange: green, Yellow: orange, yellow: blue, yellow: green, blue: green, blue: orange, blue: yellow, green: orange, green: yellow, green: blue. Thus 12 ratios can be formed.
i.e., the possiblity of forming the different ratios
3 : 9, 3 : 4, 3 : 8
9 : 3, 9 : 4, 9 : 8
4 : 3, 4 : 9, 4 : 8
8 : 3, 8 : 9, 8 : 4

(i) Length of wire = '12 s' cm 
Sum of 3 sides of equilateral triangle = '12 s'
3 \(\times\) side = 12 s
The length of a side = \(\frac{12 \mathrm{~s}}{3}=\) '4 s' cm
(ii) Sum of 4 sides of square = '12 s'
The length of a side = \(\frac{12 \mathrm{~s}}{4}=\) '3 s' cm

i), iii) are obtuse angles

20 + [8 \(\times\) 2 + {\({ 6\times 3 } \)− 10 ÷ 5}]  (given question)
=20 + [8 \(\times\) 2 + {18 − 10 ÷ 5}] (bar completed first)
=20 + [8 \(\times\) 2 + {18 − 2}] ( ÷ completed second )
=20 + [8 \(\times\) 2 + 16] ({ } completed third)
=20 + [16 + 16] ( \(\times\) completed fourth)
=20 + 32 ([ ] operation completed fifth)
=52 ( + completed last)

Total length 63 cm, on dividing 3 + 4 = 7 equal parts, we get the line segments with lengths
\(\frac{3}{7}\times63=27\ cm\)
\(\frac{4}{7}\times63=36\ cm\)
Length of each line segment is 27 cm & 36 cm

Arranging the numbers in place value chart

(i) Highest mountain is Anaimudi [Comparing left most digits]
(ii) From the above chart
In thousands place, Doddabetta and Anaimudi have greater value 2.
Comparing digits of 2637 and 2695
2 = 2, 6 = 6, 3 < 9.
\(\therefore\) 2637 < 2695
Again comparing the digits of 1647 and 1778
1=1,6 < 7
\(\therefore\)  1647 < 1778.
\(\therefore\) The required order is 2695 > 2637 > 1778> 1647.
\(\therefore\) Anaimudi > Doddabetta > Veliangiri > Mahendragiri
(iii) 

Lakh is 2 places to the left of thousand. So, it is 10 \(\times\) 10 = 100 times thousand.
Hence, 1 lakh = 100 thousand.