Matches won by Team A = 26 out of 52
\(\text { i.e: } \frac{26}{52}=1 / 2 \)
Matches won by team B = \(\frac { 3 }{ 4 } \times 52\) = 39 out of 52
∴ Team B won 39 out of 52 and therefore team B has the better record.

Number of times Antony brushes a day = 2
∴ Number of times Antony brushes a week = 2\(\times\)7 = 14
Number of times Shabeen brushes a day = 1
∴ Number of times Shabeen brushes a week = 1\(\times\)7 = 7
Number of times Antony brushes : Number of times Antony brushes =14 : 7 = 2 : 1
∴ The required ratio = 2 :1

Yes, 12 : 24 : : 18: 36
Because product of extremes = 12 x 36 = 432
Product of means = 24 x 18 = 432
∴ 12 : 24 : : 18 : 36.

Here the extremes are 3 and 20 and the means are 2 and 30.
Product of extremes, ad = 3 × 20 = 60.
Product of means, bc = 2 × 30 = 60.
Thus by proportionality law, we find ad = bc and hence 3 : 2 and 30 : 20 are in proportion.

40 in the ratio 6 : 14.
Dividing 40 into 6 + 14 = 20 equal parts and
\(40\times\frac{6}{20}=12\)
\(40\times\frac{14}{20}=28\)
\(\therefore\) The numbers are 12, 28.

Ratio of red beads: blue beads = 35: 30
Fraction of 35 : 30  \(=\frac{35}{30}\)
= 7:6
Also given that the bracelet made is smaller in size
∴ The possible ways are red beads: blue beads
The equivalent ways are
\( \frac{7 \times 2}{6 \times 2}=\frac{14}{12}=14: 12 \)
\( \frac{7 \times 3}{6 \times 3}=\frac{21}{18}=21: 18 \)
\( \frac{7 \times 4}{6 \times 4}=\frac{28}{24}=28: 24\)
= 7 : 6 (or) 14: 12 (or) 21 : 18 (or) 28 : 24
In 4 different way can she made.

In my purchase cost of 6 apples = Rs. 90
∴ cost of 1 apple = \(\frac { 90 }{ 6 } \) = Rs. 15
In my friend's purchase cost of 5 apples = Rs. 70
∴ Cost of apple =\(\frac { 70 }{ 5 } \) = Rs. 14
My friend buy for lower prize.
∴ My friend's purchase is a better buy.

Run rate = Ratio of runs to overs
Run rate of Karmegam = \(\frac { 54 }{ 9 } \) = \(\frac { 6 }{ 1 } \) = 6 :1
Run rate of Asif = \(\frac { 77 }{ 11 } \) = \(\frac { 7 }{ 1 } \) = 7 :1
∴ Asif's run rate is better.

The given pictures are in the ratio 2 : 5 and 4 : 3 respectively.
Here the extremes are 2 and 3 and the means are 5 and 4.
Product of extremes, ad = 2 \(\times\)3 = 6.
Product of means, bc = 5 \(\times\) 4 = 20.
Thus, we find ad\(\neq\)  bc and hence 2 : 5 and 4 : 3 are not in proportion.

Total length 63 cm, on dividing 3 + 4 = 7 equal parts, we get the line segments with lengths
\(\frac{3}{7}\times63=27\ cm\)
\(\frac{4}{7}\times63=36\ cm\)
Length of each line segment is 27 cm & 36 cm