Let us make Ceasar Cipher table first. Here, we have to set to + 4 table. For that, we have to start letter e to set as A, f as B … likewise d as Z. Now, the + 4 Ceasar Cipher table looks like

The given plain text is
fvieo mr gshiw ger fi xvmgoc
To crack this secret code, follow the steps given below.
Step 1: Using Ceasar Cipher table, let us first match the most repeated letters. This will help us to progress faster.
fvieo mr gshiw ger fi xvmgoc

Step 2: Then, let us find remaining letters to complete the code.

Thus, the secret sentence is, BREAK IN CODES CAN BE TRICKY

The above figure clearly forms the sequence is 1, 1, 2, 3, 5, 8... Here, we find the pattern in which each number is in the Fibonacci sequence, obtained by adding together with previous two. Going on like this to find subsequent numbers at the twelfth month, we will get 144 pairs of rabbits. In the other words, twelfth Fibonacci number is 144.

STEP 1: Here , take m = 144 and n = 120 Check whether m = n or m > n or m < n. Here m > n.
STEP 2: Subtract the smaller number from the larger number till m = n.

Now m = n , Hence, we conclude that the HCF of 144 and 120 is 24.

Here, we have to find HCF of 270, 384 and 588
STEP 1: First find the HCF of any two of the given numbers (follow the same step 1, 2 and 3 of the above example). Here, find HCF of (384, 588) first.
STEP 2: The HCF of the first two numbers which is 12 becomes the divisor and the third number 270 becomes the dividend.
STEP 3: Repeat this division process till the remainder becomes zero. The last divisor is the HCF. Here, 6 is the last divisor.
Hence, HCF of 270, 384 and 588 is 6. Therefore, we needs 6 containers so that each of them contains (270 ÷ 6 = 45) 45 ginger chocolates, (384 ÷ 6 = 64) 64 milk chocolates and (588 ÷ 6 = 98) 98 coconut chocolates.

14

The HCF of 455 and 26 is 13