8th Standard Syllabus & Materials
8th Standard
TN 8th Tamil இயல் 3 - கல்வி கரையில - வினைமுற்று Important Questions And Answers Study Material - QB365 Set A
NEW8th Standard
TN 8th Tamil இயல் 2 - ஈடில்லா இயற்கை - மயங்கொலிகள் Important Questions And Answers Study Material - QB365 Set A
NEW8th Standard
TN 8th Tamil இயல் 2 - ஈடில்லா இயற்கை -பட்டமரம் Important Questions And Answers Study Material - QB365 Set A
NEW8th Standard
TN 8th Tamil இயல் 2 - ஈடில்லா இயற்கை - இயற்கையை போற்றுவோம் Important Questions And Answers Study Material - QB365 Set A
NEW8th Standard
TN 8th Tamil இயல் 1 - தமிழ் இன்பம் - ஆழிக்கு இணை Important Questions And Answers Study Material - QB365 Set A
NEW8th Standard
TN 8th Tamil இயல் 2-ஈடில்லா இயற்கை - திருக்குறள் Important Questions And Answers Study Material - QB365 Set A
Published on: 09/12/2019
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Download Tamil Nadu 8th Standard Maths question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Maths Test1.
Use Ceasar Cipher table set + 4 and to try to solve the given secret sentence.
fvieo mr gshiw ger fi xvmgoc
2.
Given that one pair of new born rabbits they produce a new pair each month and from the second month, each new pair can breed themselves. Find how many pairs of rabbits are bred from one pair in a year, and find the relationship between the number of months and the number of pairs of rabbits by tabulation (a pair means (a male and a female)).
3.
Find the correct answer from the four alternatives given
If the word ‘P H O N E’ is coded as ‘S K R Q H’, how will ‘R A D I O’ be coded?
S C G N H
V R G N G
U D G L R
S D H K Q
4.
A group of letters are given. A numerical code has been given to each letter. These letters have to be unscrambled into a meaningful word. Find out the code for the word so formed from the 4 answers given.
L I N C P E
1 2 3 4 5 6
2 3 4 1 5 6
5 6 3 4 2 1
6 1 3 5 2 4
4 2 1 3 5 6
5.
There are four groups of letters in each set. Three of these sets are a like in some way while one is different. Find the one which is different.
H K N Q
I L O R
J M P S
A D G J
6.
There are four groups of letters in each set. Three of these sets are a like in some way while one is different. Find the one which is different.
C R D T
A P B Q
E U F V
G W H X
7.
Common prime factors of 36, 60 and 72 are
2 x 2
2 x 3
3 x 3
3 x 2 x 2
8.
Common prime factors of 30 and 250 are
2 x 5
3 x 5
2 x 3 x 5
5 x 5
9.
The difference between the 18th and 17th Fibonacci number is
233
377
610
987
10.
Every _______ number of the Fibonacci sequence is a multiple of 8
2nd
4th
6th
8th
11.
Every 3rd number of the Fibonacci sequence is a multiple of _______
2
3
5
8
12.
If F(n) is a Fibonacci number and n = 8, which of the following is true?
F(8) = F(9) + F(10)
F(8) = F(7) + F(6)
F(8) = F(10) x F(9)
F(8) = F(7) – F(6)
13.
What is the eleventh Fibonacci number?
55
77
89
144
14.
Do the given repeated division problem in repeated subtraction method and verify the HCF of 255, 204 and 68.
15.
Find the HCF of 144 and 120
16.
There are 270 ginger chocolates, 384 milk chocolates and 588 coconut chocolates. What is the largest number of containers possible so that each container contains the same number of chocolates of each kind?
17.
Using repeated subtracting method find HCF of the following:
1014 and 654
18.
Using repeated subtracting method find HCF of the following:
36 and 80
19.
Using repeated division method find HCF of the following:
184, 230 and 276
20.
Using both repeated division method and repeated subtraction method and find the greatest number that divides 167 and 95, leaving 5 as reminder
21.
Decode the given Pigpen Cipher text and compare your answer to get the Activity 3 result.
The room number in which the treasure took place
\(\sqcap \sqcup \)
II. Place of the treasure:-
.png)
III. The name of the treasure:-
.png)
22.
Frame Additive cipher table (key = 4).
23.
Kalai wants to cut identical squares as big as she can, from a piece of paper measuring 168 mm and by 196 mm. What is the length of the side of the biggest square? (To find HCF using repeated subtraction method)
24.
Using repeated subtracting method find HCF of the following:
42 and 70
25.
Using repeated division method find HCF of the following:
455 and 26
1.
Let us make Ceasar Cipher table first. Here, we have to set to + 4 table. For that, we have to start letter e to set as A, f as B … likewise d as Z. Now, the + 4 Ceasar Cipher table looks like
| Plain Text | a | b | c | d | e | f | g | h | i | j | k | l | m | n | o | p | q | r | s | t | u | v | w | x | y | z |
| Cipher Text | W | X | Y | Z | A | B | C | D | E | F | G | H | I | J | K | L | M | N | O | P | Q | R | S | T | U | V |
The given plain text is
fvieo mr gshiw ger fi xvmgoc
To crack this secret code, follow the steps given below.
Step 1: Using Ceasar Cipher table, let us first match the most repeated letters. This will help us to progress faster.
fvieo mr gshiw ger fi xvmgoc
Step 2: Then, let us find remaining letters to complete the code.
.png)
Thus, the secret sentence is, BREAK IN CODES CAN BE TRICKY
2.
The above figure clearly forms the sequence is 1, 1, 2, 3, 5, 8... Here, we find the pattern in which each number is in the Fibonacci sequence, obtained by adding together with previous two. Going on like this to find subsequent numbers at the twelfth month, we will get 144 pairs of rabbits. In the other words, twelfth Fibonacci number is 144.
| Number of months | 1 | 2 | 3 | 4 | 5 | 6 | 7 | 8 | 9 | 10 | 11 | 12 |
| Number of pairs of rabbits | 1 | 1 | 2 | 3 | 5 | 8 | 13 | 21 | 34 | 55 | 89 | 144 |
3.
(c)
U D G L R
4.
(b)
5 6 3 4 2 1
5.
(d)
A D G J
6.
(a)
C R D T
7.
(b)
2 x 3
8.
(a)
2 x 5
9.
(d)
987
10.
(d)
8th
11.
(a)
2
12.
(b)
F(8) = F(7) + F(6)
13.
(c)
89
14.
STEP 1: Here, let p = 255, q = 204 and r = 68 Check whether p = q or p > q or p < q. Here p > q.
STEP 2: Let us find the HCF of 255 and 204 first. Now, subtract smaller number from larger number till p = q.
| First | 255 – 204 = 51 | Repeat | 204 – 51 = 153 | Repeat | 153 – 51 = 102 |
| Repeat | 102 – 51 = 51 | Repeat | 51 – 51 = 0 |
Now p = q, Hence, we conclude that the HCF of 255 and 204 is 51.
STEP 3: Now repeated same procedure for r – HCF (p, q) Now, subtract smaller number from larger number till HCF (p, q) = r.
| First | 68 – 51 = 17 | Repeat | 51 – 17 = 34 |
| Repeat | 34 – 17 = 17 | Repeat | 17 – 17 = 0 |
Now HCF (p, q) = r, Hence, we conclude that the HCF of 255, 204 and 68 is 17. Comparing both the repeated division and repeated subtraction methods, in finding the HCF, we can conclude that the repeated subtraction, in one way is easier and gives the HCF faster that the repeated division and one would want to easely do subtraction rather than division. Isn’t it?
15.
STEP 1: Here , take m = 144 and n = 120 Check whether m = n or m > n or m < n. Here m > n.
STEP 2: Subtract the smaller number from the larger number till m = n.
| First | 144 – 120 = 24 | Repeat | 120 – 24 = 96 | Repeat | 96 – 24 = 72 |
| Repeat | 72 – 24 = 48 | Repeat | 48 – 24 = 24 | Repeat | 24 – 24 = 0 |
Now m = n , Hence, we conclude that the HCF of 144 and 120 is 24.
16.
Here, we have to find HCF of 270, 384 and 588
STEP 1: First find the HCF of any two of the given numbers (follow the same step 1, 2 and 3 of the above example). Here, find HCF of (384, 588) first.
STEP 2: The HCF of the first two numbers which is 12 becomes the divisor and the third number 270 becomes the dividend.
STEP 3: Repeat this division process till the remainder becomes zero. The last divisor is the HCF. Here, 6 is the last divisor.
Hence, HCF of 270, 384 and 588 is 6. Therefore, we needs 6 containers so that each of them contains (270 ÷ 6 = 45) 45 ginger chocolates, (384 ÷ 6 = 64) 64 milk chocolates and (588 ÷ 6 = 98) 98 coconut chocolates.
17.
6
18.
4
19.
First find the HCF of 18a and 230.
HCF of 184 and 230 is 46
Now we have to find the HCF of 46 and 276.
The HCF of 184, 230 and 276 is 46.
20.
18
21.
I) The room number in which the treasure took place is 28
II) Place of the treasure is C H A I R
III) The name of the treasure G I F T V O U C H E R.
22.
| Plain Text | A | B | C | D | E | F | G | H | I | J | K | L | M | N | O | P | Q | R | S | T | U | V | W | X | Y | Z |
| CipherText | 04 | 05 | 06 | 07 | 08 | 09 | 10 | 11 | 12 | 13 | 14 | 15 | 16 | 17 | 18 | 19 | 20 | 21 | 22 | 23 | 24 | 25 | 00 | 01 | 02 | 03 |
23.
Take m = 196 mm and n = 168 mm,
Here m > n.
196 - 168 = 28
168 - 28 = 140
140 - 28 = 112
112 - 28 = 84
84 - 28 = 56
56 - 28 = 28
28 - 28 = 0
The length of the side of the biggest square is 28 mm.
24.
Let number be m & n
m > n
We do m – n & the result of subtraction becomes new ‘m’.
if m becomes less than n, we do n – m and then assign the result as n.
We should do this till m = n. When m = n then ‘m’ is the HCF.
42 and 70 now m = 70, n = 42 70 – 42 = 28,
now m = 42, n = 28 42 – 28 = 14,
now m = 28, n = 14 28 – 14= 14,
now m = 14, n = 14
We stop here as m = n
∴ HCF of 42 & 70 is 14
25.
The HCF of 455 and 26 is 13
8th Standard Syllabus & Materials
8th Standard
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TN 8th Tamil இயல் 2 - ஈடில்லா இயற்கை - தமிழர் மருத்துவம் ( நேர்காணல்) Important Questions And Answers Study Material - QB365 Set A
Tamilnadu Stateboard 8th Standard Subjects
Tamilnadu Stateboard Standards
