(i) Here, given pie chart shows 100% students of your class, out of which 50% are girls and 50% are boys.
\(\therefore\)  Fraction of the circle representing girls = \(\frac{Percentage\ of\ girls}{Percentage\ of\ all\ students}=\frac{50}{100}=\frac{1}{2}\)
[dividing numerator and denominator by 50]
Fraction of the circle representing boys = \(\frac{Percentage\ of\ boys}{Percentage\ of\ all\ students}=\frac{50}{100}=\frac{1}{2}\)
[dividing numerator and denominator by 50]
(ii) Here, given pie chart shows 100% transport to school.
So, Fraction of the circle representing walk = \(\frac{Percentage\ of\ walk}{Total\ Percentage\ of\ transport}=\frac{40}{100}=\frac{2}{5}\)
 [dividing numerator and denominator by 20]
Fraction of the circle representing bus or car = \(\frac{Percentage\ of\ cars}{Total\ Percentage\ of\ transport}=\frac{40}{100}=\frac{2}{5}\)
[dividing numerator and denominator by 20]
Fraction of the circle representing cycle  = \(\frac{Percentage\ of\ cycle}{Total\ Percentage\ of\ transport}=\frac{20}{100}=\frac{1}{5}\)
[dividing numerator and denominator by 20]

(i) The given histogram represents the heights (in ern) of girls of Class VII.
(ii) Group 140 - 145 contains maximum number of girls i.e. 7.
(iii) Girls having height 145 em and more lie in the intervals 145 - 150,150 - 155 and 155 - 160.
So, number of girls having height of 145 cm and more
= (4 + 2 + 1) = 7
(iv) In group A, girls have height 150 ern and more, so these girls lie in the interval 150 - 155 and 155 - 160. Therefore, number of girls in group A who have height 150 cm and more = 2 + 1= 3
In group B, girls have height 140 cm to less than 150 cm. So, these girls lie in the intervals 140 - 145 and 145 - 150. Therefore, number of girls in group B who have height 140 cm to less than 150 cm = 7 + 4 = 11
In group C, girls have height less than 140 cm. So, these girls lie in the intervals 125 - 130, 130 - 135 and 135 - 140. Therefore, number of girls in group C who have height less than 140 cm = 1+ 2 + 3 = 6.

Here, lowest observation =31
and highest observation = 65
So, we have to take class intervals 30-35, 35-40, 40-45, ... in first column and corresponding frequency i.e. number of students whose weight lie in this class interval, in the second column. Then, frequency distribution table for the above data is given below:

Class Interval   [Weights (in kg)]	Tally marks	Frequency  (Number of students)
30-35	III	3
35-40	IIII	4
40-45	IIII	4
45-50		5
50-55	I	1
55-60	I	1
60-65	I	1
65-70	I	1
Total		20

From the above pictograph, we observe that
(i) 250 cars were produced in the month of July.
(ii) The maximum number of cars were produced in the month of September.

(i) Here, maximum height of the bar is 32 for the interval 4 - 5, so the maximum number of students watching TV is 32 and they watch TV for 4 to 5 h.
(ii) It is clear from the given graph that, students watch TV for 1 - 2, 2 - 3, 3 - 4, 4 - 5, 5 - 6 and 6 - 7 h. So, students who watch TV for less than 4 h lie in the intervals 1 - 2, 2 - 3 and 3 - 4. Also, their corresponding frequencies are 4,8 and 22.
\(\therefore\) Number of students watching TV for less than 4 h
= 4 +8 + 22 =34
(iii) Students who watch TV for more than 5 h lie in the intervals 5 - 6 and 6 - 7. Also, their corresponding frequencies are 8 and 6. 
\(\therefore\) Number of students watching TV for more than 5 h
= 8 + 6 = 14.

Here, comparison between percentage wins in ODI by 8 top cricket teams is given, so to represent the given information, we draw the double bar graph. So, draw two perpendicular axes OX and OY. Take teams on OX and percentage wins in ODI on OY Choose a suitable scale for OX and OY to draw double'bar graph.
Thus, we get the following double bar graph:

If we try to start a scooter, then it may or may not be start, so possible outcomes are may start or may not start.

To display the production of food grains of a state, bar graph is more appropriate.

Frequency table

(i) Rs 200
(ii) 4
(iii) 3.

Class interval are taken along X-axis and frequencies are taken along Y-axis in a histogram.

In an equally likely outcome, each event has same chance of occurring.

In a histogram, each class interval has equal width and there is no gap in between the bars.

6 outcomes are 1, 2, 3, 4, 5 and 6.

Upper limit - Lower limit = 32 - 28 = 4

For large number of observations, groups of equal width i.e. class interval are organised.