6

Tally marks are used to find frequency.

Required probability = \(\frac{1}{3}\)

Required probability = \(\frac{1}{2}\)

There are ten separate slips having 1 to 10 numbers (one number on one slip) out of which one slip can be chosen in 10ways.
So, total  number of outcomes = 10
Here, the numbers greater than 6 are 7, 8, 9 and 10. So, one slip having number greater than 6 can be chosen in 4 ways.
So, favourable outcomes = 4
\(\therefore\) Probability of getting a number greater than 6 = \(\frac{Favourable\ outcomes}{Total\ number\ of\ outcomes}=\frac{4}{10}=\frac{2}{5}\)

There are 52 cards in a deck of playing cards out of which one card can be drawn in 52 ways.
\(\therefore\) Total number of outcomes = 52
There are 4 aces in a deck of 52 cards, out of which one ace can be drawn in 4 ways.
So, favourable number of outcomes = 4
\(\therefore\) Probability of getting an ace = \(\frac{Favourable\ number\ of\ outcomes}{Total\ Number\ of\ outcomes}=\frac{4}{52}=\frac{1}{13}\)

In spinning a wheel, there are five possible outcomes,
[since wheel has five sectors]
So, total outcomes = 5
The pointer can stop on D only in one way.
[since, angle only one sector hasD]
SO, outcomes that make the event = 1
\(\therefore\) Probability of the pointer stopping on D = \(\frac{Possible\ outcomes\ that\ make\ the\ event }{Total\ outcomes}=\frac{1}{5}\)

Here, spinning a wheel have 5 sectors represented by A, A, B, C and 0, so possible outcomes are A, B, C and D. Here, A comes twice on wheel but in outcomes, it will be taken as single.

Total number of outcomes = Total number of green and red sectors = 5 + 3 = 8
Number of outcomes of getting a green sector = 5
Probability of getting a green sector = \(\frac{Number\ of\ outcomes\ of\ getting\ a\ green\ sector}{Total\ number\ of\ outcomes}=\frac{5}{8}\)

No, if second player got a six, it does not mean that third player would not have a chance of getting a six.

Here, number of balls is 5, which are of different colours. If we pull out a ball, then it may be R, W, B, G or Y. So, possible outcomes are R, W, B, G or Y.

To display the production of food grains of a state, bar graph is more appropriate.

Frequency table

Marks in class intervals	Tally marks	Frequency  (Number of students)
40 - 50		5
50 - 60		10
60 - 70	III	4
70 - 80	III	3
80 - 90	II	2

Class interval = 10
In class interval 50 - 60, greatest frequency occurs.

Frequency distribution table