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CBSE 8th Social Science Theme B - Reshaping India's Political Map - New Model Questions Papers Study Material - QB365 Set A
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Published on: 16/09/2019
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Questions + Answers key
Take MCQ Mathematics Test

1.
A coin is tossed three times. Find the number of possible outcomes.
2.
Tally marks are used to finds which of the following:
(i) frequency
(iii) Class size
(ii) Class a intervals
(iv) range
3.
What is the probability that a number selected from the numbers 3, 4, 5, 6, ... , 20 is a multiple of 3?
4.
What is the probability that a number selected from the numbers 3, 4, 5, 6, ... , 20 is an odd number?
5.
Numbers 1 to 10 are written on ten separate slips (one number on one slip), kept in a box and mixed well. One slip is chosen from the box without looking into it. What is the probability of getting a number greater than 6?
6.
Find the probability of getting an ace from a well-shuffled deck of 52 playing cards?
7.
Find the probability of the pointer stopping on D.
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8.
List the outcomes you can see in these experiments.
.png)
Spinning a wheel.
9.
Suppose you spin the wheel.
.png)
Find the probability of getting a green sector.
10.
In throwing a die:
Suppose the second player got a six. Does it mean that the third player would not have a chance of getting a six?
11.
You have a bag with five identical balls of different colours and you are to pull out (draw) a ball without looking at it. List the outcomes you would get in adjoining figure.
.png)
12.
The following data represents the different type of animals and their numbers in a zoo. Prepare a pie chart for the given data.
| Animals | Number of animals |
| Deer | 42 |
| Elephants | 15 |
| Giraffe | 26 |
| Reptiles | 24 |
| Tiger | 13 |
13.
Which form of graph would be appropriate to display the following data.
| Years | 2001 | 2002 | 2003 | 2004 | 2005 | 2006 |
| Production (in lakh tonne) |
60 | 50 | 70 | 55 | 80 | 85 |
14.
The marks scored by 24 students in a test are given below:
64, 47, 58, 44, 53, 72, 51, 41, 57, 89, 53, 84, 57, 78, 71, 56, 62, 54, 42, 68, 53, 68, 49, 56
Complete the following frequency table:
| Marks in class intervals | Tally marks | Frequency (Number of students) |
| 40 - 50 | ||
| 50 - 60 | ||
| 60 - 70 | ||
| 70 - 80 | ||
| 80 - 90 |
What is the class interval in which the greatest frequency occurs?
15.
The earning of 50 shops on a particular day are as follows (the figures have been estimated to the nearest hundreds):
| Earning (in Rs) | 800 | 1300 | 1700 | 2300 | 2800 | 3200 | 3400 |
| Number of shops | 7 | 9 | 2 | 5 | 17 | 7 | 4 |
Prepare a grouped frequency distribution table taking class interval of equal size, one such interval being 1500 - 2000.
1.
6
2.
Tally marks are used to find frequency.
3.
Required probability = \(\frac{1}{3}\)
4.
Required probability = \(\frac{1}{2}\)
5.
There are ten separate slips having 1 to 10 numbers (one number on one slip) out of which one slip can be chosen in 10ways.
So, total number of outcomes = 10
Here, the numbers greater than 6 are 7, 8, 9 and 10. So, one slip having number greater than 6 can be chosen in 4 ways.
So, favourable outcomes = 4
\(\therefore\) Probability of getting a number greater than 6 = \(\frac{Favourable\ outcomes}{Total\ number\ of\ outcomes}=\frac{4}{10}=\frac{2}{5}\)
6.
There are 52 cards in a deck of playing cards out of which one card can be drawn in 52 ways.
\(\therefore\) Total number of outcomes = 52
There are 4 aces in a deck of 52 cards, out of which one ace can be drawn in 4 ways.
So, favourable number of outcomes = 4
\(\therefore\) Probability of getting an ace = \(\frac{Favourable\ number\ of\ outcomes}{Total\ Number\ of\ outcomes}=\frac{4}{52}=\frac{1}{13}\)
7.
In spinning a wheel, there are five possible outcomes,
[since wheel has five sectors]
So, total outcomes = 5
The pointer can stop on D only in one way.
[since, angle only one sector hasD]
SO, outcomes that make the event = 1
\(\therefore\) Probability of the pointer stopping on D = \(\frac{Possible\ outcomes\ that\ make\ the\ event }{Total\ outcomes}=\frac{1}{5}\)
8.
Here, spinning a wheel have 5 sectors represented by A, A, B, C and 0, so possible outcomes are A, B, C and D. Here, A comes twice on wheel but in outcomes, it will be taken as single.
9.
Total number of outcomes = Total number of green and red sectors = 5 + 3 = 8
Number of outcomes of getting a green sector = 5
Probability of getting a green sector = \(\frac{Number\ of\ outcomes\ of\ getting\ a\ green\ sector}{Total\ number\ of\ outcomes}=\frac{5}{8}\)
10.
No, if second player got a six, it does not mean that third player would not have a chance of getting a six.
11.
Here, number of balls is 5, which are of different colours. If we pull out a ball, then it may be R, W, B, G or Y. So, possible outcomes are R, W, B, G or Y.
12.
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13.
To display the production of food grains of a state, bar graph is more appropriate.
14.
Frequency table
| Marks in class intervals | Tally marks | Frequency (Number of students) |
| 40 - 50 | ![]() |
5 |
| 50 - 60 | ![]() |
10 |
| 60 - 70 | III | 4 |
| 70 - 80 | III | 3 |
| 80 - 90 | II | 2 |
Class interval = 10
In class interval 50 - 60, greatest frequency occurs.
15.
Frequency distribution table
| Earnings (in Rs) | Number of shops |
| 500 - 1000 | 7 |
| 1000 - 1500 | 9 |
| 1500 - 2000 | 2 |
| 2000 - 2500 | 5 |
| 2500 - 3000 | 17 |
| 3000 - 3500 | 11 |
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