8th Standard Syllabus & Materials
8th Standard
Tamilnadu 8th Standard роХрогро┐родроорпН роЗропро▒рпНроХрогро┐родроорпН Important Questions And Answers Study Material - QB365
NEW8th Standard
Tamilnadu 8th Standard роХрогро┐родроорпН роОрогрпНроХро│рпН Important Questions And Answers Study Material - QB365 Set B
NEW8th Standard
Tamilnadu 8th Standard роХрогро┐родроорпН роОрогрпНроХро│рпН Important Questions And Answers Study Material - QB365 Set A
NEW8th Standard
Tamilnadu 8th Standard Social Science рокрпКро░рпБро│ро┐ропро▓рпН - рокрпКродрпБ рооро▒рпНро▒рпБроорпН родройро┐ропро╛ро░рпН родрпБро▒рпИроХро│рпН Important Questions And Answers Study Material - QB365
NEW8th Standard
Tamilnadu 8th Standard Social Science роХрпБроЯро┐роорпИропро┐ропро▓рпН - роирпАродро┐родрпНродрпБро▒рпИ Important Questions And Answers Study Material - QB365
NEW8th Standard
Tamilnadu 8th Standard Social Science роХрпБроЯро┐роорпИропро┐ропро▓рпН - рокро╛родрпБроХро╛рокрпНрокрпБ рооро▒рпНро▒рпБроорпН ро╡рпЖро│ро┐ропрпБро▒ро╡рпБроХрпН роХрпКро│рпНроХрпИ Important Questions And Answers Study Material - QB365

Published on: 15/06/2021
QB365 provides detailed and simple solution for every book back questions in class 8 Maths subject.It will helps to get more idea about question pattern in every book back questions with solution.
Download Tamil Nadu 8th Standard Maths question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Maths Test1.
The area of a square field is 3136 m2. Find its perimeter
2.
Simplify:\(\sqrt { 12 } \times \sqrt { 3 } \)
3.
Find the value of \(\sqrt { 42.25 } \)
4.
Combine the scientific notations:(3.7 x 10-5)(2 x 10-3)
5.
Simplify: (−2)5 x (−2)−3
1.
Given that the area of the square field = 3136 m2.
роГ The side of square field =\(\\ \sqrt { 3136 } \ m=\) 56 m
роГ The perimeter of the square field = 4 x side
= 4 x 56
= 224 m
2.
Remembering the rule,\(\sqrt { a } \times \sqrt { b } =\sqrt { a } \times \sqrt { b } \)
\(\sqrt { 12 } \times \sqrt { 3 } =\sqrt { 12\times 3 } =\sqrt { 36 } =\sqrt { { 6 }^{ 2 } } =6\)
3.
We can write this as \(\sqrt { 42.25 } =\sqrt { \cfrac { 4225 }{ 100 } } =\cfrac { \sqrt { 4225 } }{ \sqrt { 100 } } \)
Now, it is easy to compute the square root of the whole number 4225, without any botheration of decimal symbol.
\(\sqrt { 4225 } =65\) and so, we now get \(\sqrt { 42.25 } =\sqrt { \cfrac { 42.25 }{ 100 } } =\cfrac { \sqrt { 4225 } }{ \sqrt { 100 } } =\cfrac { 65 }{ 10 } \)
Th is is another way of tackling problems of square root of decimal numbers instead of long division method.
4.
(3.7 x 10-5)(2 x 10-3) = 7.4 x 10-8
5.
(- 2)5´(- 2)-3 = (-2) 5 - 3 = ( - 2) 2 = - 2 x - 2 = 4 .
8th Standard Syllabus & Materials
8th Standard
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NEW8th Standard
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NEW8th Standard
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NEW8th Standard
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Tamilnadu Stateboard 8th Standard Subjects
Tamilnadu Stateboard Standards