8th Standard Syllabus & Materials
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TN 8th Tamil இயல் 2-ஈடில்லா இயற்கை - திருக்குறள் Important Questions And Answers Study Material - QB365 Set A

Published on: 15/06/2021
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Questions + Answers key
Take MCQ Maths Test1.
X, Y and Z can do a piece of job in 4, 6 and 10 days respectively. If X,Y, and Z work together to complete, then find their separate shares if they will be paid Rs 3100 for completing the job.
2.
A and B can do a piece of work in 12 days and 9 days respectively. They work on alternate days starting with A on the first day. In how many days will the work be completed?
3.
A works 3 times as fast as B and is able to complete a task in 24 days less than the days taken by B. Find the time in which they can complete the work together.
4.
A and B together can do a piece of work in 16 days and A alone can do it in 48 days. How long will B done take to complete the work?
5.
If a company pays Rs. 6 lakh for 15 workers for 20 days, what would it pay for 5 workers for 12 days?
1.
Since they all work for the same number of days, the ratio in which they share the money is equal to the ratio of their work done per day.
That is,\(\cfrac { 1 }{ 4 } :\cfrac { 1 }{ 6 } :\cfrac { 1 }{ 10 } =\cfrac { 15 }{ 60 } :\cfrac { 10 }{ 60 } :\cfrac { 6 }{ 60 } =15:10:6\)
Here, the total parts = 15 + 10 + 6 = 31
Hence, A’ s share =\(\cfrac { 15 }{ 31 } \times 3100=Rs.1500\), B; share = \(\cfrac { 10 }{ 31 } \times 3100=Rs.1000\) and
C’ s share is Rs.3100 - (Rs.1500 + Rs.1000) = Rs.600
2.
Since they work on alternate days, let us consider a period of two days.
In the period of 2 days, work done by A and B = \(\cfrac { 1 }{ 12 } +\cfrac { 1 }{ 9 } =\cfrac { 7 }{ 36 } \)
If we consider 5 such time periods for the fraction \(\cfrac { 7 }{ 36 } \) (we consider 5 periods because
7 goes 5 times completely in 36),
work done by A and B in 5\(\times\)2(=10)days = \(5\times \cfrac { 7 }{ 36 } =\cfrac { 35 }{ 36 } \)
Therefore, the remaining work = \(1-\cfrac { 35 }{ 36 } =\cfrac { 1 }{ 36 } \)
This is done by A (why?) in \(\cfrac { 1 }{ 36 } \times 12=\cfrac { 1 }{ 3 } daysB\)
So, the total time taken = \(10days+\cfrac { 1 }{ 3 } days=10\cfrac { 1 }{ 3 } days\)
3.
If B does the work in 3 days, then A will do it in 1 day. That is, the difference is 2 days.
Here, given that the difference between A and B in completing the work is 24 days. Therefore,
A will take \(\cfrac { 24 }{ 2 } =12\) days and B will take 3 x 12 = 36 days to complete the work separately.
Hence, the time taken by A and B together to complete the work =\(\cfrac { ab }{ a+b } days\)
= \(\cfrac { 12\times 36 }{ 12+36 } =\cfrac { 12\times 36 }{ 48 } =9days\)
4.
(A+ B) ’s 1 day’s work = \(\cfrac { 1 }{ 16 } \)
A’s 1 day’s work = \(\cfrac { 1 }{ 48 } \)
ஃ B’s 1 day’s work = \(\cfrac { 1 }{ 16 } -\cfrac { 1 }{ 48 } \)
= \(\cfrac { 3-1 }{ 48 } =\cfrac { 2 }{ 48 } =\cfrac { 1 }{ 24 } \)
ஃB alone can complete the work in 24 days
5.
Proportion Method:
| Workers | Payment (Work) | Days |
| \({ D }_{ 5 }^{ 15 }\) | \({ D }_{ x }^{ 6 }{ D }\) | \(_{ 12 }^{ 20 }{ D }\) |
Here, the unknown is the payment (x). It is to be compared with the workers and the days.
Step 1:
Here, less days means less payment. So, it is a direct proportion.
ஃ The proportion is 20 : 12 :: 6 : x ⟶1
Step 2:
Also, less workers means less payment. So, it is a direct proportion again.
ஃ The proportion is 15 : 5 :: 6 : x ⟶2
Step 3:
Combining 1 and 2
\(\begin{matrix} 20:12 \\ 15:5 \end{matrix}\} ::6:x\)
We know that the product of the extremes = the product of the means
So,20 x 15 = 12 x 6 x 5 ⇒ \(x=\cfrac { 12\times 6\times 5 }{ 20\times 15 } =Rs.1.2lakh\)
Multiplicative Factor Method
| Workers | Payment (Work) | Days |
| \({ D }_{ 5 }^{ 15 }\) | \({ D }_{ x }^{ 6 }{ D }\) | \(_{ 12 }^{ 20 }{ D }\) |
Here, the unknown is the payment (x). It is to be compared with the workers and the days.
Step 1:
Here, less days means less payment. So, it is a direct proportion.
ஃ The multiplying factor is \(\cfrac { 12 }{ 20 } \) (take the reciprocal).
Step 2:
Also, less workers means less payment. So, it is a direct proportion again.
ஃ The multiplying factor is \(\cfrac { 5 }{ 15 } \) (take the reciprocal)
Step 3:
\(\therefore x=6\times \cfrac { 12 }{ 20 } \times \cfrac { 5 }{ 15 } \)
x = Rs.1.2 lakh
Formula Method
Here, P1= 15D, D1= 20 and W1= 6
P2 = 5, D2 = 12 and W2 = x
Using the formula,\(\cfrac { { P }_{ 1 }\times { D }_{ 1 } }{ { W }_{ 1 } } =\cfrac { { P }_{ 2 }\times { D }_{ 2 } }{ { W }_{ 2 } } \)
We have,\(\cfrac { 15\times 20 }{ 6 } =\cfrac { 5\times 12 }{ x } \)
\(\Rightarrow x=\cfrac { 5\times 12\times 6 }{ 15\times 20 } =Rs.12lakh\)
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Tamilnadu Stateboard 8th Standard Subjects
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