8th Standard Syllabus & Materials
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TN 8th Tamil இயல் 2 - ஈடில்லா இயற்கை - இயற்கையை போற்றுவோம் Important Questions And Answers Study Material - QB365 Set A
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Published on: 02/09/2019
Algebra
Download Tamil Nadu 8th Standard Maths question papers, model tests, one-mark questions, important questions, and public exam papers in PDF format. Free study materials and answer keys for TN State Board students.
Questions + Answers key
Take MCQ Maths Test1.
Expand: (x + 3)(x + 5)(x + 2)
2.
Expand y2 - 16 using a2 − b2 identity
3.
Multiply (3xy +7) by ( −4y )
4.
Find the product of (m2 - n)(5m2n2 - n2)
5.
Find the product of the terms
3x2y, −3xy3, x2y2
6.
Multiply a monomial by a monomial
6x,4
7.
If the area of a rectangular land is(a2 - b2 )− sq.units whose breadth is (a - b) then, its length is__________
a - b
a + b
a2- b
(a + b)2
8.
If the area of a square is 36x4y2t hen, its side is______
6x4y2
8x2y2
6x2y2
6x2y
9.
The missing terms in the product - 3m3n x 9(_) = ___________m4n3 are
mn2, 27
m2n, 27
m2n2, -27
mn2, -27
10.
The product of 7p3 and (2p2)2 is
14p12
28P7
9p7
11p12
11.
Factorise:(2x + 5)(x-y) + (4y)(x - y)
12.
Expand the following
(62-x2) =_______
13.
Expand the following
(3 - a)2 = ________
14.
\(\cfrac { { 42a }^{ 4 }{ b }^{ 5 }\left( \_ \right) }{ { 6a }^{ 4 }{ b }^{ 2 } } =\left( \_ \right) { b }^{ 3 }{ c }^{ 2 }\)
15.
\(\frac{\left.l^{4} m^{5} n^{(}-\right)}{\left.2 l m^{(-}\right) n^{6}}=\frac{l^{3} m^{2} n}{(-)}\)
16.
7ab3 ÷ 14ab = 2b2
17.
8x3y ÷ 4x2 = 2xy
1.
Comparing this with (x + a)(x + b)(x + c), we get x = x, a = 3 ,b = 5 , c = 2
(x + a)(x + b)(x + c) = x3 + (a + b + c)x2 + (ab + bc + ca)x + abc
(x + 3)(x + 5)(x + 2) = (x)3 + (3 + 5 + 2)(x)2 + (3 × 5 + 5 × 2 + 2 × 3)x + (3)(5)(2)
= x3 + 10x2+(15 +10 + 6)x + 30
(x + 3)(x + 5)(x + 2) = x3 + 10x2 + 31x + 30
2.
y2 - 16 can be written as y2 - 42
Comparing it with a2 - b2,we get ay, b = 4,
Now a2-b2 = (a + b)(a - b)
y2-42 = (y + 4)(y - 4)
y2-16 = (y + 4)(y - 4)
3.
Now, −4y×(3xy + 7) =–4y(3xy) +(–4y)(7)
=(−4×3)x×y×y+(−4×7)y
= −12xy2 − 28y
4.
(m2 - n)(5m2n2-n2) = 5m4n2 - m2n2 - 5m2n3 + n3
5.
3x2y −3xy3, x2y2 = -9x5y6
6.
6x \(\times\) 4= (6 \(\times\) 4)(x) = 24x
7.
(b)
a + b
8.
(d)
6x2y
9.
(d)
mn2, -27
10.
(b)
28P7
11.
We have (2x + 5)(x - y) + (4y)(x-y)
Taking out the common binomial factor (x-y)
We get,(x - y)(2x + 5 + 4y)
12.
( )
(62-x2) = (6 + x)(6 - x)
13.
( )
(3 - a)2 = 32 - 2(3) (a) + a2 = 9 - 6a + a2
14.
( )
\(\cfrac { { 42a }^{ 4 }{ b }^{ 5 }\left( c^2 \right) }{ { 6a }^{ 4 }{ b }^{ 2 } } =\left( 7 \right) { b }^{ 3 }{ c }^{ 2 }\)
15.
( )
\(\cfrac { { I }^{ 4 }{ m }^{ 5 }{ n }^{ (7) } }{ 2lm^{ (3) }{ n }^{ 6 } } =\cfrac { { l }^{ 3 }{ m }^{ 2 }n }{ 2 } \)
16.
(b)
17.
(a)
8th Standard Syllabus & Materials
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Tamilnadu Stateboard 8th Standard Subjects
Tamilnadu Stateboard Standards
