Assuming that the question Q₁ is answered True, questions Q₂ and Q₃ can be answered as TT, TF, FT, and FF in 4 ways.
Similarly, assuming that the question Q₂ is answered False, Q₂ and Q₃ can also be answered as TT, TF, FT, and FF in 4 ways.
Thus, as each question has only two options (True or False), the number of ways of answering these 3 questions in a slip test is 2 x 2 x 2 = 8 possible ways

There are 6 different outcomes, namely 1, 2, 3, 4, 5 and 6. All the 6 outcomes cannot occur simultaneously. Hence, there are 6 different possible outcomes in rolling a die.

There are 2 different outcomes in tossing a coin namely a Head and a Tail. Both events cannot occur simultaneously.

Shanthi wears a chudithar in 5 different ways.
She also wears a frock in 4 different ways.
So she wears either a chudithar or a frock in 5 + 4 different ways.
That is 9 different ways.

more possible ways

The student has 2 school bags and 3 water bottles.

Therefore he can carry both a school bag and a water bottle in 6 (2 x 3) different possible ways.

The teacher is going to select one student from class VI out of 10 students in 10 ways from class VII out of 15 students in 15 ways and from class VIII out of 20 students in 20 ways.
ஃ Number of ways 3 students can be selected = 10 + 15 + 20 = 45 ways

This is one of the solutions. Try for more

This is one of the solutions. Try for more solutions