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Published on: 31/10/2019
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Questions + Answers key
Take MCQ Mathematics Test
1.
The area of a square is numerically less than six times its side. List some squares in which this happens.
2.
A shirt is marked at Rs 1250 and sold for Rs 1125. What is the discount and discount per cent?
3.
Solve: x2 + 10x + 21 = x2 + 4x + 81
4.
Complete the following crossword puzzle using the given direction.
Direction:
Across:
(1) The product of number by itself two times, is called its _______
(2) If three numbers a, band c are such that a2 + b2= c2 then they are called _____ Triplets.
(3) A number is a when it is a product of the same two numbers.
Down: (4) The numbers 2n, n2-1 and n2 + 1 where n is a natural number show Pythagorean______.
(5) Finding is the inverse operation of squaring a number.
(6) A number which divides a _______ given number exactly is called a or divisor of that number.
5.
A closed cylindrical tank of radius 7 cm and height 5 m is made from a sheet of metal. If the breadth of the rectangular sheet is 10 m, then find the length of the sheet.
6.
By what number should (-5)-1 be multiplied, so that the product becomes 9?
7.
Express the product of 1.3x104 and 3.4x10-2 in the standard form.
8.
Represent the rational number \({-7\over3}\)on the number line
9.
Represent the following rational numbers on the number line \(5\over2\)
10.
Find the value of \({x\over y }+xy\) , using appropriate property and name it \(x={1\over3},y={2\over 5}\)
1.
Let the side of the square be a units.
Then, area of the square = a2 square units
According to the question,
a2 < 6a
⇒ a2 - 6a < 0
⇒ a (a-6)<0
⇒ a - 6<0 |∴ a>0
⇒ a < 6
⇒ a = 1,2,3,4,5
Hence, the sides of the square may be 1, 2, 3, 4, or 5 units.
2.
125;10%
3.
x = 10
4.
1.SQUARE
2.PYTHAGOREAN
3.PERFECT SQUARE
4.TRIPLET
5.SQUARE ROOT
6.FACTOR
5.
Here, Radius (r) = 7 cm
Height (h) = 5 cm
Since, total surface area of the closed cylinder = 2\(\pi\)r (r + h)
\(\therefore\) Total surface area of the cylindrical tank
\(=2\times\frac{22}{7}\times(7)\times(7+5)m^2\)
\(2\times22\times12 m^2=528\ m^2\)
Let length of the sheet required be'l' m
\(\therefore\) Area of the rectangular sheet = I x 10 m2
\(\Rightarrow l\times 10=528\Rightarrow l=\frac{528}{10}m=52.8 m\)
Thus, the required length of the sheet = 52.8 m.
6.
-45
7.
4.42 X102
8.
9.
10.
\({29\over30}\)
8th Standard CBSE Syllabus & Materials
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CBSE 8th Standard CBSE Subjects
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