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Published on: 07/09/2019
Comparing Quantities
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Questions + Answers key
Take MCQ Mathematics Test
1.
Find the rate of discount being given on a laptop, whose selling price is Rs 30000 after deducting a discount of Rs 4050 on its marked price.
2.
Find the ratio of the following.
(a) Speed of a cycle 15 km/h to the speed of scooter 30km/h
(b) 5m to 10 km
(c) 50 paise to Rs.5
3.
If marked price of an article is Rs 1200 and the discount is 12%, then find the selling price of the article.
4.
If \(\frac{7}{3}\) % of a number is 147, then find the number.
5.
If Rs 1600 lent at a CI of 5% per annum, then compounded half-yearly for 1 yr will amount to ...
6.
Find the discount in per cent, when MP = Rs 900and SP = Rs 873
7.
After spending 20% of the salary, Aakash has Rs 20000 in his hand. Find the amount of his salary.
8.
If simple interest for 5 yr be equal to 40% of the principal, then in how much time it will be equal to the principal?
9.
A machinery worth Rs10500 depreciated by 5%. Find its value after one year.
10.
Arun bought a pair of skates at a sale, where the discount given was 20%. It the amount he pays is Rs 1600, find the marked price.
11.
Find the buying price of the following, when 5% sale tax is added on the purchase of two bars of soap at Rs 35 each.
12.
Your bill in a shop is Rs 577.80. TIy estimating 15% discount of the same bill amount.
13.
Asurn is taken for 2 yr at 16% per annum, If interest is compounded after every three months, the number of times for which interest is charged in 2 yr is
8
4
6
9
14.
Radhika bought a car for Rs 250000. Next year, its price decreased by 10% and further next year it decreased by 12%. In the two years, overall decrease per cent in the price of the car is
3.2%
22%
20.8%
8%
15.
The buying price of 5 kg guava, at the rate Rs 20 per kg with 5% sales tax on the purchase, is
Rs 22
Rs 23
Rs 24
None of these
16.
Suppose a certain sum doubles in 2 yr at r % rateof simple interest per annum or at R% rate of interest per annum compounded annually,we have
r
R < r
R=r
Cannot be termined
17.
By selling 50 items, a shopkeeper lost the amount equal to the selling price of 10 items. His loss per cent is
\(\frac{30}{7}\)%
\(\frac{40}{3}\)%
\(\frac{25}{3}\)%
\(\frac{50}{3}\)%
18.
The compound interest on Rs 50000 at4% per annum for 2 yr compounded annually is Rs 4080.
19.
If for the principal P, rate R% and time T,the simple interest is SI and compound interest is CI. Then, CI > SI.
20.
The sale price is regular price minus the discount.
21.
40% of [100 - 20% of 300] is equal to 64.
22.
The cost price of 10 tables is equal to the sale price of 5 tables. Then, profit per cent is 100%.
23.
y is the interest calculated on the previous year's amount. Here, y refers to
24.
The amount of money that is earning interest or that you are borrowing is called the
25.
The amount due is equal to the principal plus the
26.
The discount per cent is calculated on the x of an article. Here, x refers to.
27.
The time period after which the interest /s added each time to form a new principal is called the
1.
13.5%
2.
(a) Given, speed of a cycle = 15 km/h
and speed of scooter = 30 km/h
∴ Ratio of the speed of a cycle to the speed of the
scooter = \(\frac{15 km/h}{30 km/h}=\frac{15}{30}=\frac{1}{2}\)or 1:2
(b) We know that, 1 km = 1000 m
∴ Ratto of 5m to 10 km = \(\frac{5m}{10 km}=\frac{5 m}{10\times 1000m}\)|
\(=\frac{5}{10\times1000}=\frac{1}{2000}\)
or 1 : 2000
(c) We know that, Rs 1 = 100 paise
∴ Ratio of 50 paise to Rs 5 = \(\frac{50 paise}{Rs 5}\)
\(\frac{50 paise}{5\times 100 paise}=\frac{50}{5\times100}\)
\(=\frac{5}{5\times10}=\frac{1}{10}\) or 1:10
3.
Rs 1056
4.
∵ \(\frac{7}{3}\)% of the number = 147
⇒ \(\frac{7}{300}\)ｘNumber = 147
∴ Number = 147ｘ\(\frac{300}{7}\)= 6300
5.
Rs 1681
6.
3%
7.
Rs 25000
8.
12 yr 6 months
9.
Here, principal (P) = Rs 10500,
Reduction (R) = - 5% and time (n) = 1yr [depreciation means reduction]
∴ Reduced the value after one year = P\((1-\frac{R}{100})^{n}\)
= 10500\((1-\frac{5}{100})^{1}\)
= 10500\((\frac{100-5}{100})\)
= 10500ｘ\(\frac{95}{100}\)
= 105ｘ95
= Rs 9975
Hence, the value of a machinery after one year will be Rs 9975.
10.
Let the marked price of a pair of skates be Rs 100,
Discount per cent on a pair of skates = 20%
∴ Discount amount on a pair of skates
= 20% of marked price
= 20% oH 100 = Rs \((\frac{20}{100}\times100)\) = Rs 20
∴ Selling price of a pair of skates = Rs 100 - Rs 20
= Rs (100 - 20) = Rs 80
If selling price is Rs 80, then marked price = Rs 100
If selling price is Rs 1, then marked price =Rs \(\frac{100}{80}\)
If selling price is Rs 1600, then marked price
=Rs \((\frac{100}{80}\times 1600)\) = Rs(100ｘ20) = Rs 2000
Hence, the marked price of a pair of skates is Rs 2000.
11.
Given, cost of one bar of soap = Rs 35
∴ Cost of two bars of soap = Rs (35 x 2) =Rs 70
Also, sale tax = 5%
Now, sale tax charged = 5% of cost of two bars of soap
= 5% of Rs 70
= Rs \((\frac{5}{100}\times 70)=\) Rs \(\frac{350}{100}\) = Rs 3.50
∴ Buyingprice of two bars of soap = Cost of two bars of soap + Sale tax
= Rs (70 + 350) = Rs 73.50
Hence, the buying price of two bars of soap is Rs 73.50.
12.
(i) Round off the bill to nearest tens of Rs 577.80 i. e. Rs 580.
(ii) To find 15% of this, we get 10% of the bill i.e. \(\frac{10}{100}\times 580\)= Rs 58
(iii) Take half of this i.e .\(\frac{1}{2}\times 58=29\)
(iv) Add the amounts of (ii) and (iii), we get 58 + 29 = Rs 87
Thus, our bill amount is reduced by Rs 87 and we have to pay Rs 493 or Rs 495 approximately.
13.
(a)
8
14.
(c)
20.8%
15.
(d)
None of these
16.
(b)
R < r
17.
(d)
\(\frac{50}{3}\)%
18.
(a)
19.
(a)
20.
(a)
21.
(b)
22.
(b)
23.
( )
Compound interest
24.
( )
Principal
25.
( )
Accrued interest
26.
( )
Marked price
27.
( )
Conversion period
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CBSE 8th Standard CBSE Subjects
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