Amount of milk consumed in the morning = \(2\frac { 1 }{ 2 } \)litres
Amount of milk consumed in the evening = \(1\frac { 1 }{ 2 } \)  litres
\(\therefore\) Total amount of milk consumed 
= \(2\frac { 1 }{ 2 } +1\frac { 1 }{ 2 } =\frac { 2\times 2+1 }{ 2 } +\frac { 1\times 2+1 }{ 2 } \)
= \(\frac { 4+1 }{ 2 } +\frac { 2+1 }{ 2 } \)
= \(\frac { 5 }{ 2 } +\frac { 3 }{ 2 } =\frac { 5+3 }{ 2 } =\frac { 8 }{ 2 } \)= 4
Hence she uses 4 litres of milk in a day in the stall.

A cube is a cuboid whose edges are all of equal length.
It has 6 faces.
Each face has 4 Each face
Each face 4 has vertices.

It is a polygon as it is a simple closed figure made up entirely of line segments.

1. Number of people in U.P. state.
2. Number of copies of Ram Charit Manas published each year.
3. Number of grains in a sack full of wheat.
4. Number of railway tickets sold in 2002-2003 in U.P.
5. Number of saving account holders in nationalised banks in U.P.

Factors of 6 = 1,2,3,6
Factors of 10 =1, 2, 5,10
Common factors of 6 and 10 = 1,2

First, we have to find out the LCM of 18, 24, and 32.

\(\therefore\) LCM = 2 x 2 x 2 x 2 x 2 x 3 x 3
= 288
We know that, the smallest 4-digit number is 1000.
On dividing 1000 by 288, we get 136 as remainder.

\(\therefore\) Required smallest 4-digit number which is exactly divisible by 18, 24 and 32 = (Smallest 4-digit number + Divisor - Remainder)
= 1000 + 288 - 136 = 1152

HCF of 12, 45 and 75 = 3

Let \(\frac { a }{ b } =\frac { 1 }{ 8 } \) and \(\frac { c }{ b } =\frac { 1 }{ 8 } \) ,then sum = \(\frac { a+c }{ b } =\frac { 1+1 }{ 8 } =\frac { 2 }{ 8 } =\frac { 1 }{ 4 } \) ; Hence the sum of\(\frac { 1 }{ 8 } \) and\(\frac { 1 }{ 8 } \) is \(\frac { 2 }{ 8 } \)

\(\because\) 60 =30 x 2
30 = 10 x 3 and 10 = 5 x 2

\(\therefore\)Hence, missing numbers are 2, 3, 5 and 2.

Information in raw or unorganised form (such as alphabets. numbers or symbols) that refer to, or represent conditions, ideas or objects.

Given, figure is covered by 4 full squares and 2 half squares
∴  Area = \(\left( 4\times 1+2\times \frac { 1 }{ 2 } \right) sq\quad units\)
= (4 + 1)sq units = 5 sq units

Commutativity of addition

Here, numerators of all fractions are same.
Descending order of denominators
= \(50 > 23 > 17 > 12 > 9 > 7 > 5\)
∴ Ascending order of fractions =\(\frac { 1 }{ 50 } ,\frac { 1 }{ 23 } ,\frac { 1 }{ 17 } ,\frac { 1 }{ 12 } ,\frac { 1 }{ 9 } ,\frac { 1 }{ 7 } ,\frac { 1 }{ 5 } \)\(\begin{bmatrix} \because {1\over 50}\ has\ larger\ denominator, \\ so\ it\ is\ smaller\ fraction \end{bmatrix}\)
and descending order of fractions = \({1\over 5},{1\over 7},\frac { 1 }{ 9 } ,\frac { 1 }{ 12 } ,\frac { 1 }{ 17 } ,\frac { 1 }{ 23 } ,\frac { 1 }{ 50 } \)

x=5 cm

Zero

6

We know that, in a rhombus, all four sides are equal and opposite sides are parallel. If its all angles are right angles, then it becomes a square. So, a square can be thought of as a special rhombus.

Multiples of 6 = 6, 12,18, 24, 30, 36, 42, 48, 54, 60, 66,72, ...
Multiples of 8 = 8, 16, 24, 32, 40, 48, 56, 64, 72, 80,88,96, ...
Hence, first three common multiples are 24, 48 and 72.

By observing the given triangles in two different ways, name of each triangle is given below:
In the given triangle, all the sides are different, so it is a scalene triangle and one angle is right angle. So, it is a right angled triangle also.

Vertex of a circle cannot be possible i.e. circle has no vertex.

PQ is perpendicular bisector of AB.

The three angles in the above figure are \(\angle BAC,\angle ABC,\ and\ \angle ACB\).

All the line segments are \(\bar {PQ},\bar {PR},\bar {PS},\bar {QR},\bar {QS}\ and \bar {RS}.\)

Expanded form of given numbers as
76496 = 7 \(\times\) 10000 + 6 \(\times\) 1000 + 4 \(\times\) 100 + 9 \(\times\) 10 + 6

-11

Obtuse angle

(-7)+(+8)=(-7)+(+7)+(+1)   [∵ 7+1=8]
=0+(+1)=+1  [∵ (-7)+(+7)=0]

∵ 28,292 ⟶ 28,000[rounding off to nearest thousands]
21,496 ⟶ 21,000 [rounding off to nearest thousands]
∴ Estimated difference = 28000 - 21000 = 7000

The measurement of L\(\angle P\) = 30°
The measurement of \(\angle Q\) = 90°,
Hence, \(\angle Q > \angle P.\)

12159 is not divisible by 4.
12159 is not divisible by 8.

We have, 0.06=0 tenths + 6 hundreds = \(0+\frac { 6 }{ 100 } =\frac { 6 }{ 100 } =\frac { 3 }{ 50 } \)

Here, -3 and -8 both are on the left of zero, but -3 is near to the zero in comparison of -8. So, -3 is to the right of -8.

Opposite of 30 km North is 30 Km South.

T and R

West

Prime numbers between 1 and 10 are 2,3,5 and 7.
Therefore, the greatest prime number between 1 and 10 is 7.

We know that, 1 kg = 1000 g = (1000 X 1000) mg [∵ 1 g = 1000 mg]
= 1000000 mg
∴ 1000000 milligrams make one kilogram

Numerator =5 and denominator =9
∴ Required fraction = \(\frac { 5 }{ 9 } \)

No, the commutative property does not hold under subtraction of whole numbers.

100 - 1= 99

We have, 15 x 68 = 15 x (60 + 8) = 15 x 60 + 15 x 8 [by distributive property of multiplication over addition]
                        = 900 + 120 = 1020.

Here, fraction \(\frac { 1 }{ 3 } \) shows that out of 3 equal parts, 1 part is shaded. So, the required figure is shown alongside.

To get the multiples of any number, we multiply that number with natural numbers.
So, first three multiples of 5 are 5 x 1,5 x 2,5 x 3 = 5, 10, 15.

When we measure the length of a line segment by ruler, there may be some errors due to its thickness and angular viewing. These errors can be removed by measuring a line segment with the help of a divider. Hence, the use of a divider is better than a ruler.

We can give the name to these given points in different ways as follows:

Here, the given figure is divided into 4 equal parts and 3 parts out of 4 parts are shaded.
∴ The required fraction = \(\frac { 3 }{ 4 } \)

The predecessor of given numbers are as follows:

Both 67454 and 78465 are five-digit numbers. So, we compare them by comparing the digits at ten thousand places. Since, 7> 6. So, 78465> 67454.